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Why I cannot instantiate a class whose constructor is private in a friend class?
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30 pm US/Eastern)
Data science time! April 2019 and salary with experience
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I have two classes; Salary
that is intended to hold information and calculations regarding the salary of an employee and Employee
that has an object of type class Salary
and some members like name and address of the employee...
What I want to do is to prevent
class Salary
from being instantiated and onlyclass Employee
can instantiate it. So I declared the constructors ofSalary
private and madeEmployee
friend ofSalary
. But I get errors:class Employee;
class Salary
public:
private:
Salary() : revenue_, cost_
Salary(int x, int y) : revenue_ x ,
cost_ y
int revenue_, cost_;
friend class Employee;
;
class Employee
public:
std::string name_;
Salary sal;
;
int main()
Employee emp; // "Salary::Salary()" is inaccessibleThe problem raised for me if I forward declare
main
:int main(int, char*[]);
And make
main
friend ofclass Salary
so in Salary:class Salary
//...
friend int main(int argc, char* argv[]);
;
Now the program compiles correctly!
*** Another thing in main if I declare an object this way:
Employee emp; // ok
Employee emp; // error?
c++ constructor friend-class
add a comment |
I have two classes; Salary
that is intended to hold information and calculations regarding the salary of an employee and Employee
that has an object of type class Salary
and some members like name and address of the employee...
What I want to do is to prevent
class Salary
from being instantiated and onlyclass Employee
can instantiate it. So I declared the constructors ofSalary
private and madeEmployee
friend ofSalary
. But I get errors:class Employee;
class Salary
public:
private:
Salary() : revenue_, cost_
Salary(int x, int y) : revenue_ x ,
cost_ y
int revenue_, cost_;
friend class Employee;
;
class Employee
public:
std::string name_;
Salary sal;
;
int main()
Employee emp; // "Salary::Salary()" is inaccessibleThe problem raised for me if I forward declare
main
:int main(int, char*[]);
And make
main
friend ofclass Salary
so in Salary:class Salary
//...
friend int main(int argc, char* argv[]);
;
Now the program compiles correctly!
*** Another thing in main if I declare an object this way:
Employee emp; // ok
Employee emp; // error?
c++ constructor friend-class
Why are you makingSalary
's constructor private? It seems like there are contexts when you'd want to useSalary
outside ofEmployee
– J. Antonio Perez
4 hours ago
add a comment |
I have two classes; Salary
that is intended to hold information and calculations regarding the salary of an employee and Employee
that has an object of type class Salary
and some members like name and address of the employee...
What I want to do is to prevent
class Salary
from being instantiated and onlyclass Employee
can instantiate it. So I declared the constructors ofSalary
private and madeEmployee
friend ofSalary
. But I get errors:class Employee;
class Salary
public:
private:
Salary() : revenue_, cost_
Salary(int x, int y) : revenue_ x ,
cost_ y
int revenue_, cost_;
friend class Employee;
;
class Employee
public:
std::string name_;
Salary sal;
;
int main()
Employee emp; // "Salary::Salary()" is inaccessibleThe problem raised for me if I forward declare
main
:int main(int, char*[]);
And make
main
friend ofclass Salary
so in Salary:class Salary
//...
friend int main(int argc, char* argv[]);
;
Now the program compiles correctly!
*** Another thing in main if I declare an object this way:
Employee emp; // ok
Employee emp; // error?
c++ constructor friend-class
I have two classes; Salary
that is intended to hold information and calculations regarding the salary of an employee and Employee
that has an object of type class Salary
and some members like name and address of the employee...
What I want to do is to prevent
class Salary
from being instantiated and onlyclass Employee
can instantiate it. So I declared the constructors ofSalary
private and madeEmployee
friend ofSalary
. But I get errors:class Employee;
class Salary
public:
private:
Salary() : revenue_, cost_
Salary(int x, int y) : revenue_ x ,
cost_ y
int revenue_, cost_;
friend class Employee;
;
class Employee
public:
std::string name_;
Salary sal;
;
int main()
Employee emp; // "Salary::Salary()" is inaccessibleThe problem raised for me if I forward declare
main
:int main(int, char*[]);
And make
main
friend ofclass Salary
so in Salary:class Salary
//...
friend int main(int argc, char* argv[]);
;
Now the program compiles correctly!
*** Another thing in main if I declare an object this way:
Employee emp; // ok
Employee emp; // error?
c++ constructor friend-class
c++ constructor friend-class
edited 4 hours ago
Syfu_H
asked 4 hours ago
Syfu_HSyfu_H
36018
36018
Why are you makingSalary
's constructor private? It seems like there are contexts when you'd want to useSalary
outside ofEmployee
– J. Antonio Perez
4 hours ago
add a comment |
Why are you makingSalary
's constructor private? It seems like there are contexts when you'd want to useSalary
outside ofEmployee
– J. Antonio Perez
4 hours ago
Why are you making
Salary
's constructor private? It seems like there are contexts when you'd want to use Salary
outside of Employee
– J. Antonio Perez
4 hours ago
Why are you making
Salary
's constructor private? It seems like there are contexts when you'd want to use Salary
outside of Employee
– J. Antonio Perez
4 hours ago
add a comment |
4 Answers
4
active
oldest
votes
Because you don't provide a constructor for Employee
the braces in your initialization Employee emp;
will perform an aggregate initialization, which essentially means that each member is initialized one-by-one using the default rules, in the context of main()
. Since main()
doesn't have access to the Salary
constructor, it fails.
As others have pointed out, adding an Employee
default constructor will resolve your problem:
class Employee
public:
Employee() = default;
std::string name_;
Salary sal;
;
1
I'm trying on MSVS and onlyEmployee() ;
allowsEmployee emp;
to compile. Clang seems to acceptEmployee() = default;
, but then again, Clang seems to accept having no default constructor here.
– wally
4 hours ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 hours ago
add a comment |
You have to explicitly declare the default constructor of class Employee
thus you can initialize an abject via uniform initialization
:
class Employee
public:
Employee() // add it
std::string name_;
Salary sal;
;
int main()
Employee emp; // now this should compile
add a comment |
You need Employee
's ctor to call the ctor of Salary
. The ctor of Salary
is not accessible from main
.
eg:
class Employee
public:
Employee() : sal()
public:
std::string name_;
Salary sal;
;
add a comment |
If you erase the "" after "Employee emp" in your main() function it compiles just fine (gcc 7.3.1 on Fedora 27).
1
I recommend explaining why.
– user4581301
4 hours ago
Yes. Not onyl GCC but also MSVC14 also compilesEmployee emp;
but why?
– Syfu_H
4 hours ago
1
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
4 hours ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Because you don't provide a constructor for Employee
the braces in your initialization Employee emp;
will perform an aggregate initialization, which essentially means that each member is initialized one-by-one using the default rules, in the context of main()
. Since main()
doesn't have access to the Salary
constructor, it fails.
As others have pointed out, adding an Employee
default constructor will resolve your problem:
class Employee
public:
Employee() = default;
std::string name_;
Salary sal;
;
1
I'm trying on MSVS and onlyEmployee() ;
allowsEmployee emp;
to compile. Clang seems to acceptEmployee() = default;
, but then again, Clang seems to accept having no default constructor here.
– wally
4 hours ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 hours ago
add a comment |
Because you don't provide a constructor for Employee
the braces in your initialization Employee emp;
will perform an aggregate initialization, which essentially means that each member is initialized one-by-one using the default rules, in the context of main()
. Since main()
doesn't have access to the Salary
constructor, it fails.
As others have pointed out, adding an Employee
default constructor will resolve your problem:
class Employee
public:
Employee() = default;
std::string name_;
Salary sal;
;
1
I'm trying on MSVS and onlyEmployee() ;
allowsEmployee emp;
to compile. Clang seems to acceptEmployee() = default;
, but then again, Clang seems to accept having no default constructor here.
– wally
4 hours ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 hours ago
add a comment |
Because you don't provide a constructor for Employee
the braces in your initialization Employee emp;
will perform an aggregate initialization, which essentially means that each member is initialized one-by-one using the default rules, in the context of main()
. Since main()
doesn't have access to the Salary
constructor, it fails.
As others have pointed out, adding an Employee
default constructor will resolve your problem:
class Employee
public:
Employee() = default;
std::string name_;
Salary sal;
;
Because you don't provide a constructor for Employee
the braces in your initialization Employee emp;
will perform an aggregate initialization, which essentially means that each member is initialized one-by-one using the default rules, in the context of main()
. Since main()
doesn't have access to the Salary
constructor, it fails.
As others have pointed out, adding an Employee
default constructor will resolve your problem:
class Employee
public:
Employee() = default;
std::string name_;
Salary sal;
;
edited 4 hours ago
answered 4 hours ago
zdanzdan
22.2k34864
22.2k34864
1
I'm trying on MSVS and onlyEmployee() ;
allowsEmployee emp;
to compile. Clang seems to acceptEmployee() = default;
, but then again, Clang seems to accept having no default constructor here.
– wally
4 hours ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 hours ago
add a comment |
1
I'm trying on MSVS and onlyEmployee() ;
allowsEmployee emp;
to compile. Clang seems to acceptEmployee() = default;
, but then again, Clang seems to accept having no default constructor here.
– wally
4 hours ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 hours ago
1
1
I'm trying on MSVS and only
Employee() ;
allows Employee emp;
to compile. Clang seems to accept Employee() = default;
, but then again, Clang seems to accept having no default constructor here.– wally
4 hours ago
I'm trying on MSVS and only
Employee() ;
allows Employee emp;
to compile. Clang seems to accept Employee() = default;
, but then again, Clang seems to accept having no default constructor here.– wally
4 hours ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 hours ago
GCC does the same as Clang, and doesn't need a default constructor to compile in this case. Have you tried this answer on any specific compiler?
– wally
3 hours ago
add a comment |
You have to explicitly declare the default constructor of class Employee
thus you can initialize an abject via uniform initialization
:
class Employee
public:
Employee() // add it
std::string name_;
Salary sal;
;
int main()
Employee emp; // now this should compile
add a comment |
You have to explicitly declare the default constructor of class Employee
thus you can initialize an abject via uniform initialization
:
class Employee
public:
Employee() // add it
std::string name_;
Salary sal;
;
int main()
Employee emp; // now this should compile
add a comment |
You have to explicitly declare the default constructor of class Employee
thus you can initialize an abject via uniform initialization
:
class Employee
public:
Employee() // add it
std::string name_;
Salary sal;
;
int main()
Employee emp; // now this should compile
You have to explicitly declare the default constructor of class Employee
thus you can initialize an abject via uniform initialization
:
class Employee
public:
Employee() // add it
std::string name_;
Salary sal;
;
int main()
Employee emp; // now this should compile
answered 4 hours ago
Raindrop7Raindrop7
3,74531224
3,74531224
add a comment |
add a comment |
You need Employee
's ctor to call the ctor of Salary
. The ctor of Salary
is not accessible from main
.
eg:
class Employee
public:
Employee() : sal()
public:
std::string name_;
Salary sal;
;
add a comment |
You need Employee
's ctor to call the ctor of Salary
. The ctor of Salary
is not accessible from main
.
eg:
class Employee
public:
Employee() : sal()
public:
std::string name_;
Salary sal;
;
add a comment |
You need Employee
's ctor to call the ctor of Salary
. The ctor of Salary
is not accessible from main
.
eg:
class Employee
public:
Employee() : sal()
public:
std::string name_;
Salary sal;
;
You need Employee
's ctor to call the ctor of Salary
. The ctor of Salary
is not accessible from main
.
eg:
class Employee
public:
Employee() : sal()
public:
std::string name_;
Salary sal;
;
edited 4 hours ago
Pavan Manjunath
20.1k1181108
20.1k1181108
answered 4 hours ago
schuessschuess
536416
536416
add a comment |
add a comment |
If you erase the "" after "Employee emp" in your main() function it compiles just fine (gcc 7.3.1 on Fedora 27).
1
I recommend explaining why.
– user4581301
4 hours ago
Yes. Not onyl GCC but also MSVC14 also compilesEmployee emp;
but why?
– Syfu_H
4 hours ago
1
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
4 hours ago
add a comment |
If you erase the "" after "Employee emp" in your main() function it compiles just fine (gcc 7.3.1 on Fedora 27).
1
I recommend explaining why.
– user4581301
4 hours ago
Yes. Not onyl GCC but also MSVC14 also compilesEmployee emp;
but why?
– Syfu_H
4 hours ago
1
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
4 hours ago
add a comment |
If you erase the "" after "Employee emp" in your main() function it compiles just fine (gcc 7.3.1 on Fedora 27).
If you erase the "" after "Employee emp" in your main() function it compiles just fine (gcc 7.3.1 on Fedora 27).
answered 4 hours ago
Eric SokolowskyEric Sokolowsky
614
614
1
I recommend explaining why.
– user4581301
4 hours ago
Yes. Not onyl GCC but also MSVC14 also compilesEmployee emp;
but why?
– Syfu_H
4 hours ago
1
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
4 hours ago
add a comment |
1
I recommend explaining why.
– user4581301
4 hours ago
Yes. Not onyl GCC but also MSVC14 also compilesEmployee emp;
but why?
– Syfu_H
4 hours ago
1
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
4 hours ago
1
1
I recommend explaining why.
– user4581301
4 hours ago
I recommend explaining why.
– user4581301
4 hours ago
Yes. Not onyl GCC but also MSVC14 also compiles
Employee emp;
but why?– Syfu_H
4 hours ago
Yes. Not onyl GCC but also MSVC14 also compiles
Employee emp;
but why?– Syfu_H
4 hours ago
1
1
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
4 hours ago
@Syfu_H Value Initialization. And I could be mistaken here (been caught on this in the past), but the Value Initialization is being replaced by Aggregate Initialization
– user4581301
4 hours ago
add a comment |
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Why are you making
Salary
's constructor private? It seems like there are contexts when you'd want to useSalary
outside ofEmployee
– J. Antonio Perez
4 hours ago