Is a distribution that is normal, but highly skewed considered Gaussian? The Next CEO of Stack OverflowFinding the distribution when the observations are dependentThe correct probability distribution / way to identify large deviations in a set of daily changes to portfolio valueWhich Distribution Does the Data Point Belong to?Distribution of Sample Means Compared to Population MeanRight skewed asymmetric Gaussian-like distributionModel building and data analysisWhat would the distribution of time spent per day on a given site look like?Distinguish between underlying Distribution and data shape in data transforming?Test to determine whether the empirical distribution for a given day is an outlier compared with other daysError on mean from measurements made from a distribution with a possible long tail
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Is a distribution that is normal, but highly skewed considered Gaussian?
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Is a distribution that is normal, but highly skewed considered Gaussian?
The Next CEO of Stack OverflowFinding the distribution when the observations are dependentThe correct probability distribution / way to identify large deviations in a set of daily changes to portfolio valueWhich Distribution Does the Data Point Belong to?Distribution of Sample Means Compared to Population MeanRight skewed asymmetric Gaussian-like distributionModel building and data analysisWhat would the distribution of time spent per day on a given site look like?Distinguish between underlying Distribution and data shape in data transforming?Test to determine whether the empirical distribution for a given day is an outlier compared with other daysError on mean from measurements made from a distribution with a possible long tail
$begingroup$
I have this question: What do you think the distribution of time spent per day on YouTube looks like?
My answer is that it is probably normally distributed and highly left skewed. I expect there is one mode where most users spend around some average time and then a long right tale since some users are overwhelming power users.
Is that a fair answer? Is there a better word for that distribution?
distributions
asked 4 hours ago
CauderCauder
556
$endgroup$
add a comment |
$begingroup$
I have this question: What do you think the distribution of time spent per day on YouTube looks like?
My answer is that it is probably normally distributed and highly left skewed. I expect there is one mode where most users spend around some average time and then a long right tale since some users are overwhelming power users.
Is that a fair answer? Is there a better word for that distribution?
distributions
asked 4 hours ago
CauderCauder
556
$endgroup$
add a comment |
$begingroup$
I have this question: What do you think the distribution of time spent per day on YouTube looks like?
My answer is that it is probably normally distributed and highly left skewed. I expect there is one mode where most users spend around some average time and then a long right tale since some users are overwhelming power users.
Is that a fair answer? Is there a better word for that distribution?
distributions
asked 4 hours ago
CauderCauder
556
$endgroup$
I have this question: What do you think the distribution of time spent per day on YouTube looks like?
My answer is that it is probably normally distributed and highly left skewed. I expect there is one mode where most users spend around some average time and then a long right tale since some users are overwhelming power users.
Is that a fair answer? Is there a better word for that distribution?
distributions
distributions
asked 4 hours ago
CauderCauder
556
asked 4 hours ago
CauderCauder
556
asked 4 hours ago
CauderCauder
556
asked 4 hours ago
CauderCauder
556
asked 4 hours ago
CauderCauder
556
556
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
A distribution that is normal is not highly skewed. That is a contradiction. Normally distributed variables have skew = 0.
answered 4 hours ago
Peter Flom♦Peter Flom
76.5k11107213
$endgroup$
$begingroup$
What is a better way to describe the distribution? Is there a word for that type of distribution where it centers around a mode and then has a long tail?
$endgroup$
– Cauder
4 hours ago
2
$begingroup$
Unimodal and skewed is as close as I can come...
$endgroup$
– jbowman
4 hours ago
$begingroup$
Perfect. Thanks @jbowman
$endgroup$
– Cauder
4 hours ago
3
$begingroup$
As an aside, it's just really incredible that people give their time to help other people get better at this stuff. I know it goes without saying, but it's so cool what you both do!
$endgroup$
– Cauder
4 hours ago
add a comment |
$begingroup$
If it has long right tail, then it's right skewed.
It can't be a normal distribution since skew !=0, it's perhaps a unimodal skew normal distribution:
https://en.wikipedia.org/wiki/Skew_normal_distribution
answered 4 hours ago
beholdbehold
656
New contributor
behold is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
A fraction per day is certainly not negative. This rules out the normal distribution, which has probability mass over the entire real axis - in particular over the negative half.
Power law distributions are often used to model things like income distributions, sizes of cities etc. They are nonnegative and typically highly skewed. These would be the first I would try in modeling time spent watching YouTube. (Or monitoring CrossValidated questions.)
More information on power laws can be found here or here, or in our power-law tag.
answered 4 hours ago
Stephan KolassaStephan Kolassa
47.1k7100175
$endgroup$
$begingroup$
You're completely correct that normal distributions have support on the real line. And yet...they're no an awful model for some strictly positive qualities, like adults' height or weight, where the mean and variance are such that the negative values are very unlikely under the model.
$endgroup$
– Matt Krause
1 hour ago
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
A distribution that is normal is not highly skewed. That is a contradiction. Normally distributed variables have skew = 0.
answered 4 hours ago
Peter Flom♦Peter Flom
76.5k11107213
$endgroup$
$begingroup$
What is a better way to describe the distribution? Is there a word for that type of distribution where it centers around a mode and then has a long tail?
$endgroup$
– Cauder
4 hours ago
2
$begingroup$
Unimodal and skewed is as close as I can come...
$endgroup$
– jbowman
4 hours ago
$begingroup$
Perfect. Thanks @jbowman
$endgroup$
– Cauder
4 hours ago
3
$begingroup$
As an aside, it's just really incredible that people give their time to help other people get better at this stuff. I know it goes without saying, but it's so cool what you both do!
$endgroup$
– Cauder
4 hours ago
add a comment |
$begingroup$
A distribution that is normal is not highly skewed. That is a contradiction. Normally distributed variables have skew = 0.
answered 4 hours ago
Peter Flom♦Peter Flom
76.5k11107213
$endgroup$
$begingroup$
What is a better way to describe the distribution? Is there a word for that type of distribution where it centers around a mode and then has a long tail?
$endgroup$
– Cauder
4 hours ago
2
$begingroup$
Unimodal and skewed is as close as I can come...
$endgroup$
– jbowman
4 hours ago
$begingroup$
Perfect. Thanks @jbowman
$endgroup$
– Cauder
4 hours ago
3
$begingroup$
As an aside, it's just really incredible that people give their time to help other people get better at this stuff. I know it goes without saying, but it's so cool what you both do!
$endgroup$
– Cauder
4 hours ago
add a comment |
$begingroup$
A distribution that is normal is not highly skewed. That is a contradiction. Normally distributed variables have skew = 0.
answered 4 hours ago
Peter Flom♦Peter Flom
76.5k11107213
$endgroup$
A distribution that is normal is not highly skewed. That is a contradiction. Normally distributed variables have skew = 0.
answered 4 hours ago
Peter Flom♦Peter Flom
76.5k11107213
answered 4 hours ago
Peter Flom♦Peter Flom
76.5k11107213
answered 4 hours ago
Peter Flom♦Peter Flom
76.5k11107213
answered 4 hours ago
Peter Flom♦Peter Flom
76.5k11107213
76.5k11107213
$begingroup$
What is a better way to describe the distribution? Is there a word for that type of distribution where it centers around a mode and then has a long tail?
$endgroup$
– Cauder
4 hours ago
2
$begingroup$
Unimodal and skewed is as close as I can come...
$endgroup$
– jbowman
4 hours ago
$begingroup$
Perfect. Thanks @jbowman
$endgroup$
– Cauder
4 hours ago
3
$begingroup$
As an aside, it's just really incredible that people give their time to help other people get better at this stuff. I know it goes without saying, but it's so cool what you both do!
$endgroup$
– Cauder
4 hours ago
add a comment |
$begingroup$
What is a better way to describe the distribution? Is there a word for that type of distribution where it centers around a mode and then has a long tail?
$endgroup$
– Cauder
4 hours ago
2
$begingroup$
Unimodal and skewed is as close as I can come...
$endgroup$
– jbowman
4 hours ago
$begingroup$
Perfect. Thanks @jbowman
$endgroup$
– Cauder
4 hours ago
3
$begingroup$
As an aside, it's just really incredible that people give their time to help other people get better at this stuff. I know it goes without saying, but it's so cool what you both do!
$endgroup$
– Cauder
4 hours ago
$begingroup$
What is a better way to describe the distribution? Is there a word for that type of distribution where it centers around a mode and then has a long tail?
$endgroup$
– Cauder
4 hours ago
$begingroup$
What is a better way to describe the distribution? Is there a word for that type of distribution where it centers around a mode and then has a long tail?
$endgroup$
– Cauder
4 hours ago
2
2
$begingroup$
Unimodal and skewed is as close as I can come...
$endgroup$
– jbowman
4 hours ago
$begingroup$
Unimodal and skewed is as close as I can come...
$endgroup$
– jbowman
4 hours ago
$begingroup$
Perfect. Thanks @jbowman
$endgroup$
– Cauder
4 hours ago
$begingroup$
Perfect. Thanks @jbowman
$endgroup$
– Cauder
4 hours ago
3
3
$begingroup$
As an aside, it's just really incredible that people give their time to help other people get better at this stuff. I know it goes without saying, but it's so cool what you both do!
$endgroup$
– Cauder
4 hours ago
$begingroup$
As an aside, it's just really incredible that people give their time to help other people get better at this stuff. I know it goes without saying, but it's so cool what you both do!
$endgroup$
– Cauder
4 hours ago
add a comment |
$begingroup$
If it has long right tail, then it's right skewed.
It can't be a normal distribution since skew !=0, it's perhaps a unimodal skew normal distribution:
https://en.wikipedia.org/wiki/Skew_normal_distribution
answered 4 hours ago
beholdbehold
656
New contributor
behold is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
If it has long right tail, then it's right skewed.
It can't be a normal distribution since skew !=0, it's perhaps a unimodal skew normal distribution:
https://en.wikipedia.org/wiki/Skew_normal_distribution
answered 4 hours ago
beholdbehold
656
New contributor
behold is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
If it has long right tail, then it's right skewed.
It can't be a normal distribution since skew !=0, it's perhaps a unimodal skew normal distribution:
https://en.wikipedia.org/wiki/Skew_normal_distribution
answered 4 hours ago
beholdbehold
656
New contributor
behold is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
If it has long right tail, then it's right skewed.
It can't be a normal distribution since skew !=0, it's perhaps a unimodal skew normal distribution:
https://en.wikipedia.org/wiki/Skew_normal_distribution
answered 4 hours ago
beholdbehold
656
New contributor
behold is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 4 hours ago
beholdbehold
656
New contributor
behold is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 4 hours ago
beholdbehold
656
answered 4 hours ago
beholdbehold
656
656
New contributor
behold is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
behold is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
behold is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
$begingroup$
A fraction per day is certainly not negative. This rules out the normal distribution, which has probability mass over the entire real axis - in particular over the negative half.
Power law distributions are often used to model things like income distributions, sizes of cities etc. They are nonnegative and typically highly skewed. These would be the first I would try in modeling time spent watching YouTube. (Or monitoring CrossValidated questions.)
More information on power laws can be found here or here, or in our power-law tag.
answered 4 hours ago
Stephan KolassaStephan Kolassa
47.1k7100175
$endgroup$
$begingroup$
You're completely correct that normal distributions have support on the real line. And yet...they're no an awful model for some strictly positive qualities, like adults' height or weight, where the mean and variance are such that the negative values are very unlikely under the model.
$endgroup$
– Matt Krause
1 hour ago
add a comment |
$begingroup$
A fraction per day is certainly not negative. This rules out the normal distribution, which has probability mass over the entire real axis - in particular over the negative half.
Power law distributions are often used to model things like income distributions, sizes of cities etc. They are nonnegative and typically highly skewed. These would be the first I would try in modeling time spent watching YouTube. (Or monitoring CrossValidated questions.)
More information on power laws can be found here or here, or in our power-law tag.
answered 4 hours ago
Stephan KolassaStephan Kolassa
47.1k7100175
$endgroup$
$begingroup$
You're completely correct that normal distributions have support on the real line. And yet...they're no an awful model for some strictly positive qualities, like adults' height or weight, where the mean and variance are such that the negative values are very unlikely under the model.
$endgroup$
– Matt Krause
1 hour ago
add a comment |
$begingroup$
A fraction per day is certainly not negative. This rules out the normal distribution, which has probability mass over the entire real axis - in particular over the negative half.
Power law distributions are often used to model things like income distributions, sizes of cities etc. They are nonnegative and typically highly skewed. These would be the first I would try in modeling time spent watching YouTube. (Or monitoring CrossValidated questions.)
More information on power laws can be found here or here, or in our power-law tag.
answered 4 hours ago
Stephan KolassaStephan Kolassa
47.1k7100175
$endgroup$
A fraction per day is certainly not negative. This rules out the normal distribution, which has probability mass over the entire real axis - in particular over the negative half.
Power law distributions are often used to model things like income distributions, sizes of cities etc. They are nonnegative and typically highly skewed. These would be the first I would try in modeling time spent watching YouTube. (Or monitoring CrossValidated questions.)
More information on power laws can be found here or here, or in our power-law tag.
answered 4 hours ago
Stephan KolassaStephan Kolassa
47.1k7100175
answered 4 hours ago
Stephan KolassaStephan Kolassa
47.1k7100175
answered 4 hours ago
Stephan KolassaStephan Kolassa
47.1k7100175
answered 4 hours ago
Stephan KolassaStephan Kolassa
47.1k7100175
47.1k7100175
$begingroup$
You're completely correct that normal distributions have support on the real line. And yet...they're no an awful model for some strictly positive qualities, like adults' height or weight, where the mean and variance are such that the negative values are very unlikely under the model.
$endgroup$
– Matt Krause
1 hour ago
add a comment |
$begingroup$
You're completely correct that normal distributions have support on the real line. And yet...they're no an awful model for some strictly positive qualities, like adults' height or weight, where the mean and variance are such that the negative values are very unlikely under the model.
$endgroup$
– Matt Krause
1 hour ago
$begingroup$
You're completely correct that normal distributions have support on the real line. And yet...they're no an awful model for some strictly positive qualities, like adults' height or weight, where the mean and variance are such that the negative values are very unlikely under the model.
$endgroup$
– Matt Krause
1 hour ago
$begingroup$
You're completely correct that normal distributions have support on the real line. And yet...they're no an awful model for some strictly positive qualities, like adults' height or weight, where the mean and variance are such that the negative values are very unlikely under the model.
$endgroup$
– Matt Krause
1 hour ago
add a comment |
Thanks for contributing an answer to Cross Validated!
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