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Magnifying glass in hyperbolic space

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Magnifying glass in hyperbolic space

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14

1

$begingroup$

My grandmother used to read with a magnifying glass. What (an ideal) magnifying glass does, is basically a homothety: it scales the picture by some factor. Now, in a hyperbolic space there is no such thing as homothety. So, what a person living in a hyperbolic space would do to improve poor vision?

geometry hyperbolic-geometry

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asked 9 hours ago

liaombroliaombro

359210

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add a comment | 

14

1

$begingroup$

My grandmother used to read with a magnifying glass. What (an ideal) magnifying glass does, is basically a homothety: it scales the picture by some factor. Now, in a hyperbolic space there is no such thing as homothety. So, what a person living in a hyperbolic space would do to improve poor vision?

geometry hyperbolic-geometry

share|cite|improve this question

asked 9 hours ago

liaombroliaombro

359210

$endgroup$

add a comment | 

$begingroup$

My grandmother used to read with a magnifying glass. What (an ideal) magnifying glass does, is basically a homothety: it scales the picture by some factor. Now, in a hyperbolic space there is no such thing as homothety. So, what a person living in a hyperbolic space would do to improve poor vision?

geometry hyperbolic-geometry

share|cite|improve this question

asked 9 hours ago

liaombroliaombro

359210

$endgroup$

share|cite|improve this question

asked 9 hours ago

liaombroliaombro

359210

share|cite|improve this question

asked 9 hours ago

liaombroliaombro

359210

asked 9 hours ago

liaombroliaombro

359210

asked 9 hours ago

liaombroliaombro

359210

2 Answers
2

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oldest

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11

$begingroup$

What you say will still be true: a magnifying glass will still scale the picture by some factor. Let us say that the scale factor is $ell > 1$.

The difference will be that the scaled picture will no longer be a picture of the old familiar hyperbolic space in which the sectional curvature is $-1$. Instead, it will be a picture of hyperbolic space with curvature $-frac1ell^2$; I'm using here that the units of curvature are basically $1/text(length)^2$.

So, for example, a really powerful magnifying glass with scale factor $ell >!!> 1$ will present a picture of a hyperbolic space whose curvature is nearly zero, being pretty much indistinguishable from Euclidean space.

share|cite|improve this answer

answered 9 hours ago

Lee MosherLee Mosher

50.9k33888

$endgroup$

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  I believe, your link currently does not work as intended
  $endgroup$
  – WorldSEnder
  3 hours ago
  

  
  
  
  

add a comment | 

3

$begingroup$

Even though a magnifying glass appears to scale the plane picture you're looking at uniformly, the actual image that forms on your retina lives on (the inside of) a sphere. So that actual image cannot actually be scaled uniformly.

Really, our immediate visual sensations lives not in our 3D space, but in the space of directions emanating from our eye. And that space is a sphere no matter whether the eye itself is embedded in hyperbolic or Euclidean space. More precisely, a sphere in hyperbolic space is always isometric to a sphere in Euclidean space; they just embed differently.

So a hyperbolic creature's retina might well have the same intrinsic geometry as ours does, and so it is completely conceivable that his magnifying glass might transform his visual sensation in the same (imperfect) way that our magnifying glasses do for our eyes.

share|cite|improve this answer

answered 5 hours ago

Henning MakholmHenning Makholm

242k17308550

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add a comment | 

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11

$begingroup$

What you say will still be true: a magnifying glass will still scale the picture by some factor. Let us say that the scale factor is $ell > 1$.

The difference will be that the scaled picture will no longer be a picture of the old familiar hyperbolic space in which the sectional curvature is $-1$. Instead, it will be a picture of hyperbolic space with curvature $-frac1ell^2$; I'm using here that the units of curvature are basically $1/text(length)^2$.

So, for example, a really powerful magnifying glass with scale factor $ell >!!> 1$ will present a picture of a hyperbolic space whose curvature is nearly zero, being pretty much indistinguishable from Euclidean space.

share|cite|improve this answer

answered 9 hours ago

Lee MosherLee Mosher

50.9k33888

$endgroup$

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  I believe, your link currently does not work as intended
  $endgroup$
  – WorldSEnder
  3 hours ago
  

  
  
  
  

add a comment | 

11

$begingroup$

What you say will still be true: a magnifying glass will still scale the picture by some factor. Let us say that the scale factor is $ell > 1$.

The difference will be that the scaled picture will no longer be a picture of the old familiar hyperbolic space in which the sectional curvature is $-1$. Instead, it will be a picture of hyperbolic space with curvature $-frac1ell^2$; I'm using here that the units of curvature are basically $1/text(length)^2$.

So, for example, a really powerful magnifying glass with scale factor $ell >!!> 1$ will present a picture of a hyperbolic space whose curvature is nearly zero, being pretty much indistinguishable from Euclidean space.

share|cite|improve this answer

answered 9 hours ago

Lee MosherLee Mosher

50.9k33888

$endgroup$

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  I believe, your link currently does not work as intended
  $endgroup$
  – WorldSEnder
  3 hours ago
  

  
  
  
  

add a comment | 

$begingroup$

What you say will still be true: a magnifying glass will still scale the picture by some factor. Let us say that the scale factor is $ell > 1$.

The difference will be that the scaled picture will no longer be a picture of the old familiar hyperbolic space in which the sectional curvature is $-1$. Instead, it will be a picture of hyperbolic space with curvature $-frac1ell^2$; I'm using here that the units of curvature are basically $1/text(length)^2$.

So, for example, a really powerful magnifying glass with scale factor $ell >!!> 1$ will present a picture of a hyperbolic space whose curvature is nearly zero, being pretty much indistinguishable from Euclidean space.

share|cite|improve this answer

answered 9 hours ago

Lee MosherLee Mosher

50.9k33888

$endgroup$

share|cite|improve this answer

answered 9 hours ago

Lee MosherLee Mosher

50.9k33888

answered 9 hours ago

Lee MosherLee Mosher

50.9k33888

answered 9 hours ago

Lee MosherLee Mosher

50.9k33888

3

$begingroup$

Even though a magnifying glass appears to scale the plane picture you're looking at uniformly, the actual image that forms on your retina lives on (the inside of) a sphere. So that actual image cannot actually be scaled uniformly.

Really, our immediate visual sensations lives not in our 3D space, but in the space of directions emanating from our eye. And that space is a sphere no matter whether the eye itself is embedded in hyperbolic or Euclidean space. More precisely, a sphere in hyperbolic space is always isometric to a sphere in Euclidean space; they just embed differently.

So a hyperbolic creature's retina might well have the same intrinsic geometry as ours does, and so it is completely conceivable that his magnifying glass might transform his visual sensation in the same (imperfect) way that our magnifying glasses do for our eyes.

share|cite|improve this answer

answered 5 hours ago

Henning MakholmHenning Makholm

242k17308550

$endgroup$

add a comment | 

3

$begingroup$

Even though a magnifying glass appears to scale the plane picture you're looking at uniformly, the actual image that forms on your retina lives on (the inside of) a sphere. So that actual image cannot actually be scaled uniformly.

Really, our immediate visual sensations lives not in our 3D space, but in the space of directions emanating from our eye. And that space is a sphere no matter whether the eye itself is embedded in hyperbolic or Euclidean space. More precisely, a sphere in hyperbolic space is always isometric to a sphere in Euclidean space; they just embed differently.

So a hyperbolic creature's retina might well have the same intrinsic geometry as ours does, and so it is completely conceivable that his magnifying glass might transform his visual sensation in the same (imperfect) way that our magnifying glasses do for our eyes.

share|cite|improve this answer

answered 5 hours ago

Henning MakholmHenning Makholm

242k17308550

$endgroup$

add a comment | 

$begingroup$

Even though a magnifying glass appears to scale the plane picture you're looking at uniformly, the actual image that forms on your retina lives on (the inside of) a sphere. So that actual image cannot actually be scaled uniformly.

Really, our immediate visual sensations lives not in our 3D space, but in the space of directions emanating from our eye. And that space is a sphere no matter whether the eye itself is embedded in hyperbolic or Euclidean space. More precisely, a sphere in hyperbolic space is always isometric to a sphere in Euclidean space; they just embed differently.

So a hyperbolic creature's retina might well have the same intrinsic geometry as ours does, and so it is completely conceivable that his magnifying glass might transform his visual sensation in the same (imperfect) way that our magnifying glasses do for our eyes.

share|cite|improve this answer

answered 5 hours ago

Henning MakholmHenning Makholm

242k17308550

$endgroup$

share|cite|improve this answer

answered 5 hours ago

Henning MakholmHenning Makholm

242k17308550

answered 5 hours ago

Henning MakholmHenning Makholm

242k17308550

answered 5 hours ago

Henning MakholmHenning Makholm

242k17308550