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Convert seconds to minutes
recursive search for a pattern, then for each match print out the specific SEQUENCE: line number, file name, and no file contentsExtract Values from simple html file via grep/awkStrategy to extract movies's name from this ununiform dataset?Print a line in stdout that matches an expression if the output contains another expressionUsing Awk to Search Bro Log for IPs/Keywords Found in Online Text FileHow to limit printed output based on number of occurences (AWK)stream editing tools: output what's scrapedText processing - Building a slurm topology.conf file from ibnetdiscover outputBash script command to search and highlight text in terminal bufferSumming minutes and seconds with awk
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music()
sed -e 's/position //'
bash awk
edited 6 hours ago
αғsнιη
17.1k103069
asked 7 hours ago
JoeJoe
173
add a comment |
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music()
sed -e 's/position //'
bash awk
edited 6 hours ago
αғsнιη
17.1k103069
asked 7 hours ago
JoeJoe
173
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
6 hours ago
Usingdate -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.
– bu5hman
6 hours ago
add a comment |
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music()
sed -e 's/position //'
bash awk
edited 6 hours ago
αғsнιη
17.1k103069
asked 7 hours ago
JoeJoe
173
I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.
Currently the relevant part of the function looks like this:
print_music()
sed -e 's/position //'
bash awk
bash awk
edited 6 hours ago
αғsнιη
17.1k103069
asked 7 hours ago
JoeJoe
173
edited 6 hours ago
αғsнιη
17.1k103069
asked 7 hours ago
JoeJoe
173
edited 6 hours ago
αғsнιη
17.1k103069
edited 6 hours ago
αғsнιη
17.1k103069
edited 6 hours ago
αғsнιη
17.1k103069
17.1k103069
asked 7 hours ago
JoeJoe
173
asked 7 hours ago
JoeJoe
173
asked 7 hours ago
JoeJoe
173
173
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
6 hours ago
Usingdate -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.
– bu5hman
6 hours ago
add a comment |
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
6 hours ago
Usingdate -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.
– bu5hman
6 hours ago
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
6 hours ago
Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
6 hours ago
Using
date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.– bu5hman
6 hours ago
Using
date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.– bu5hman
6 hours ago
add a comment |
1 Answer
1
active
oldest
votes
This will help you:
sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))";
$ sec2min 500
8:20
$ sec2min 1
0:01
answered 6 hours ago
glenn jackmanglenn jackman
53k573114
Thanks! That's working perfectly :)
– Joe
4 hours ago
Here's the same operation using a second iteration of awk ...awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
– RubberStamp
2 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This will help you:
sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))";
$ sec2min 500
8:20
$ sec2min 1
0:01
answered 6 hours ago
glenn jackmanglenn jackman
53k573114
Thanks! That's working perfectly :)
– Joe
4 hours ago
Here's the same operation using a second iteration of awk ...awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
– RubberStamp
2 hours ago
add a comment |
This will help you:
sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))";
$ sec2min 500
8:20
$ sec2min 1
0:01
answered 6 hours ago
glenn jackmanglenn jackman
53k573114
Thanks! That's working perfectly :)
– Joe
4 hours ago
Here's the same operation using a second iteration of awk ...awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
– RubberStamp
2 hours ago
add a comment |
This will help you:
sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))";
$ sec2min 500
8:20
$ sec2min 1
0:01
answered 6 hours ago
glenn jackmanglenn jackman
53k573114
This will help you:
sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))";
$ sec2min 500
8:20
$ sec2min 1
0:01
answered 6 hours ago
glenn jackmanglenn jackman
53k573114
answered 6 hours ago
glenn jackmanglenn jackman
53k573114
answered 6 hours ago
glenn jackmanglenn jackman
53k573114
answered 6 hours ago
glenn jackmanglenn jackman
53k573114
53k573114
Thanks! That's working perfectly :)
– Joe
4 hours ago
Here's the same operation using a second iteration of awk ...awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
– RubberStamp
2 hours ago
add a comment |
Thanks! That's working perfectly :)
– Joe
4 hours ago
Here's the same operation using a second iteration of awk ...awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'
– RubberStamp
2 hours ago
Thanks! That's working perfectly :)
– Joe
4 hours ago
Thanks! That's working perfectly :)
– Joe
4 hours ago
Here's the same operation using a second iteration of awk ...
awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'– RubberStamp
2 hours ago
Here's the same operation using a second iteration of awk ...
awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'– RubberStamp
2 hours ago
add a comment |
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Is this stackoverflow.com/q/13422743/4023950 what you need?
– αғsнιη
6 hours ago
Using
date -d@$variable +%-M%Sdoes the conversion but unlike @glenn jackman solution,datewill wrap to0:00at 3,600 secs.– bu5hman
6 hours ago