Does a semiconductor follow Ohm's law?Does a diode really follow Ohm's Law?Is Ohm's Law violating itself?Ohm's law clarificationbrief explanation of Ohm's lawOhm's Law confusion — can there be voltage without current?Why are these readings violating ohm's law? (Are they?)Can a battery produce more amperes as per Ohm's law?High voltage transmission, transformers and Ohm's lawDoes a diode really follow Ohm's Law?General definiton of Ohm's lawHow do transformer obey Ohm's law?
What term is being referred to with "reflected-sound-of-underground-spirits"?
How to stop co-workers from teasing me because I know Russian?
Are Boeing 737-800’s grounded?
Can we say “you can pay when the order gets ready”?
What software provides a code editing environment on iPad?
How can Republicans who favour free markets, consistently express anger when they don't like the outcome of that choice?
Is it idiomatic to construct against `this`?
Why other Westeros houses don't use wildfire?
Does a semiconductor follow Ohm's law?
Real-world applications of fields, rings and groups in linear algebra.
As an international instructor, should I openly talk about my accent?
Could moose/elk survive in the Amazon forest?
What is the origin of the term "plane of the spirit level"?
Why is it that the natural deduction method can't test for invalidity?
How to pronounce 'C++' in Spanish
Was there a shared-world project before "Thieves World"?
How do I deal with a coworker that keeps asking to make small superficial changes to a report, and it is seriously triggering my anxiety?
What's the polite way to say "I need to urinate"?
Why did C use the -> operator instead of reusing the . operator?
What happened to Captain America in Endgame?
Can someone publish a story that happened to you?
Size of electromagnet needed to replicate Earth's magnetic field
Phrase for the opposite of "foolproof"
Contradiction proof for inequality of P and NP?
Does a semiconductor follow Ohm's law?
Does a diode really follow Ohm's Law?Is Ohm's Law violating itself?Ohm's law clarificationbrief explanation of Ohm's lawOhm's Law confusion — can there be voltage without current?Why are these readings violating ohm's law? (Are they?)Can a battery produce more amperes as per Ohm's law?High voltage transmission, transformers and Ohm's lawDoes a diode really follow Ohm's Law?General definiton of Ohm's lawHow do transformer obey Ohm's law?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
Ohm's law is valid for metals, but is it valid for semiconductors? Does it work there?
I am not talking about a PN junction here.
If I have a block of silicon and pass voltage across it, will I see current flowing, in accordance with Ohm's law?
semiconductors ohms-law
edited 1 hour ago
Hearth
5,28011340
asked 2 hours ago
Shaona BoseShaona Bose
1113
New contributor
Shaona Bose is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Ohm's law is valid for metals, but is it valid for semiconductors? Does it work there?
I am not talking about a PN junction here.
If I have a block of silicon and pass voltage across it, will I see current flowing, in accordance with Ohm's law?
semiconductors ohms-law
edited 1 hour ago
Hearth
5,28011340
asked 2 hours ago
Shaona BoseShaona Bose
1113
New contributor
Shaona Bose is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Yes. In fact, the very first chapter of any book on microelectronics starts out at the beginning analyzing semiconductor behavior with the assumption of the Drude model and the application of Ohm's Law (though you'd have to put some of the equations together to produce Ohm's law, since they will be using volts/meter, usually.)
$endgroup$
– jonk
2 hours ago
$begingroup$
You would need a block of silicon doped with either a N-type or P-type to make it a conductor. Silicon on it's own wouldn't conduct current because there is no transfer of electrons/holes.
$endgroup$
– Rajesh S
8 mins ago
add a comment |
$begingroup$
Ohm's law is valid for metals, but is it valid for semiconductors? Does it work there?
I am not talking about a PN junction here.
If I have a block of silicon and pass voltage across it, will I see current flowing, in accordance with Ohm's law?
semiconductors ohms-law
edited 1 hour ago
Hearth
5,28011340
asked 2 hours ago
Shaona BoseShaona Bose
1113
New contributor
Shaona Bose is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Ohm's law is valid for metals, but is it valid for semiconductors? Does it work there?
I am not talking about a PN junction here.
If I have a block of silicon and pass voltage across it, will I see current flowing, in accordance with Ohm's law?
semiconductors ohms-law
semiconductors ohms-law
edited 1 hour ago
Hearth
5,28011340
asked 2 hours ago
Shaona BoseShaona Bose
1113
New contributor
Shaona Bose is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Hearth
5,28011340
asked 2 hours ago
Shaona BoseShaona Bose
1113
New contributor
Shaona Bose is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Hearth
5,28011340
edited 1 hour ago
Hearth
5,28011340
edited 1 hour ago
Hearth
5,28011340
5,28011340
asked 2 hours ago
Shaona BoseShaona Bose
1113
New contributor
Shaona Bose is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Shaona BoseShaona Bose
1113
asked 2 hours ago
Shaona BoseShaona Bose
1113
1113
New contributor
Shaona Bose is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Shaona Bose is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Shaona Bose is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
Yes. In fact, the very first chapter of any book on microelectronics starts out at the beginning analyzing semiconductor behavior with the assumption of the Drude model and the application of Ohm's Law (though you'd have to put some of the equations together to produce Ohm's law, since they will be using volts/meter, usually.)
$endgroup$
– jonk
2 hours ago
$begingroup$
You would need a block of silicon doped with either a N-type or P-type to make it a conductor. Silicon on it's own wouldn't conduct current because there is no transfer of electrons/holes.
$endgroup$
– Rajesh S
8 mins ago
add a comment |
$begingroup$
Yes. In fact, the very first chapter of any book on microelectronics starts out at the beginning analyzing semiconductor behavior with the assumption of the Drude model and the application of Ohm's Law (though you'd have to put some of the equations together to produce Ohm's law, since they will be using volts/meter, usually.)
$endgroup$
– jonk
2 hours ago
$begingroup$
You would need a block of silicon doped with either a N-type or P-type to make it a conductor. Silicon on it's own wouldn't conduct current because there is no transfer of electrons/holes.
$endgroup$
– Rajesh S
8 mins ago
$begingroup$
Yes. In fact, the very first chapter of any book on microelectronics starts out at the beginning analyzing semiconductor behavior with the assumption of the Drude model and the application of Ohm's Law (though you'd have to put some of the equations together to produce Ohm's law, since they will be using volts/meter, usually.)
$endgroup$
– jonk
2 hours ago
$begingroup$
Yes. In fact, the very first chapter of any book on microelectronics starts out at the beginning analyzing semiconductor behavior with the assumption of the Drude model and the application of Ohm's Law (though you'd have to put some of the equations together to produce Ohm's law, since they will be using volts/meter, usually.)
$endgroup$
– jonk
2 hours ago
$begingroup$
You would need a block of silicon doped with either a N-type or P-type to make it a conductor. Silicon on it's own wouldn't conduct current because there is no transfer of electrons/holes.
$endgroup$
– Rajesh S
8 mins ago
$begingroup$
You would need a block of silicon doped with either a N-type or P-type to make it a conductor. Silicon on it's own wouldn't conduct current because there is no transfer of electrons/holes.
$endgroup$
– Rajesh S
8 mins ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Yes. All materials under normal conditions follow ohm's law, though it becomes less useful in good insulators where breakdown occurs before any substantial amount of current can flow.
Non-ohmic effects occur at boundaries between different materials, such as pn junctions, schottky junctions, thermocouples, electrochemical cells, et cetera. They can also be observed in discharge phenomena, where the flow of current causes ionization and chemical changes in the conducting material.
Edit: it's worth mentioning that the presence of (changing) magnetic fields can complicate things. Transformers and inductors are not generally considered to obey ohm's law under dynamic conditions, for instance.
For further information on where it gets murky, see this question.
answered 2 hours ago
HearthHearth
5,28011340
$endgroup$
$begingroup$
To be accurate, I'd phrase it "nearly all materials under normal conditions closely approximate Ohm's law". As engineers, we tend to separate the exceptions into nicely explained phenomena, such as resistance change due to heating, or thermoelectric effects, or rectification, etc., etc., etc. If you're going into a 16-bit ADC, then in general you only just barely start to worry. If you're going into a 24-bit ADC and the last eight aren't just there to boost your ego, then worry.
$endgroup$
– TimWescott
2 mins ago
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("schematics", function ()
StackExchange.schematics.init();
);
, "cicuitlab");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "135"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Shaona Bose is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f435719%2fdoes-a-semiconductor-follow-ohms-law%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Yes. All materials under normal conditions follow ohm's law, though it becomes less useful in good insulators where breakdown occurs before any substantial amount of current can flow.
Non-ohmic effects occur at boundaries between different materials, such as pn junctions, schottky junctions, thermocouples, electrochemical cells, et cetera. They can also be observed in discharge phenomena, where the flow of current causes ionization and chemical changes in the conducting material.
Edit: it's worth mentioning that the presence of (changing) magnetic fields can complicate things. Transformers and inductors are not generally considered to obey ohm's law under dynamic conditions, for instance.
For further information on where it gets murky, see this question.
answered 2 hours ago
HearthHearth
5,28011340
$endgroup$
$begingroup$
To be accurate, I'd phrase it "nearly all materials under normal conditions closely approximate Ohm's law". As engineers, we tend to separate the exceptions into nicely explained phenomena, such as resistance change due to heating, or thermoelectric effects, or rectification, etc., etc., etc. If you're going into a 16-bit ADC, then in general you only just barely start to worry. If you're going into a 24-bit ADC and the last eight aren't just there to boost your ego, then worry.
$endgroup$
– TimWescott
2 mins ago
add a comment |
$begingroup$
Yes. All materials under normal conditions follow ohm's law, though it becomes less useful in good insulators where breakdown occurs before any substantial amount of current can flow.
Non-ohmic effects occur at boundaries between different materials, such as pn junctions, schottky junctions, thermocouples, electrochemical cells, et cetera. They can also be observed in discharge phenomena, where the flow of current causes ionization and chemical changes in the conducting material.
Edit: it's worth mentioning that the presence of (changing) magnetic fields can complicate things. Transformers and inductors are not generally considered to obey ohm's law under dynamic conditions, for instance.
For further information on where it gets murky, see this question.
answered 2 hours ago
HearthHearth
5,28011340
$endgroup$
$begingroup$
To be accurate, I'd phrase it "nearly all materials under normal conditions closely approximate Ohm's law". As engineers, we tend to separate the exceptions into nicely explained phenomena, such as resistance change due to heating, or thermoelectric effects, or rectification, etc., etc., etc. If you're going into a 16-bit ADC, then in general you only just barely start to worry. If you're going into a 24-bit ADC and the last eight aren't just there to boost your ego, then worry.
$endgroup$
– TimWescott
2 mins ago
add a comment |
$begingroup$
Yes. All materials under normal conditions follow ohm's law, though it becomes less useful in good insulators where breakdown occurs before any substantial amount of current can flow.
Non-ohmic effects occur at boundaries between different materials, such as pn junctions, schottky junctions, thermocouples, electrochemical cells, et cetera. They can also be observed in discharge phenomena, where the flow of current causes ionization and chemical changes in the conducting material.
Edit: it's worth mentioning that the presence of (changing) magnetic fields can complicate things. Transformers and inductors are not generally considered to obey ohm's law under dynamic conditions, for instance.
For further information on where it gets murky, see this question.
answered 2 hours ago
HearthHearth
5,28011340
$endgroup$
Yes. All materials under normal conditions follow ohm's law, though it becomes less useful in good insulators where breakdown occurs before any substantial amount of current can flow.
Non-ohmic effects occur at boundaries between different materials, such as pn junctions, schottky junctions, thermocouples, electrochemical cells, et cetera. They can also be observed in discharge phenomena, where the flow of current causes ionization and chemical changes in the conducting material.
Edit: it's worth mentioning that the presence of (changing) magnetic fields can complicate things. Transformers and inductors are not generally considered to obey ohm's law under dynamic conditions, for instance.
For further information on where it gets murky, see this question.
answered 2 hours ago
HearthHearth
5,28011340
edited 2 hours ago
answered 2 hours ago
HearthHearth
5,28011340
answered 2 hours ago
HearthHearth
5,28011340
answered 2 hours ago
HearthHearth
5,28011340
5,28011340
$begingroup$
To be accurate, I'd phrase it "nearly all materials under normal conditions closely approximate Ohm's law". As engineers, we tend to separate the exceptions into nicely explained phenomena, such as resistance change due to heating, or thermoelectric effects, or rectification, etc., etc., etc. If you're going into a 16-bit ADC, then in general you only just barely start to worry. If you're going into a 24-bit ADC and the last eight aren't just there to boost your ego, then worry.
$endgroup$
– TimWescott
2 mins ago
add a comment |
$begingroup$
To be accurate, I'd phrase it "nearly all materials under normal conditions closely approximate Ohm's law". As engineers, we tend to separate the exceptions into nicely explained phenomena, such as resistance change due to heating, or thermoelectric effects, or rectification, etc., etc., etc. If you're going into a 16-bit ADC, then in general you only just barely start to worry. If you're going into a 24-bit ADC and the last eight aren't just there to boost your ego, then worry.
$endgroup$
– TimWescott
2 mins ago
$begingroup$
To be accurate, I'd phrase it "nearly all materials under normal conditions closely approximate Ohm's law". As engineers, we tend to separate the exceptions into nicely explained phenomena, such as resistance change due to heating, or thermoelectric effects, or rectification, etc., etc., etc. If you're going into a 16-bit ADC, then in general you only just barely start to worry. If you're going into a 24-bit ADC and the last eight aren't just there to boost your ego, then worry.
$endgroup$
– TimWescott
2 mins ago
$begingroup$
To be accurate, I'd phrase it "nearly all materials under normal conditions closely approximate Ohm's law". As engineers, we tend to separate the exceptions into nicely explained phenomena, such as resistance change due to heating, or thermoelectric effects, or rectification, etc., etc., etc. If you're going into a 16-bit ADC, then in general you only just barely start to worry. If you're going into a 24-bit ADC and the last eight aren't just there to boost your ego, then worry.
$endgroup$
– TimWescott
2 mins ago
add a comment |
Shaona Bose is a new contributor. Be nice, and check out our Code of Conduct.
Shaona Bose is a new contributor. Be nice, and check out our Code of Conduct.
Shaona Bose is a new contributor. Be nice, and check out our Code of Conduct.
Shaona Bose is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Electrical Engineering Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f435719%2fdoes-a-semiconductor-follow-ohms-law%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Yes. In fact, the very first chapter of any book on microelectronics starts out at the beginning analyzing semiconductor behavior with the assumption of the Drude model and the application of Ohm's Law (though you'd have to put some of the equations together to produce Ohm's law, since they will be using volts/meter, usually.)
$endgroup$
– jonk
2 hours ago
$begingroup$
You would need a block of silicon doped with either a N-type or P-type to make it a conductor. Silicon on it's own wouldn't conduct current because there is no transfer of electrons/holes.
$endgroup$
– Rajesh S
8 mins ago