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RegionPlot of annulus gives a mesh
The Next CEO of Stack OverflowHow to express ticks in scientific form?How to combine ParametricPlot and RegionPlot?How should I debug a failed Manipulate of RegionPlot?RegionPlot, RegionPlot3D and differing embedding dimensionsPlotting issue — possible bug?An issue evaluating RegionInteresectCannot avoid redundant function evaluations in RegionPlotFrame within a Frame for all plots? Why?Exporting ParametricPlot to .pdfIssue related to BoundaryDiscretizeGraphics
1
$begingroup$
So I tried plotting an annulus in two ways:
RegionPlot[Annulus[0,0,a,b]]
Graphics[Annulus[0,0,a,b]]
Why does RegionPlot give a fractal looking thing? (see below for when a=1; b=5;)
*note, I used wolfram programing lab.
graphics regions
edited 5 hours ago
MarcoB
38.1k556114
asked 5 hours ago
Ion SmeIon Sme
876
$endgroup$
|
show 4 more comments
1
$begingroup$
So I tried plotting an annulus in two ways:
RegionPlot[Annulus[0,0,a,b]]
Graphics[Annulus[0,0,a,b]]
Why does RegionPlot give a fractal looking thing? (see below for when a=1; b=5;)
*note, I used wolfram programing lab.
graphics regions
edited 5 hours ago
MarcoB
38.1k556114
asked 5 hours ago
Ion SmeIon Sme
876
$endgroup$
$begingroup$
What are $a$ and $b$ here?
$endgroup$
– mjw
5 hours ago
$begingroup$
Try a=1; b=5; But really any values give something weird
$endgroup$
– Ion Sme
5 hours ago
4
$begingroup$
Because it discretized the region in order to plot it, and it is showing the underlying triangulation mesh.
$endgroup$
– MarcoB
5 hours ago
1
$begingroup$
@IonSme I guess they just use different defaults for plotting; the Graphics result is "normal-looking" though.
$endgroup$
– MarcoB
5 hours ago
2
$begingroup$
There are some subtle differences going on how Mma showsRegions andRegionPlotGraphics. AlsoRegions can be defined analytically viaImplicitRegionorParametricRegionor as 'flat'MeshRegions.DiscretizeRegionconverts every type to aMeshRegionand some functions likeRegionPlotmight use something similar toDiscretizeRegionunder the hood to make plotting easier, whose discretization it for some reason decides to show. Like others wrote you can useImplicitRegionto get a different (not discretized) look in your case.
$endgroup$
– Thies Heidecke
4 hours ago
|
show 4 more comments
1
1
1
$begingroup$
So I tried plotting an annulus in two ways:
RegionPlot[Annulus[0,0,a,b]]
Graphics[Annulus[0,0,a,b]]
Why does RegionPlot give a fractal looking thing? (see below for when a=1; b=5;)
*note, I used wolfram programing lab.
graphics regions
edited 5 hours ago
MarcoB
38.1k556114
asked 5 hours ago
Ion SmeIon Sme
876
$endgroup$
So I tried plotting an annulus in two ways:
RegionPlot[Annulus[0,0,a,b]]
Graphics[Annulus[0,0,a,b]]
Why does RegionPlot give a fractal looking thing? (see below for when a=1; b=5;)
*note, I used wolfram programing lab.
graphics regions
graphics regions
edited 5 hours ago
MarcoB
38.1k556114
asked 5 hours ago
Ion SmeIon Sme
876
edited 5 hours ago
MarcoB
38.1k556114
asked 5 hours ago
Ion SmeIon Sme
876
edited 5 hours ago
MarcoB
38.1k556114
edited 5 hours ago
MarcoB
38.1k556114
edited 5 hours ago
MarcoB
38.1k556114
38.1k556114
asked 5 hours ago
Ion SmeIon Sme
876
asked 5 hours ago
Ion SmeIon Sme
876
asked 5 hours ago
Ion SmeIon Sme
876
876
$begingroup$
What are $a$ and $b$ here?
$endgroup$
– mjw
5 hours ago
$begingroup$
Try a=1; b=5; But really any values give something weird
$endgroup$
– Ion Sme
5 hours ago
4
$begingroup$
Because it discretized the region in order to plot it, and it is showing the underlying triangulation mesh.
$endgroup$
– MarcoB
5 hours ago
1
$begingroup$
@IonSme I guess they just use different defaults for plotting; the Graphics result is "normal-looking" though.
$endgroup$
– MarcoB
5 hours ago
2
$begingroup$
There are some subtle differences going on how Mma showsRegions andRegionPlotGraphics. AlsoRegions can be defined analytically viaImplicitRegionorParametricRegionor as 'flat'MeshRegions.DiscretizeRegionconverts every type to aMeshRegionand some functions likeRegionPlotmight use something similar toDiscretizeRegionunder the hood to make plotting easier, whose discretization it for some reason decides to show. Like others wrote you can useImplicitRegionto get a different (not discretized) look in your case.
$endgroup$
– Thies Heidecke
4 hours ago
|
show 4 more comments
$begingroup$
What are $a$ and $b$ here?
$endgroup$
– mjw
5 hours ago
$begingroup$
Try a=1; b=5; But really any values give something weird
$endgroup$
– Ion Sme
5 hours ago
4
$begingroup$
Because it discretized the region in order to plot it, and it is showing the underlying triangulation mesh.
$endgroup$
– MarcoB
5 hours ago
1
$begingroup$
@IonSme I guess they just use different defaults for plotting; the Graphics result is "normal-looking" though.
$endgroup$
– MarcoB
5 hours ago
2
$begingroup$
There are some subtle differences going on how Mma showsRegions andRegionPlotGraphics. AlsoRegions can be defined analytically viaImplicitRegionorParametricRegionor as 'flat'MeshRegions.DiscretizeRegionconverts every type to aMeshRegionand some functions likeRegionPlotmight use something similar toDiscretizeRegionunder the hood to make plotting easier, whose discretization it for some reason decides to show. Like others wrote you can useImplicitRegionto get a different (not discretized) look in your case.
$endgroup$
– Thies Heidecke
4 hours ago
$begingroup$
What are $a$ and $b$ here?
$endgroup$
– mjw
5 hours ago
$begingroup$
What are $a$ and $b$ here?
$endgroup$
– mjw
5 hours ago
$begingroup$
Try a=1; b=5; But really any values give something weird
$endgroup$
– Ion Sme
5 hours ago
$begingroup$
Try a=1; b=5; But really any values give something weird
$endgroup$
– Ion Sme
5 hours ago
4
4
$begingroup$
Because it discretized the region in order to plot it, and it is showing the underlying triangulation mesh.
$endgroup$
– MarcoB
5 hours ago
$begingroup$
Because it discretized the region in order to plot it, and it is showing the underlying triangulation mesh.
$endgroup$
– MarcoB
5 hours ago
1
1
$begingroup$
@IonSme I guess they just use different defaults for plotting; the Graphics result is "normal-looking" though.
$endgroup$
– MarcoB
5 hours ago
$begingroup$
@IonSme I guess they just use different defaults for plotting; the Graphics result is "normal-looking" though.
$endgroup$
– MarcoB
5 hours ago
2
2
$begingroup$
There are some subtle differences going on how Mma shows
Regions and RegionPlot Graphics. Also Regions can be defined analytically via ImplicitRegion or ParametricRegion or as 'flat' MeshRegions. DiscretizeRegion converts every type to a MeshRegion and some functions like RegionPlot might use something similar to DiscretizeRegion under the hood to make plotting easier, whose discretization it for some reason decides to show. Like others wrote you can use ImplicitRegion to get a different (not discretized) look in your case.$endgroup$
– Thies Heidecke
4 hours ago
$begingroup$
There are some subtle differences going on how Mma shows
Regions and RegionPlot Graphics. Also Regions can be defined analytically via ImplicitRegion or ParametricRegion or as 'flat' MeshRegions. DiscretizeRegion converts every type to a MeshRegion and some functions like RegionPlot might use something similar to DiscretizeRegion under the hood to make plotting easier, whose discretization it for some reason decides to show. Like others wrote you can use ImplicitRegion to get a different (not discretized) look in your case.$endgroup$
– Thies Heidecke
4 hours ago
|
show 4 more comments
1 Answer
1
active
oldest
votes
4
$begingroup$
a = 1; b = 5;
Please try plotting with Region[]. These look okay to me:
Region[RegionDifference[Disk[0, 0, b], Disk[0, 0, a]]]
Region[Annulus[0, 0, a, b]]
Here is a decent plot, with RegionPlot:
RegionPlot[x^2 + y^2 > 1 && x^2 + y^2 < 25, x, -6, 6, y, -6, 6]
Here it is (again) with Graphics[]:
Graphics[LightBlue, Annulus[0, 0, a, b]]
answered 5 hours ago
mjwmjw
1,17610
$endgroup$
$begingroup$
Hmmm, that worked, but why is RegionPlot so funky?
$endgroup$
– Ion Sme
5 hours ago
1
$begingroup$
I think MarcoB mostly answers this below your question. So we can then ask: Why doesRegionPlotuse one algorithm, andRegionanother?RegionPlotseems to like functions as inputs, and also likes to have the $x$ and $y$ ranges speciifed ...
$endgroup$
– mjw
5 hours ago
add a comment |
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1 Answer
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votes
1 Answer
1
active
oldest
votes
active
oldest
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votes
4
$begingroup$
a = 1; b = 5;
Please try plotting with Region[]. These look okay to me:
Region[RegionDifference[Disk[0, 0, b], Disk[0, 0, a]]]
Region[Annulus[0, 0, a, b]]
Here is a decent plot, with RegionPlot:
RegionPlot[x^2 + y^2 > 1 && x^2 + y^2 < 25, x, -6, 6, y, -6, 6]
Here it is (again) with Graphics[]:
Graphics[LightBlue, Annulus[0, 0, a, b]]
answered 5 hours ago
mjwmjw
1,17610
$endgroup$
$begingroup$
Hmmm, that worked, but why is RegionPlot so funky?
$endgroup$
– Ion Sme
5 hours ago
1
$begingroup$
I think MarcoB mostly answers this below your question. So we can then ask: Why doesRegionPlotuse one algorithm, andRegionanother?RegionPlotseems to like functions as inputs, and also likes to have the $x$ and $y$ ranges speciifed ...
$endgroup$
– mjw
5 hours ago
add a comment |
4
$begingroup$
a = 1; b = 5;
Please try plotting with Region[]. These look okay to me:
Region[RegionDifference[Disk[0, 0, b], Disk[0, 0, a]]]
Region[Annulus[0, 0, a, b]]
Here is a decent plot, with RegionPlot:
RegionPlot[x^2 + y^2 > 1 && x^2 + y^2 < 25, x, -6, 6, y, -6, 6]
Here it is (again) with Graphics[]:
Graphics[LightBlue, Annulus[0, 0, a, b]]
answered 5 hours ago
mjwmjw
1,17610
$endgroup$
$begingroup$
Hmmm, that worked, but why is RegionPlot so funky?
$endgroup$
– Ion Sme
5 hours ago
1
$begingroup$
I think MarcoB mostly answers this below your question. So we can then ask: Why doesRegionPlotuse one algorithm, andRegionanother?RegionPlotseems to like functions as inputs, and also likes to have the $x$ and $y$ ranges speciifed ...
$endgroup$
– mjw
5 hours ago
add a comment |
4
4
4
$begingroup$
a = 1; b = 5;
Please try plotting with Region[]. These look okay to me:
Region[RegionDifference[Disk[0, 0, b], Disk[0, 0, a]]]
Region[Annulus[0, 0, a, b]]
Here is a decent plot, with RegionPlot:
RegionPlot[x^2 + y^2 > 1 && x^2 + y^2 < 25, x, -6, 6, y, -6, 6]
Here it is (again) with Graphics[]:
Graphics[LightBlue, Annulus[0, 0, a, b]]
answered 5 hours ago
mjwmjw
1,17610
$endgroup$
a = 1; b = 5;
Please try plotting with Region[]. These look okay to me:
Region[RegionDifference[Disk[0, 0, b], Disk[0, 0, a]]]
Region[Annulus[0, 0, a, b]]
Here is a decent plot, with RegionPlot:
RegionPlot[x^2 + y^2 > 1 && x^2 + y^2 < 25, x, -6, 6, y, -6, 6]
Here it is (again) with Graphics[]:
Graphics[LightBlue, Annulus[0, 0, a, b]]
answered 5 hours ago
mjwmjw
1,17610
edited 5 hours ago
answered 5 hours ago
mjwmjw
1,17610
answered 5 hours ago
mjwmjw
1,17610
answered 5 hours ago
mjwmjw
1,17610
1,17610
$begingroup$
Hmmm, that worked, but why is RegionPlot so funky?
$endgroup$
– Ion Sme
5 hours ago
1
$begingroup$
I think MarcoB mostly answers this below your question. So we can then ask: Why doesRegionPlotuse one algorithm, andRegionanother?RegionPlotseems to like functions as inputs, and also likes to have the $x$ and $y$ ranges speciifed ...
$endgroup$
– mjw
5 hours ago
add a comment |
$begingroup$
Hmmm, that worked, but why is RegionPlot so funky?
$endgroup$
– Ion Sme
5 hours ago
1
$begingroup$
I think MarcoB mostly answers this below your question. So we can then ask: Why doesRegionPlotuse one algorithm, andRegionanother?RegionPlotseems to like functions as inputs, and also likes to have the $x$ and $y$ ranges speciifed ...
$endgroup$
– mjw
5 hours ago
$begingroup$
Hmmm, that worked, but why is RegionPlot so funky?
$endgroup$
– Ion Sme
5 hours ago
$begingroup$
Hmmm, that worked, but why is RegionPlot so funky?
$endgroup$
– Ion Sme
5 hours ago
1
1
$begingroup$
I think MarcoB mostly answers this below your question. So we can then ask: Why does
RegionPlot use one algorithm, and Region another? RegionPlot seems to like functions as inputs, and also likes to have the $x$ and $y$ ranges speciifed ...$endgroup$
– mjw
5 hours ago
$begingroup$
I think MarcoB mostly answers this below your question. So we can then ask: Why does
RegionPlot use one algorithm, and Region another? RegionPlot seems to like functions as inputs, and also likes to have the $x$ and $y$ ranges speciifed ...$endgroup$
– mjw
5 hours ago
add a comment |
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$begingroup$
What are $a$ and $b$ here?
$endgroup$
– mjw
5 hours ago
$begingroup$
Try a=1; b=5; But really any values give something weird
$endgroup$
– Ion Sme
5 hours ago
4
$begingroup$
Because it discretized the region in order to plot it, and it is showing the underlying triangulation mesh.
$endgroup$
– MarcoB
5 hours ago
1
$begingroup$
@IonSme I guess they just use different defaults for plotting; the Graphics result is "normal-looking" though.
$endgroup$
– MarcoB
5 hours ago
2
$begingroup$
There are some subtle differences going on how Mma shows
Regions andRegionPlotGraphics. AlsoRegions can be defined analytically viaImplicitRegionorParametricRegionor as 'flat'MeshRegions.DiscretizeRegionconverts every type to aMeshRegionand some functions likeRegionPlotmight use something similar toDiscretizeRegionunder the hood to make plotting easier, whose discretization it for some reason decides to show. Like others wrote you can useImplicitRegionto get a different (not discretized) look in your case.$endgroup$
– Thies Heidecke
4 hours ago