Mdtryhht

Let's suppose I want to find all .txt files and search for some string. I would do:

find ./ -type f -name "*.txt" -exec egrep -iH 'something' '' ;

What if I want to do a more complex filtering, like this:

egrep something file.txt | egrep somethingelse | egrep other

Inside find -exec? (or similar)

Please keep in mind that I'm searching for a solution that I could easily type when I need it. I know that this could be done with a few lines using a shell script, but that isn't what I'm looking for.

If you must do it from within find, you need to call a shell:

find ./ -type f -name "*.txt" -exec sh -c 'grep -EiH something "$1" | grep -E somethingelse | grep -E other' sh ;

Other alternatives include using xargs instead:

find ./ -type f -name "*.txt" | 
 xargs -I grep -EiH something | 
 grep -EiH somethingelse | 
 grep -EiH other

Or, much safer for arbitrary filenames (assuming your find supports -print0):

find ./ -type f -name "*.txt" -print0 | 
 xargs -0 grep -EiH something | 
 grep -Ei somethingelse | 
 grep -Ei other

Or, you could just use a shell loop instead:

find ./ -type f -name "*.txt" -print0 | 
 while IFS= read -d '' file; do 
 grep -Ei something "$file" | 
 grep -Ei somethingelse | 
 grep -Ei other
 done

You can put bash (or another shell) as your -exec command:

find -type -f -name "*.txt" -exec bash -c 'egrep -iH something "" | egrep somethingelse | egrep other' ;

One of the downsides of doing it this way is that it creates more potential for nested quoting issues as your commands get more complex. If you want to avoid that, you can break it out into a for-loop:

for i in $(find -type -f -name "*.txt"); do
 if egrep -iH something "$i" | egrep somethingelse | egrep other; then 
 echo "Found something: $i"
 fi
done