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Would a grinding machine be a simple and workable propulsion system for an interplanetary spacecraft?

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Would a grinding machine be a simple and workable propulsion system for an interplanetary spacecraft?



The Next CEO of Stack OverflowCould antimatter be used for spacecraft propulsion?How much does it cost to fill an ion thuster with Xenon for a spacecraft propulsion system?Is a spherical rocket design a plausible replacement for current designs today?Pulse Rocket EngineHow does Accion System's TILE propulsion module compare to an equivalently sized Hall effect or an Ion thruster?Liquid shield for spacecraft?Could a spacecraft be propelled by a 180 degree deflection of two charged particle beams?If specific impulse is directly related to exhaust velocity, would a ion post-accelerator improve the Isp of a propulsion system?Could protons in the Sun's solar wind be used to create a photonic laser thruster for a spacecraft?Very Low Gravity Bicycle










4












$begingroup$


I am wondering if any space agency has ever considered using a grinding machine as a propulsion system for an interplanetary spacecraft. This system would not be used to lift the spacecraft off of a planet's surface, but rather used solely as an interplanetary/interstellar propulsion system.



The working principle is a simple one (see picture below). This grinding machine would be located at the stern of the spacecraft. Metal shavings flying off of the grinding wheel of this grinding machine would produce a propelling force for the spacecraft via Newton's Third Law of Motion. The amount of propulsion produced at any one time would be achieved by increasing/decreasing the rotational speed of the grinding wheel.



The electrical source for the electric motor of the grinding machine could be a small nuclear power plant on board the spacecraft. The 'fuel' source could be long steel rods or large rocks. A source of rocks could be obtained by mining an asteroid field or a small moon. Lastly, I think that diamond grinding wheels would probably be the most ideal to use due to their durability and longevity.



Would a grinding machine be a simple and workable propulsion system for an interplanetary spacecraft?



enter image description here










share|improve this question











$endgroup$







  • 2




    $begingroup$
    It would need 2 grinding machines for a counter balance.
    $endgroup$
    – Muze
    3 hours ago










  • $begingroup$
    @Muze, thanks for pointing that out
    $endgroup$
    – HRIATEXP
    1 hour ago















4












$begingroup$


I am wondering if any space agency has ever considered using a grinding machine as a propulsion system for an interplanetary spacecraft. This system would not be used to lift the spacecraft off of a planet's surface, but rather used solely as an interplanetary/interstellar propulsion system.



The working principle is a simple one (see picture below). This grinding machine would be located at the stern of the spacecraft. Metal shavings flying off of the grinding wheel of this grinding machine would produce a propelling force for the spacecraft via Newton's Third Law of Motion. The amount of propulsion produced at any one time would be achieved by increasing/decreasing the rotational speed of the grinding wheel.



The electrical source for the electric motor of the grinding machine could be a small nuclear power plant on board the spacecraft. The 'fuel' source could be long steel rods or large rocks. A source of rocks could be obtained by mining an asteroid field or a small moon. Lastly, I think that diamond grinding wheels would probably be the most ideal to use due to their durability and longevity.



Would a grinding machine be a simple and workable propulsion system for an interplanetary spacecraft?



enter image description here










share|improve this question











$endgroup$







  • 2




    $begingroup$
    It would need 2 grinding machines for a counter balance.
    $endgroup$
    – Muze
    3 hours ago










  • $begingroup$
    @Muze, thanks for pointing that out
    $endgroup$
    – HRIATEXP
    1 hour ago













4












4








4





$begingroup$


I am wondering if any space agency has ever considered using a grinding machine as a propulsion system for an interplanetary spacecraft. This system would not be used to lift the spacecraft off of a planet's surface, but rather used solely as an interplanetary/interstellar propulsion system.



The working principle is a simple one (see picture below). This grinding machine would be located at the stern of the spacecraft. Metal shavings flying off of the grinding wheel of this grinding machine would produce a propelling force for the spacecraft via Newton's Third Law of Motion. The amount of propulsion produced at any one time would be achieved by increasing/decreasing the rotational speed of the grinding wheel.



The electrical source for the electric motor of the grinding machine could be a small nuclear power plant on board the spacecraft. The 'fuel' source could be long steel rods or large rocks. A source of rocks could be obtained by mining an asteroid field or a small moon. Lastly, I think that diamond grinding wheels would probably be the most ideal to use due to their durability and longevity.



Would a grinding machine be a simple and workable propulsion system for an interplanetary spacecraft?



enter image description here










share|improve this question











$endgroup$




I am wondering if any space agency has ever considered using a grinding machine as a propulsion system for an interplanetary spacecraft. This system would not be used to lift the spacecraft off of a planet's surface, but rather used solely as an interplanetary/interstellar propulsion system.



The working principle is a simple one (see picture below). This grinding machine would be located at the stern of the spacecraft. Metal shavings flying off of the grinding wheel of this grinding machine would produce a propelling force for the spacecraft via Newton's Third Law of Motion. The amount of propulsion produced at any one time would be achieved by increasing/decreasing the rotational speed of the grinding wheel.



The electrical source for the electric motor of the grinding machine could be a small nuclear power plant on board the spacecraft. The 'fuel' source could be long steel rods or large rocks. A source of rocks could be obtained by mining an asteroid field or a small moon. Lastly, I think that diamond grinding wheels would probably be the most ideal to use due to their durability and longevity.



Would a grinding machine be a simple and workable propulsion system for an interplanetary spacecraft?



enter image description here







spacecraft propulsion engine-design physics design-alternative






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 1 hour ago







HRIATEXP

















asked 4 hours ago









HRIATEXPHRIATEXP

1776




1776







  • 2




    $begingroup$
    It would need 2 grinding machines for a counter balance.
    $endgroup$
    – Muze
    3 hours ago










  • $begingroup$
    @Muze, thanks for pointing that out
    $endgroup$
    – HRIATEXP
    1 hour ago












  • 2




    $begingroup$
    It would need 2 grinding machines for a counter balance.
    $endgroup$
    – Muze
    3 hours ago










  • $begingroup$
    @Muze, thanks for pointing that out
    $endgroup$
    – HRIATEXP
    1 hour ago







2




2




$begingroup$
It would need 2 grinding machines for a counter balance.
$endgroup$
– Muze
3 hours ago




$begingroup$
It would need 2 grinding machines for a counter balance.
$endgroup$
– Muze
3 hours ago












$begingroup$
@Muze, thanks for pointing that out
$endgroup$
– HRIATEXP
1 hour ago




$begingroup$
@Muze, thanks for pointing that out
$endgroup$
– HRIATEXP
1 hour ago










2 Answers
2






active

oldest

votes


















2












$begingroup$

I don't know if it has ever been considered by anyone.



In my view, this is not a good idea for at least the following reasons:



  1. It is equivalent to mechanically throwing things retrograde. See this video for an overly simple example. This is obviously not a good way for propulsion, as the specific impulse is very low. Let's talk just about the impulse $$p=mv$$ here, where $m$ is the "reaction mass", i.e. the mass of the material that's being ground, the object being throw backwards, or chemical propellant. $v$ is the velocity of the reaction mass relative to the spacecraft. The velocity $v$ of the sparks is in the order of a few m/s (same velocity as the edge of the grinding wheel. With chemical propellants, it is a few km/s. So, for the same amount $m$ of reaction mass that you carry, classical propulsion gives you a factor of about 1000 more impulse than grinding.

  2. The produced momentum is kind of stochastic. As can be seen in your graphic, the sparks form a cone instead of a straight line. While the upward and the downward motions statistically cancel each other, their vertical components are a waste. While admittedly this also applies to chemical rocket engines (and ion thrusters?), just throwing some stuff overboard would be more efficient in this respect.

Still, I like this question for thinking out of the box. On a side note, reading the title reminded me of this passage of J.D. Clark's book "Ignition!":




F.A. Tsander in Moscow [...] had suggested that an astronaut might stretch his fuel supply by imitating Phileas Fogg. When a fuel tank was emptied, the astronaut could simply grind it up and add the powdered aluminum thus obtaining to the remaining fuel, whose heating value would be correspondingly enhanced!




I think this was actually tried, but found not to work well because the Aluminium particles take too long to combust, i.e. they continue to burn after they have left the combustion chamber. (Some?) Solid rocket propellants are based on Aluminium, though, but that's different.






share|improve this answer









$endgroup$












  • $begingroup$
    Don't make the velocity "a few m/s". The question doesn't constrain the wheel and bar to any particular composition, there's no reason to choose the worst case to base your answer on. Also, cosine losses are often present in real propulsion systems for various reasons, they are not show-stoppers.
    $endgroup$
    – uhoh
    48 mins ago



















1












$begingroup$

Good for you, for thinking outside the box! Fearlessly pursuing new ideas is where any new breakthrough comes from.



But rocket exhaust moves at thousands of meters per second -- supersonic speeds. Recalling the formula relating acceleration to velocity for circular motion, a=v^2/r. So, given a velocity of 3,000 meters per second and a wheel radius of, say, 1 meter, the acceleration at the rim would be roughly 9,000,000 m/s^2, or 900,000 times Earth gravity. And angular velocity, v=Rw, or 9,000,000 radians per second. I think you would have trouble spinning the wheel up to that kind of speed, and I think you would have trouble finding a wheel material that wouldn't fly apart.






share|improve this answer









$endgroup$








  • 2




    $begingroup$
    Why can't the wheel be 1cm or even 1 mm in diameter? Maybe outside-the-box thinking is possible in answers as well? There are applications in spaceflight where high Isp is needed but at low thrust (e.g. anywhere solar-electric propulsion is used) so a system with high velocity but physically small scale might be interesting to explore for the interplanetary spacecraft.
    $endgroup$
    – uhoh
    40 mins ago







  • 1




    $begingroup$
    The speed at the rim is the radius times the angular speed. If you cut the radius by a factor of ten the angular speed has to increase by a factor of ten to keep the speed at the rim constant. I believe that brings us up to a hundred million radians per second. I look at those numbers and, well, I think we would probably have to put some work into it yet. It's pretty fast.
    $endgroup$
    – Greg
    26 mins ago










  • $begingroup$
    Okay now I'm going to think about this more myself, thanks!
    $endgroup$
    – uhoh
    21 mins ago











Your Answer





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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

I don't know if it has ever been considered by anyone.



In my view, this is not a good idea for at least the following reasons:



  1. It is equivalent to mechanically throwing things retrograde. See this video for an overly simple example. This is obviously not a good way for propulsion, as the specific impulse is very low. Let's talk just about the impulse $$p=mv$$ here, where $m$ is the "reaction mass", i.e. the mass of the material that's being ground, the object being throw backwards, or chemical propellant. $v$ is the velocity of the reaction mass relative to the spacecraft. The velocity $v$ of the sparks is in the order of a few m/s (same velocity as the edge of the grinding wheel. With chemical propellants, it is a few km/s. So, for the same amount $m$ of reaction mass that you carry, classical propulsion gives you a factor of about 1000 more impulse than grinding.

  2. The produced momentum is kind of stochastic. As can be seen in your graphic, the sparks form a cone instead of a straight line. While the upward and the downward motions statistically cancel each other, their vertical components are a waste. While admittedly this also applies to chemical rocket engines (and ion thrusters?), just throwing some stuff overboard would be more efficient in this respect.

Still, I like this question for thinking out of the box. On a side note, reading the title reminded me of this passage of J.D. Clark's book "Ignition!":




F.A. Tsander in Moscow [...] had suggested that an astronaut might stretch his fuel supply by imitating Phileas Fogg. When a fuel tank was emptied, the astronaut could simply grind it up and add the powdered aluminum thus obtaining to the remaining fuel, whose heating value would be correspondingly enhanced!




I think this was actually tried, but found not to work well because the Aluminium particles take too long to combust, i.e. they continue to burn after they have left the combustion chamber. (Some?) Solid rocket propellants are based on Aluminium, though, but that's different.






share|improve this answer









$endgroup$












  • $begingroup$
    Don't make the velocity "a few m/s". The question doesn't constrain the wheel and bar to any particular composition, there's no reason to choose the worst case to base your answer on. Also, cosine losses are often present in real propulsion systems for various reasons, they are not show-stoppers.
    $endgroup$
    – uhoh
    48 mins ago
















2












$begingroup$

I don't know if it has ever been considered by anyone.



In my view, this is not a good idea for at least the following reasons:



  1. It is equivalent to mechanically throwing things retrograde. See this video for an overly simple example. This is obviously not a good way for propulsion, as the specific impulse is very low. Let's talk just about the impulse $$p=mv$$ here, where $m$ is the "reaction mass", i.e. the mass of the material that's being ground, the object being throw backwards, or chemical propellant. $v$ is the velocity of the reaction mass relative to the spacecraft. The velocity $v$ of the sparks is in the order of a few m/s (same velocity as the edge of the grinding wheel. With chemical propellants, it is a few km/s. So, for the same amount $m$ of reaction mass that you carry, classical propulsion gives you a factor of about 1000 more impulse than grinding.

  2. The produced momentum is kind of stochastic. As can be seen in your graphic, the sparks form a cone instead of a straight line. While the upward and the downward motions statistically cancel each other, their vertical components are a waste. While admittedly this also applies to chemical rocket engines (and ion thrusters?), just throwing some stuff overboard would be more efficient in this respect.

Still, I like this question for thinking out of the box. On a side note, reading the title reminded me of this passage of J.D. Clark's book "Ignition!":




F.A. Tsander in Moscow [...] had suggested that an astronaut might stretch his fuel supply by imitating Phileas Fogg. When a fuel tank was emptied, the astronaut could simply grind it up and add the powdered aluminum thus obtaining to the remaining fuel, whose heating value would be correspondingly enhanced!




I think this was actually tried, but found not to work well because the Aluminium particles take too long to combust, i.e. they continue to burn after they have left the combustion chamber. (Some?) Solid rocket propellants are based on Aluminium, though, but that's different.






share|improve this answer









$endgroup$












  • $begingroup$
    Don't make the velocity "a few m/s". The question doesn't constrain the wheel and bar to any particular composition, there's no reason to choose the worst case to base your answer on. Also, cosine losses are often present in real propulsion systems for various reasons, they are not show-stoppers.
    $endgroup$
    – uhoh
    48 mins ago














2












2








2





$begingroup$

I don't know if it has ever been considered by anyone.



In my view, this is not a good idea for at least the following reasons:



  1. It is equivalent to mechanically throwing things retrograde. See this video for an overly simple example. This is obviously not a good way for propulsion, as the specific impulse is very low. Let's talk just about the impulse $$p=mv$$ here, where $m$ is the "reaction mass", i.e. the mass of the material that's being ground, the object being throw backwards, or chemical propellant. $v$ is the velocity of the reaction mass relative to the spacecraft. The velocity $v$ of the sparks is in the order of a few m/s (same velocity as the edge of the grinding wheel. With chemical propellants, it is a few km/s. So, for the same amount $m$ of reaction mass that you carry, classical propulsion gives you a factor of about 1000 more impulse than grinding.

  2. The produced momentum is kind of stochastic. As can be seen in your graphic, the sparks form a cone instead of a straight line. While the upward and the downward motions statistically cancel each other, their vertical components are a waste. While admittedly this also applies to chemical rocket engines (and ion thrusters?), just throwing some stuff overboard would be more efficient in this respect.

Still, I like this question for thinking out of the box. On a side note, reading the title reminded me of this passage of J.D. Clark's book "Ignition!":




F.A. Tsander in Moscow [...] had suggested that an astronaut might stretch his fuel supply by imitating Phileas Fogg. When a fuel tank was emptied, the astronaut could simply grind it up and add the powdered aluminum thus obtaining to the remaining fuel, whose heating value would be correspondingly enhanced!




I think this was actually tried, but found not to work well because the Aluminium particles take too long to combust, i.e. they continue to burn after they have left the combustion chamber. (Some?) Solid rocket propellants are based on Aluminium, though, but that's different.






share|improve this answer









$endgroup$



I don't know if it has ever been considered by anyone.



In my view, this is not a good idea for at least the following reasons:



  1. It is equivalent to mechanically throwing things retrograde. See this video for an overly simple example. This is obviously not a good way for propulsion, as the specific impulse is very low. Let's talk just about the impulse $$p=mv$$ here, where $m$ is the "reaction mass", i.e. the mass of the material that's being ground, the object being throw backwards, or chemical propellant. $v$ is the velocity of the reaction mass relative to the spacecraft. The velocity $v$ of the sparks is in the order of a few m/s (same velocity as the edge of the grinding wheel. With chemical propellants, it is a few km/s. So, for the same amount $m$ of reaction mass that you carry, classical propulsion gives you a factor of about 1000 more impulse than grinding.

  2. The produced momentum is kind of stochastic. As can be seen in your graphic, the sparks form a cone instead of a straight line. While the upward and the downward motions statistically cancel each other, their vertical components are a waste. While admittedly this also applies to chemical rocket engines (and ion thrusters?), just throwing some stuff overboard would be more efficient in this respect.

Still, I like this question for thinking out of the box. On a side note, reading the title reminded me of this passage of J.D. Clark's book "Ignition!":




F.A. Tsander in Moscow [...] had suggested that an astronaut might stretch his fuel supply by imitating Phileas Fogg. When a fuel tank was emptied, the astronaut could simply grind it up and add the powdered aluminum thus obtaining to the remaining fuel, whose heating value would be correspondingly enhanced!




I think this was actually tried, but found not to work well because the Aluminium particles take too long to combust, i.e. they continue to burn after they have left the combustion chamber. (Some?) Solid rocket propellants are based on Aluminium, though, but that's different.







share|improve this answer












share|improve this answer



share|improve this answer










answered 2 hours ago









Everyday AstronautEveryday Astronaut

2,215832




2,215832











  • $begingroup$
    Don't make the velocity "a few m/s". The question doesn't constrain the wheel and bar to any particular composition, there's no reason to choose the worst case to base your answer on. Also, cosine losses are often present in real propulsion systems for various reasons, they are not show-stoppers.
    $endgroup$
    – uhoh
    48 mins ago

















  • $begingroup$
    Don't make the velocity "a few m/s". The question doesn't constrain the wheel and bar to any particular composition, there's no reason to choose the worst case to base your answer on. Also, cosine losses are often present in real propulsion systems for various reasons, they are not show-stoppers.
    $endgroup$
    – uhoh
    48 mins ago
















$begingroup$
Don't make the velocity "a few m/s". The question doesn't constrain the wheel and bar to any particular composition, there's no reason to choose the worst case to base your answer on. Also, cosine losses are often present in real propulsion systems for various reasons, they are not show-stoppers.
$endgroup$
– uhoh
48 mins ago





$begingroup$
Don't make the velocity "a few m/s". The question doesn't constrain the wheel and bar to any particular composition, there's no reason to choose the worst case to base your answer on. Also, cosine losses are often present in real propulsion systems for various reasons, they are not show-stoppers.
$endgroup$
– uhoh
48 mins ago












1












$begingroup$

Good for you, for thinking outside the box! Fearlessly pursuing new ideas is where any new breakthrough comes from.



But rocket exhaust moves at thousands of meters per second -- supersonic speeds. Recalling the formula relating acceleration to velocity for circular motion, a=v^2/r. So, given a velocity of 3,000 meters per second and a wheel radius of, say, 1 meter, the acceleration at the rim would be roughly 9,000,000 m/s^2, or 900,000 times Earth gravity. And angular velocity, v=Rw, or 9,000,000 radians per second. I think you would have trouble spinning the wheel up to that kind of speed, and I think you would have trouble finding a wheel material that wouldn't fly apart.






share|improve this answer









$endgroup$








  • 2




    $begingroup$
    Why can't the wheel be 1cm or even 1 mm in diameter? Maybe outside-the-box thinking is possible in answers as well? There are applications in spaceflight where high Isp is needed but at low thrust (e.g. anywhere solar-electric propulsion is used) so a system with high velocity but physically small scale might be interesting to explore for the interplanetary spacecraft.
    $endgroup$
    – uhoh
    40 mins ago







  • 1




    $begingroup$
    The speed at the rim is the radius times the angular speed. If you cut the radius by a factor of ten the angular speed has to increase by a factor of ten to keep the speed at the rim constant. I believe that brings us up to a hundred million radians per second. I look at those numbers and, well, I think we would probably have to put some work into it yet. It's pretty fast.
    $endgroup$
    – Greg
    26 mins ago










  • $begingroup$
    Okay now I'm going to think about this more myself, thanks!
    $endgroup$
    – uhoh
    21 mins ago















1












$begingroup$

Good for you, for thinking outside the box! Fearlessly pursuing new ideas is where any new breakthrough comes from.



But rocket exhaust moves at thousands of meters per second -- supersonic speeds. Recalling the formula relating acceleration to velocity for circular motion, a=v^2/r. So, given a velocity of 3,000 meters per second and a wheel radius of, say, 1 meter, the acceleration at the rim would be roughly 9,000,000 m/s^2, or 900,000 times Earth gravity. And angular velocity, v=Rw, or 9,000,000 radians per second. I think you would have trouble spinning the wheel up to that kind of speed, and I think you would have trouble finding a wheel material that wouldn't fly apart.






share|improve this answer









$endgroup$








  • 2




    $begingroup$
    Why can't the wheel be 1cm or even 1 mm in diameter? Maybe outside-the-box thinking is possible in answers as well? There are applications in spaceflight where high Isp is needed but at low thrust (e.g. anywhere solar-electric propulsion is used) so a system with high velocity but physically small scale might be interesting to explore for the interplanetary spacecraft.
    $endgroup$
    – uhoh
    40 mins ago







  • 1




    $begingroup$
    The speed at the rim is the radius times the angular speed. If you cut the radius by a factor of ten the angular speed has to increase by a factor of ten to keep the speed at the rim constant. I believe that brings us up to a hundred million radians per second. I look at those numbers and, well, I think we would probably have to put some work into it yet. It's pretty fast.
    $endgroup$
    – Greg
    26 mins ago










  • $begingroup$
    Okay now I'm going to think about this more myself, thanks!
    $endgroup$
    – uhoh
    21 mins ago













1












1








1





$begingroup$

Good for you, for thinking outside the box! Fearlessly pursuing new ideas is where any new breakthrough comes from.



But rocket exhaust moves at thousands of meters per second -- supersonic speeds. Recalling the formula relating acceleration to velocity for circular motion, a=v^2/r. So, given a velocity of 3,000 meters per second and a wheel radius of, say, 1 meter, the acceleration at the rim would be roughly 9,000,000 m/s^2, or 900,000 times Earth gravity. And angular velocity, v=Rw, or 9,000,000 radians per second. I think you would have trouble spinning the wheel up to that kind of speed, and I think you would have trouble finding a wheel material that wouldn't fly apart.






share|improve this answer









$endgroup$



Good for you, for thinking outside the box! Fearlessly pursuing new ideas is where any new breakthrough comes from.



But rocket exhaust moves at thousands of meters per second -- supersonic speeds. Recalling the formula relating acceleration to velocity for circular motion, a=v^2/r. So, given a velocity of 3,000 meters per second and a wheel radius of, say, 1 meter, the acceleration at the rim would be roughly 9,000,000 m/s^2, or 900,000 times Earth gravity. And angular velocity, v=Rw, or 9,000,000 radians per second. I think you would have trouble spinning the wheel up to that kind of speed, and I think you would have trouble finding a wheel material that wouldn't fly apart.







share|improve this answer












share|improve this answer



share|improve this answer










answered 2 hours ago









GregGreg

84137




84137







  • 2




    $begingroup$
    Why can't the wheel be 1cm or even 1 mm in diameter? Maybe outside-the-box thinking is possible in answers as well? There are applications in spaceflight where high Isp is needed but at low thrust (e.g. anywhere solar-electric propulsion is used) so a system with high velocity but physically small scale might be interesting to explore for the interplanetary spacecraft.
    $endgroup$
    – uhoh
    40 mins ago







  • 1




    $begingroup$
    The speed at the rim is the radius times the angular speed. If you cut the radius by a factor of ten the angular speed has to increase by a factor of ten to keep the speed at the rim constant. I believe that brings us up to a hundred million radians per second. I look at those numbers and, well, I think we would probably have to put some work into it yet. It's pretty fast.
    $endgroup$
    – Greg
    26 mins ago










  • $begingroup$
    Okay now I'm going to think about this more myself, thanks!
    $endgroup$
    – uhoh
    21 mins ago












  • 2




    $begingroup$
    Why can't the wheel be 1cm or even 1 mm in diameter? Maybe outside-the-box thinking is possible in answers as well? There are applications in spaceflight where high Isp is needed but at low thrust (e.g. anywhere solar-electric propulsion is used) so a system with high velocity but physically small scale might be interesting to explore for the interplanetary spacecraft.
    $endgroup$
    – uhoh
    40 mins ago







  • 1




    $begingroup$
    The speed at the rim is the radius times the angular speed. If you cut the radius by a factor of ten the angular speed has to increase by a factor of ten to keep the speed at the rim constant. I believe that brings us up to a hundred million radians per second. I look at those numbers and, well, I think we would probably have to put some work into it yet. It's pretty fast.
    $endgroup$
    – Greg
    26 mins ago










  • $begingroup$
    Okay now I'm going to think about this more myself, thanks!
    $endgroup$
    – uhoh
    21 mins ago







2




2




$begingroup$
Why can't the wheel be 1cm or even 1 mm in diameter? Maybe outside-the-box thinking is possible in answers as well? There are applications in spaceflight where high Isp is needed but at low thrust (e.g. anywhere solar-electric propulsion is used) so a system with high velocity but physically small scale might be interesting to explore for the interplanetary spacecraft.
$endgroup$
– uhoh
40 mins ago





$begingroup$
Why can't the wheel be 1cm or even 1 mm in diameter? Maybe outside-the-box thinking is possible in answers as well? There are applications in spaceflight where high Isp is needed but at low thrust (e.g. anywhere solar-electric propulsion is used) so a system with high velocity but physically small scale might be interesting to explore for the interplanetary spacecraft.
$endgroup$
– uhoh
40 mins ago





1




1




$begingroup$
The speed at the rim is the radius times the angular speed. If you cut the radius by a factor of ten the angular speed has to increase by a factor of ten to keep the speed at the rim constant. I believe that brings us up to a hundred million radians per second. I look at those numbers and, well, I think we would probably have to put some work into it yet. It's pretty fast.
$endgroup$
– Greg
26 mins ago




$begingroup$
The speed at the rim is the radius times the angular speed. If you cut the radius by a factor of ten the angular speed has to increase by a factor of ten to keep the speed at the rim constant. I believe that brings us up to a hundred million radians per second. I look at those numbers and, well, I think we would probably have to put some work into it yet. It's pretty fast.
$endgroup$
– Greg
26 mins ago












$begingroup$
Okay now I'm going to think about this more myself, thanks!
$endgroup$
– uhoh
21 mins ago




$begingroup$
Okay now I'm going to think about this more myself, thanks!
$endgroup$
– uhoh
21 mins ago

















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