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Bash method for viewing beginning and end of file
Command to display first few and last few lines of a fileRace Condition for Shell Blocks in Bash?Add character to beginning and end of columnHow to transform two delimited ASCII filesusing awk to create a LaTex table from my data in a text fileAppend columns in a text file to after the final rowRemove spaces and headers from a dumped database tableCount the maximum character length for all the data fields in a simplified csv file and output to txtWriting a program for editing .txt data - Python or Unix?Merging two Unix filesegrep regular expression - same word in the beginning and endhow to evaluate number between a range of numbers using different variables in bash
On queue-based clusters the Queue of pending jobs is shown from a command, say showqueue
.
The command returns, in columns, a list of reasonable data like names, etc, but the columns/data don't really matter for the question.
I like using the utility watch
like watch showqueue
at times (with an alias of alias watch="watch "
to force alias expansion of my command to watch). There is valuable data (Running jobs), in the first few lines, then pending jobs, etc, and some valuable summaries at the end.
However, at times the output of showqueue goes off the screen (Unbelievable, I know)! Ideally, I'd like some way to be able to see the beginning and end of the file at the same time.
The best I have so far is: showqueue > file; head -n 20 file > file2; echo "..." >> file2 ; tail -n 20 file >> file2; cat file2
, and using watch
on an alias of that.
Does anyone know of anything a little more flexible or single-utility? My solution gets a little nastier with bash loops to make the "..." break multilined, it's not adaptive to resizing the terminal window at all, and I'm sure there's more that I missed.
Any suggestions?
bash text-processing
New contributor
add a comment |
On queue-based clusters the Queue of pending jobs is shown from a command, say showqueue
.
The command returns, in columns, a list of reasonable data like names, etc, but the columns/data don't really matter for the question.
I like using the utility watch
like watch showqueue
at times (with an alias of alias watch="watch "
to force alias expansion of my command to watch). There is valuable data (Running jobs), in the first few lines, then pending jobs, etc, and some valuable summaries at the end.
However, at times the output of showqueue goes off the screen (Unbelievable, I know)! Ideally, I'd like some way to be able to see the beginning and end of the file at the same time.
The best I have so far is: showqueue > file; head -n 20 file > file2; echo "..." >> file2 ; tail -n 20 file >> file2; cat file2
, and using watch
on an alias of that.
Does anyone know of anything a little more flexible or single-utility? My solution gets a little nastier with bash loops to make the "..." break multilined, it's not adaptive to resizing the terminal window at all, and I'm sure there's more that I missed.
Any suggestions?
bash text-processing
New contributor
Closed as duplicate, but the question only shares similarities (Mine is more about a command, I learned, and not files), and the answers here didn't show up there, but if you insist
– MadisonCooper
4 hours ago
1
Fair enough. I've reopened. Note that the answer that you have accepted will only work for large outputs as noted at my answer at Command to display first few and last few lines of a file (tryseq 30 | (head && tail)
for instance).
– Stéphane Chazelas
4 hours ago
1
I meant that answer. That Q&A has two answers of mine because another Q&A was merged with it (see question history)
– Stéphane Chazelas
4 hours ago
add a comment |
On queue-based clusters the Queue of pending jobs is shown from a command, say showqueue
.
The command returns, in columns, a list of reasonable data like names, etc, but the columns/data don't really matter for the question.
I like using the utility watch
like watch showqueue
at times (with an alias of alias watch="watch "
to force alias expansion of my command to watch). There is valuable data (Running jobs), in the first few lines, then pending jobs, etc, and some valuable summaries at the end.
However, at times the output of showqueue goes off the screen (Unbelievable, I know)! Ideally, I'd like some way to be able to see the beginning and end of the file at the same time.
The best I have so far is: showqueue > file; head -n 20 file > file2; echo "..." >> file2 ; tail -n 20 file >> file2; cat file2
, and using watch
on an alias of that.
Does anyone know of anything a little more flexible or single-utility? My solution gets a little nastier with bash loops to make the "..." break multilined, it's not adaptive to resizing the terminal window at all, and I'm sure there's more that I missed.
Any suggestions?
bash text-processing
New contributor
On queue-based clusters the Queue of pending jobs is shown from a command, say showqueue
.
The command returns, in columns, a list of reasonable data like names, etc, but the columns/data don't really matter for the question.
I like using the utility watch
like watch showqueue
at times (with an alias of alias watch="watch "
to force alias expansion of my command to watch). There is valuable data (Running jobs), in the first few lines, then pending jobs, etc, and some valuable summaries at the end.
However, at times the output of showqueue goes off the screen (Unbelievable, I know)! Ideally, I'd like some way to be able to see the beginning and end of the file at the same time.
The best I have so far is: showqueue > file; head -n 20 file > file2; echo "..." >> file2 ; tail -n 20 file >> file2; cat file2
, and using watch
on an alias of that.
Does anyone know of anything a little more flexible or single-utility? My solution gets a little nastier with bash loops to make the "..." break multilined, it's not adaptive to resizing the terminal window at all, and I'm sure there's more that I missed.
Any suggestions?
bash text-processing
bash text-processing
New contributor
New contributor
edited 5 hours ago
Rui F Ribeiro
41.7k1483142
41.7k1483142
New contributor
asked 5 hours ago
MadisonCooperMadisonCooper
233
233
New contributor
New contributor
Closed as duplicate, but the question only shares similarities (Mine is more about a command, I learned, and not files), and the answers here didn't show up there, but if you insist
– MadisonCooper
4 hours ago
1
Fair enough. I've reopened. Note that the answer that you have accepted will only work for large outputs as noted at my answer at Command to display first few and last few lines of a file (tryseq 30 | (head && tail)
for instance).
– Stéphane Chazelas
4 hours ago
1
I meant that answer. That Q&A has two answers of mine because another Q&A was merged with it (see question history)
– Stéphane Chazelas
4 hours ago
add a comment |
Closed as duplicate, but the question only shares similarities (Mine is more about a command, I learned, and not files), and the answers here didn't show up there, but if you insist
– MadisonCooper
4 hours ago
1
Fair enough. I've reopened. Note that the answer that you have accepted will only work for large outputs as noted at my answer at Command to display first few and last few lines of a file (tryseq 30 | (head && tail)
for instance).
– Stéphane Chazelas
4 hours ago
1
I meant that answer. That Q&A has two answers of mine because another Q&A was merged with it (see question history)
– Stéphane Chazelas
4 hours ago
Closed as duplicate, but the question only shares similarities (Mine is more about a command, I learned, and not files), and the answers here didn't show up there, but if you insist
– MadisonCooper
4 hours ago
Closed as duplicate, but the question only shares similarities (Mine is more about a command, I learned, and not files), and the answers here didn't show up there, but if you insist
– MadisonCooper
4 hours ago
1
1
Fair enough. I've reopened. Note that the answer that you have accepted will only work for large outputs as noted at my answer at Command to display first few and last few lines of a file (try
seq 30 | (head && tail)
for instance).– Stéphane Chazelas
4 hours ago
Fair enough. I've reopened. Note that the answer that you have accepted will only work for large outputs as noted at my answer at Command to display first few and last few lines of a file (try
seq 30 | (head && tail)
for instance).– Stéphane Chazelas
4 hours ago
1
1
I meant that answer. That Q&A has two answers of mine because another Q&A was merged with it (see question history)
– Stéphane Chazelas
4 hours ago
I meant that answer. That Q&A has two answers of mine because another Q&A was merged with it (see question history)
– Stéphane Chazelas
4 hours ago
add a comment |
4 Answers
4
active
oldest
votes
Are you looking to do something like the following? Shows output from both head and tail.
$ showqueue | (head && tail)
3
Some implementations ofhead
may read more than 10 lines and leave nothing fortail
to read. The utility is not supposed to do that and I believe that the GNU tools are well behave in this respect. Usehead; echo '...'; tail
to get the dots in there as well.
– Kusalananda♦
5 hours ago
Yeah, combined with @Kusalananda's comment it's much more succinct than my solution. I'll mark as correct for now! Thanks.
– MadisonCooper
5 hours ago
2
@Kusalananda, nope, on my system, GNU head (coreutils 8.26) reads blocks of 8192 bytes. It does try to seek back, but obviously can't in case of a pipe. Though anyway, is there really a requirement forhead
to not over-read? (same on Mac, it seems to read by blocks)
– ilkkachu
5 hours ago
1
@ilkkachu yeah, even as it stands the tail part is occasionally blank even on sufficiently long output (I know since I'm using head -n 35, and that's full), but fortunately it's just a convenience to watch and I can wait 3 seconds for a refresh if needed.
– MadisonCooper
5 hours ago
1
@Kusalananda, POSIX allows implementations to do that when the input is not seekable and most implementations do. Not doing it would mean reading one byte at a time which would be very inefficient (or put the data back onto the pipe where supported which would cause all sorts of different problems). The onlyhead
implementation I know that reads one byte at a time to avoid reading past the 10th newline is ksh93'shead
builtin.
– Stéphane Chazelas
4 hours ago
|
show 3 more comments
awk solution for an arbitrary number of lines shown from the head and the tail (change n=3
to set the amount):
$ seq 99999 | awk -v n=3 'NR <= n; NR > n a[NR] = $0; delete a[NR-n];
END print "..."; for (i = NR-n+1; i <= NR; i++) if (i in a) print a[i]; '
1
2
3
...
99997
99998
99999
As it's written, the head and tail parts will not overlap, even if the input is shorter than 2*n
lines.
In some awk implementations, using for (x in a) print a[x];
in the END
part also works. But in general, it's not guaranteed to return the array entries in the correct order, and doesn't in e.g. mawk.
Ifm
is the number of lines in the file, andm < 2n
, that will print2n - m
empty lines. Also have look here ;-).for (x in a)
will iterate in order only in GNU awk; if you think that it works inmawk
too, test with > 10 values.
– mosvy
4 hours ago
@mosvy, oh, whoops, I forgot to re-check that after realizingx in a
wasn't right. Fixed now, thanks. There's also another awk answer in the question Stéphane linked to. I like the modulo trick, though!
– ilkkachu
4 hours ago
add a comment |
You can use simple awk script. Added circle buffer there n=3 is for last 3 lines
awk 'NR<=n print $0 A[NR%n]=$0 END for (i=1; i<=n; ++i) print A[(NR+i)%n] ' n=3 < <( showqueue )
New contributor
1
This would only show the first and last line. To show more than that, you would have to changeNR==1
toNR <= 10
(or something), and then collect lines into a (circular?) buffer that you later output in theEND
block.
– Kusalananda♦
5 hours ago
yes let me update
– Abdurrahim
5 hours ago
This will print some lines twice when then the number of lines is less than 2 * n.
– mosvy
4 hours ago
add a comment |
Using the same approach as you, using a temporary file, but doing it slightly shorter:
showqueue >/tmp/q.out; head -n 20 /tmp/q.out; echo '...'; tail -n 20 /tmp/q.out
This would not suffer from the same issues as discussed under another answer, but would possibly show the same lines twice if the output was shorter than 40 lines.
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Are you looking to do something like the following? Shows output from both head and tail.
$ showqueue | (head && tail)
3
Some implementations ofhead
may read more than 10 lines and leave nothing fortail
to read. The utility is not supposed to do that and I believe that the GNU tools are well behave in this respect. Usehead; echo '...'; tail
to get the dots in there as well.
– Kusalananda♦
5 hours ago
Yeah, combined with @Kusalananda's comment it's much more succinct than my solution. I'll mark as correct for now! Thanks.
– MadisonCooper
5 hours ago
2
@Kusalananda, nope, on my system, GNU head (coreutils 8.26) reads blocks of 8192 bytes. It does try to seek back, but obviously can't in case of a pipe. Though anyway, is there really a requirement forhead
to not over-read? (same on Mac, it seems to read by blocks)
– ilkkachu
5 hours ago
1
@ilkkachu yeah, even as it stands the tail part is occasionally blank even on sufficiently long output (I know since I'm using head -n 35, and that's full), but fortunately it's just a convenience to watch and I can wait 3 seconds for a refresh if needed.
– MadisonCooper
5 hours ago
1
@Kusalananda, POSIX allows implementations to do that when the input is not seekable and most implementations do. Not doing it would mean reading one byte at a time which would be very inefficient (or put the data back onto the pipe where supported which would cause all sorts of different problems). The onlyhead
implementation I know that reads one byte at a time to avoid reading past the 10th newline is ksh93'shead
builtin.
– Stéphane Chazelas
4 hours ago
|
show 3 more comments
Are you looking to do something like the following? Shows output from both head and tail.
$ showqueue | (head && tail)
3
Some implementations ofhead
may read more than 10 lines and leave nothing fortail
to read. The utility is not supposed to do that and I believe that the GNU tools are well behave in this respect. Usehead; echo '...'; tail
to get the dots in there as well.
– Kusalananda♦
5 hours ago
Yeah, combined with @Kusalananda's comment it's much more succinct than my solution. I'll mark as correct for now! Thanks.
– MadisonCooper
5 hours ago
2
@Kusalananda, nope, on my system, GNU head (coreutils 8.26) reads blocks of 8192 bytes. It does try to seek back, but obviously can't in case of a pipe. Though anyway, is there really a requirement forhead
to not over-read? (same on Mac, it seems to read by blocks)
– ilkkachu
5 hours ago
1
@ilkkachu yeah, even as it stands the tail part is occasionally blank even on sufficiently long output (I know since I'm using head -n 35, and that's full), but fortunately it's just a convenience to watch and I can wait 3 seconds for a refresh if needed.
– MadisonCooper
5 hours ago
1
@Kusalananda, POSIX allows implementations to do that when the input is not seekable and most implementations do. Not doing it would mean reading one byte at a time which would be very inefficient (or put the data back onto the pipe where supported which would cause all sorts of different problems). The onlyhead
implementation I know that reads one byte at a time to avoid reading past the 10th newline is ksh93'shead
builtin.
– Stéphane Chazelas
4 hours ago
|
show 3 more comments
Are you looking to do something like the following? Shows output from both head and tail.
$ showqueue | (head && tail)
Are you looking to do something like the following? Shows output from both head and tail.
$ showqueue | (head && tail)
answered 5 hours ago
Timothy PulliamTimothy Pulliam
1,335924
1,335924
3
Some implementations ofhead
may read more than 10 lines and leave nothing fortail
to read. The utility is not supposed to do that and I believe that the GNU tools are well behave in this respect. Usehead; echo '...'; tail
to get the dots in there as well.
– Kusalananda♦
5 hours ago
Yeah, combined with @Kusalananda's comment it's much more succinct than my solution. I'll mark as correct for now! Thanks.
– MadisonCooper
5 hours ago
2
@Kusalananda, nope, on my system, GNU head (coreutils 8.26) reads blocks of 8192 bytes. It does try to seek back, but obviously can't in case of a pipe. Though anyway, is there really a requirement forhead
to not over-read? (same on Mac, it seems to read by blocks)
– ilkkachu
5 hours ago
1
@ilkkachu yeah, even as it stands the tail part is occasionally blank even on sufficiently long output (I know since I'm using head -n 35, and that's full), but fortunately it's just a convenience to watch and I can wait 3 seconds for a refresh if needed.
– MadisonCooper
5 hours ago
1
@Kusalananda, POSIX allows implementations to do that when the input is not seekable and most implementations do. Not doing it would mean reading one byte at a time which would be very inefficient (or put the data back onto the pipe where supported which would cause all sorts of different problems). The onlyhead
implementation I know that reads one byte at a time to avoid reading past the 10th newline is ksh93'shead
builtin.
– Stéphane Chazelas
4 hours ago
|
show 3 more comments
3
Some implementations ofhead
may read more than 10 lines and leave nothing fortail
to read. The utility is not supposed to do that and I believe that the GNU tools are well behave in this respect. Usehead; echo '...'; tail
to get the dots in there as well.
– Kusalananda♦
5 hours ago
Yeah, combined with @Kusalananda's comment it's much more succinct than my solution. I'll mark as correct for now! Thanks.
– MadisonCooper
5 hours ago
2
@Kusalananda, nope, on my system, GNU head (coreutils 8.26) reads blocks of 8192 bytes. It does try to seek back, but obviously can't in case of a pipe. Though anyway, is there really a requirement forhead
to not over-read? (same on Mac, it seems to read by blocks)
– ilkkachu
5 hours ago
1
@ilkkachu yeah, even as it stands the tail part is occasionally blank even on sufficiently long output (I know since I'm using head -n 35, and that's full), but fortunately it's just a convenience to watch and I can wait 3 seconds for a refresh if needed.
– MadisonCooper
5 hours ago
1
@Kusalananda, POSIX allows implementations to do that when the input is not seekable and most implementations do. Not doing it would mean reading one byte at a time which would be very inefficient (or put the data back onto the pipe where supported which would cause all sorts of different problems). The onlyhead
implementation I know that reads one byte at a time to avoid reading past the 10th newline is ksh93'shead
builtin.
– Stéphane Chazelas
4 hours ago
3
3
Some implementations of
head
may read more than 10 lines and leave nothing for tail
to read. The utility is not supposed to do that and I believe that the GNU tools are well behave in this respect. Use head; echo '...'; tail
to get the dots in there as well.– Kusalananda♦
5 hours ago
Some implementations of
head
may read more than 10 lines and leave nothing for tail
to read. The utility is not supposed to do that and I believe that the GNU tools are well behave in this respect. Use head; echo '...'; tail
to get the dots in there as well.– Kusalananda♦
5 hours ago
Yeah, combined with @Kusalananda's comment it's much more succinct than my solution. I'll mark as correct for now! Thanks.
– MadisonCooper
5 hours ago
Yeah, combined with @Kusalananda's comment it's much more succinct than my solution. I'll mark as correct for now! Thanks.
– MadisonCooper
5 hours ago
2
2
@Kusalananda, nope, on my system, GNU head (coreutils 8.26) reads blocks of 8192 bytes. It does try to seek back, but obviously can't in case of a pipe. Though anyway, is there really a requirement for
head
to not over-read? (same on Mac, it seems to read by blocks)– ilkkachu
5 hours ago
@Kusalananda, nope, on my system, GNU head (coreutils 8.26) reads blocks of 8192 bytes. It does try to seek back, but obviously can't in case of a pipe. Though anyway, is there really a requirement for
head
to not over-read? (same on Mac, it seems to read by blocks)– ilkkachu
5 hours ago
1
1
@ilkkachu yeah, even as it stands the tail part is occasionally blank even on sufficiently long output (I know since I'm using head -n 35, and that's full), but fortunately it's just a convenience to watch and I can wait 3 seconds for a refresh if needed.
– MadisonCooper
5 hours ago
@ilkkachu yeah, even as it stands the tail part is occasionally blank even on sufficiently long output (I know since I'm using head -n 35, and that's full), but fortunately it's just a convenience to watch and I can wait 3 seconds for a refresh if needed.
– MadisonCooper
5 hours ago
1
1
@Kusalananda, POSIX allows implementations to do that when the input is not seekable and most implementations do. Not doing it would mean reading one byte at a time which would be very inefficient (or put the data back onto the pipe where supported which would cause all sorts of different problems). The only
head
implementation I know that reads one byte at a time to avoid reading past the 10th newline is ksh93's head
builtin.– Stéphane Chazelas
4 hours ago
@Kusalananda, POSIX allows implementations to do that when the input is not seekable and most implementations do. Not doing it would mean reading one byte at a time which would be very inefficient (or put the data back onto the pipe where supported which would cause all sorts of different problems). The only
head
implementation I know that reads one byte at a time to avoid reading past the 10th newline is ksh93's head
builtin.– Stéphane Chazelas
4 hours ago
|
show 3 more comments
awk solution for an arbitrary number of lines shown from the head and the tail (change n=3
to set the amount):
$ seq 99999 | awk -v n=3 'NR <= n; NR > n a[NR] = $0; delete a[NR-n];
END print "..."; for (i = NR-n+1; i <= NR; i++) if (i in a) print a[i]; '
1
2
3
...
99997
99998
99999
As it's written, the head and tail parts will not overlap, even if the input is shorter than 2*n
lines.
In some awk implementations, using for (x in a) print a[x];
in the END
part also works. But in general, it's not guaranteed to return the array entries in the correct order, and doesn't in e.g. mawk.
Ifm
is the number of lines in the file, andm < 2n
, that will print2n - m
empty lines. Also have look here ;-).for (x in a)
will iterate in order only in GNU awk; if you think that it works inmawk
too, test with > 10 values.
– mosvy
4 hours ago
@mosvy, oh, whoops, I forgot to re-check that after realizingx in a
wasn't right. Fixed now, thanks. There's also another awk answer in the question Stéphane linked to. I like the modulo trick, though!
– ilkkachu
4 hours ago
add a comment |
awk solution for an arbitrary number of lines shown from the head and the tail (change n=3
to set the amount):
$ seq 99999 | awk -v n=3 'NR <= n; NR > n a[NR] = $0; delete a[NR-n];
END print "..."; for (i = NR-n+1; i <= NR; i++) if (i in a) print a[i]; '
1
2
3
...
99997
99998
99999
As it's written, the head and tail parts will not overlap, even if the input is shorter than 2*n
lines.
In some awk implementations, using for (x in a) print a[x];
in the END
part also works. But in general, it's not guaranteed to return the array entries in the correct order, and doesn't in e.g. mawk.
Ifm
is the number of lines in the file, andm < 2n
, that will print2n - m
empty lines. Also have look here ;-).for (x in a)
will iterate in order only in GNU awk; if you think that it works inmawk
too, test with > 10 values.
– mosvy
4 hours ago
@mosvy, oh, whoops, I forgot to re-check that after realizingx in a
wasn't right. Fixed now, thanks. There's also another awk answer in the question Stéphane linked to. I like the modulo trick, though!
– ilkkachu
4 hours ago
add a comment |
awk solution for an arbitrary number of lines shown from the head and the tail (change n=3
to set the amount):
$ seq 99999 | awk -v n=3 'NR <= n; NR > n a[NR] = $0; delete a[NR-n];
END print "..."; for (i = NR-n+1; i <= NR; i++) if (i in a) print a[i]; '
1
2
3
...
99997
99998
99999
As it's written, the head and tail parts will not overlap, even if the input is shorter than 2*n
lines.
In some awk implementations, using for (x in a) print a[x];
in the END
part also works. But in general, it's not guaranteed to return the array entries in the correct order, and doesn't in e.g. mawk.
awk solution for an arbitrary number of lines shown from the head and the tail (change n=3
to set the amount):
$ seq 99999 | awk -v n=3 'NR <= n; NR > n a[NR] = $0; delete a[NR-n];
END print "..."; for (i = NR-n+1; i <= NR; i++) if (i in a) print a[i]; '
1
2
3
...
99997
99998
99999
As it's written, the head and tail parts will not overlap, even if the input is shorter than 2*n
lines.
In some awk implementations, using for (x in a) print a[x];
in the END
part also works. But in general, it's not guaranteed to return the array entries in the correct order, and doesn't in e.g. mawk.
edited 4 hours ago
answered 5 hours ago
ilkkachuilkkachu
62.7k10103180
62.7k10103180
Ifm
is the number of lines in the file, andm < 2n
, that will print2n - m
empty lines. Also have look here ;-).for (x in a)
will iterate in order only in GNU awk; if you think that it works inmawk
too, test with > 10 values.
– mosvy
4 hours ago
@mosvy, oh, whoops, I forgot to re-check that after realizingx in a
wasn't right. Fixed now, thanks. There's also another awk answer in the question Stéphane linked to. I like the modulo trick, though!
– ilkkachu
4 hours ago
add a comment |
Ifm
is the number of lines in the file, andm < 2n
, that will print2n - m
empty lines. Also have look here ;-).for (x in a)
will iterate in order only in GNU awk; if you think that it works inmawk
too, test with > 10 values.
– mosvy
4 hours ago
@mosvy, oh, whoops, I forgot to re-check that after realizingx in a
wasn't right. Fixed now, thanks. There's also another awk answer in the question Stéphane linked to. I like the modulo trick, though!
– ilkkachu
4 hours ago
If
m
is the number of lines in the file, and m < 2n
, that will print 2n - m
empty lines. Also have look here ;-). for (x in a)
will iterate in order only in GNU awk; if you think that it works in mawk
too, test with > 10 values.– mosvy
4 hours ago
If
m
is the number of lines in the file, and m < 2n
, that will print 2n - m
empty lines. Also have look here ;-). for (x in a)
will iterate in order only in GNU awk; if you think that it works in mawk
too, test with > 10 values.– mosvy
4 hours ago
@mosvy, oh, whoops, I forgot to re-check that after realizing
x in a
wasn't right. Fixed now, thanks. There's also another awk answer in the question Stéphane linked to. I like the modulo trick, though!– ilkkachu
4 hours ago
@mosvy, oh, whoops, I forgot to re-check that after realizing
x in a
wasn't right. Fixed now, thanks. There's also another awk answer in the question Stéphane linked to. I like the modulo trick, though!– ilkkachu
4 hours ago
add a comment |
You can use simple awk script. Added circle buffer there n=3 is for last 3 lines
awk 'NR<=n print $0 A[NR%n]=$0 END for (i=1; i<=n; ++i) print A[(NR+i)%n] ' n=3 < <( showqueue )
New contributor
1
This would only show the first and last line. To show more than that, you would have to changeNR==1
toNR <= 10
(or something), and then collect lines into a (circular?) buffer that you later output in theEND
block.
– Kusalananda♦
5 hours ago
yes let me update
– Abdurrahim
5 hours ago
This will print some lines twice when then the number of lines is less than 2 * n.
– mosvy
4 hours ago
add a comment |
You can use simple awk script. Added circle buffer there n=3 is for last 3 lines
awk 'NR<=n print $0 A[NR%n]=$0 END for (i=1; i<=n; ++i) print A[(NR+i)%n] ' n=3 < <( showqueue )
New contributor
1
This would only show the first and last line. To show more than that, you would have to changeNR==1
toNR <= 10
(or something), and then collect lines into a (circular?) buffer that you later output in theEND
block.
– Kusalananda♦
5 hours ago
yes let me update
– Abdurrahim
5 hours ago
This will print some lines twice when then the number of lines is less than 2 * n.
– mosvy
4 hours ago
add a comment |
You can use simple awk script. Added circle buffer there n=3 is for last 3 lines
awk 'NR<=n print $0 A[NR%n]=$0 END for (i=1; i<=n; ++i) print A[(NR+i)%n] ' n=3 < <( showqueue )
New contributor
You can use simple awk script. Added circle buffer there n=3 is for last 3 lines
awk 'NR<=n print $0 A[NR%n]=$0 END for (i=1; i<=n; ++i) print A[(NR+i)%n] ' n=3 < <( showqueue )
New contributor
edited 5 hours ago
New contributor
answered 5 hours ago
AbdurrahimAbdurrahim
1012
1012
New contributor
New contributor
1
This would only show the first and last line. To show more than that, you would have to changeNR==1
toNR <= 10
(or something), and then collect lines into a (circular?) buffer that you later output in theEND
block.
– Kusalananda♦
5 hours ago
yes let me update
– Abdurrahim
5 hours ago
This will print some lines twice when then the number of lines is less than 2 * n.
– mosvy
4 hours ago
add a comment |
1
This would only show the first and last line. To show more than that, you would have to changeNR==1
toNR <= 10
(or something), and then collect lines into a (circular?) buffer that you later output in theEND
block.
– Kusalananda♦
5 hours ago
yes let me update
– Abdurrahim
5 hours ago
This will print some lines twice when then the number of lines is less than 2 * n.
– mosvy
4 hours ago
1
1
This would only show the first and last line. To show more than that, you would have to change
NR==1
to NR <= 10
(or something), and then collect lines into a (circular?) buffer that you later output in the END
block.– Kusalananda♦
5 hours ago
This would only show the first and last line. To show more than that, you would have to change
NR==1
to NR <= 10
(or something), and then collect lines into a (circular?) buffer that you later output in the END
block.– Kusalananda♦
5 hours ago
yes let me update
– Abdurrahim
5 hours ago
yes let me update
– Abdurrahim
5 hours ago
This will print some lines twice when then the number of lines is less than 2 * n.
– mosvy
4 hours ago
This will print some lines twice when then the number of lines is less than 2 * n.
– mosvy
4 hours ago
add a comment |
Using the same approach as you, using a temporary file, but doing it slightly shorter:
showqueue >/tmp/q.out; head -n 20 /tmp/q.out; echo '...'; tail -n 20 /tmp/q.out
This would not suffer from the same issues as discussed under another answer, but would possibly show the same lines twice if the output was shorter than 40 lines.
add a comment |
Using the same approach as you, using a temporary file, but doing it slightly shorter:
showqueue >/tmp/q.out; head -n 20 /tmp/q.out; echo '...'; tail -n 20 /tmp/q.out
This would not suffer from the same issues as discussed under another answer, but would possibly show the same lines twice if the output was shorter than 40 lines.
add a comment |
Using the same approach as you, using a temporary file, but doing it slightly shorter:
showqueue >/tmp/q.out; head -n 20 /tmp/q.out; echo '...'; tail -n 20 /tmp/q.out
This would not suffer from the same issues as discussed under another answer, but would possibly show the same lines twice if the output was shorter than 40 lines.
Using the same approach as you, using a temporary file, but doing it slightly shorter:
showqueue >/tmp/q.out; head -n 20 /tmp/q.out; echo '...'; tail -n 20 /tmp/q.out
This would not suffer from the same issues as discussed under another answer, but would possibly show the same lines twice if the output was shorter than 40 lines.
edited 5 hours ago
answered 5 hours ago
Kusalananda♦Kusalananda
138k17258426
138k17258426
add a comment |
add a comment |
MadisonCooper is a new contributor. Be nice, and check out our Code of Conduct.
MadisonCooper is a new contributor. Be nice, and check out our Code of Conduct.
MadisonCooper is a new contributor. Be nice, and check out our Code of Conduct.
MadisonCooper is a new contributor. Be nice, and check out our Code of Conduct.
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Closed as duplicate, but the question only shares similarities (Mine is more about a command, I learned, and not files), and the answers here didn't show up there, but if you insist
– MadisonCooper
4 hours ago
1
Fair enough. I've reopened. Note that the answer that you have accepted will only work for large outputs as noted at my answer at Command to display first few and last few lines of a file (try
seq 30 | (head && tail)
for instance).– Stéphane Chazelas
4 hours ago
1
I meant that answer. That Q&A has two answers of mine because another Q&A was merged with it (see question history)
– Stéphane Chazelas
4 hours ago