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Convert seconds to minutes


recursive search for a pattern, then for each match print out the specific SEQUENCE: line number, file name, and no file contentsExtract Values from simple html file via grep/awkStrategy to extract movies's name from this ununiform dataset?Print a line in stdout that matches an expression if the output contains another expressionUsing Awk to Search Bro Log for IPs/Keywords Found in Online Text FileHow to limit printed output based on number of occurences (AWK)stream editing tools: output what's scrapedText processing - Building a slurm topology.conf file from ibnetdiscover outputBash script command to search and highlight text in terminal bufferSumming minutes and seconds with awk













1















I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.



Currently the relevant part of the function looks like this:



print_music()
 sed -e 's/position //'





bash awk







share|improve this question
























  • Is this stackoverflow.com/q/13422743/4023950 what you need?

    – αғsнιη
    6 hours ago











  • Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

    – bu5hman
    6 hours ago
















1















I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.



Currently the relevant part of the function looks like this:



print_music()
 sed -e 's/position //'





bash awk







share|improve this question
























  • Is this stackoverflow.com/q/13422743/4023950 what you need?

    – αғsнιη
    6 hours ago











  • Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

    – bu5hman
    6 hours ago














1












1








1


0






I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.



Currently the relevant part of the function looks like this:



print_music()
 sed -e 's/position //'





bash awk







share|improve this question
















I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.



Currently the relevant part of the function looks like this:



print_music()
 sed -e 's/position //'





bash awk




bash awk






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 6 hours ago









αғsнιη

17.1k103069




17.1k103069










asked 7 hours ago









JoeJoe

173




173












  • Is this stackoverflow.com/q/13422743/4023950 what you need?

    – αғsнιη
    6 hours ago











  • Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

    – bu5hman
    6 hours ago


















  • Is this stackoverflow.com/q/13422743/4023950 what you need?

    – αғsнιη
    6 hours ago











  • Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

    – bu5hman
    6 hours ago

















Is this stackoverflow.com/q/13422743/4023950 what you need?

– αғsнιη
6 hours ago





Is this stackoverflow.com/q/13422743/4023950 what you need?

– αғsнιη
6 hours ago













Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

– bu5hman
6 hours ago






Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.

– bu5hman
6 hours ago











1 Answer
1






active

oldest

votes


















5














This will help you:



sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; 




$ sec2min 500
8:20
$ sec2min 1
0:01





share|improve this answer























  • Thanks! That's working perfectly :)

    – Joe
    4 hours ago











  • Here's the same operation using a second iteration of awk ... awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'

    – RubberStamp
    2 hours ago











Your Answer








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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









5














This will help you:



sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; 




$ sec2min 500
8:20
$ sec2min 1
0:01





share|improve this answer























  • Thanks! That's working perfectly :)

    – Joe
    4 hours ago











  • Here's the same operation using a second iteration of awk ... awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'

    – RubberStamp
    2 hours ago















5














This will help you:



sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; 




$ sec2min 500
8:20
$ sec2min 1
0:01





share|improve this answer























  • Thanks! That's working perfectly :)

    – Joe
    4 hours ago











  • Here's the same operation using a second iteration of awk ... awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'

    – RubberStamp
    2 hours ago













5












5








5







This will help you:



sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; 




$ sec2min 500
8:20
$ sec2min 1
0:01





share|improve this answer













This will help you:



sec2min() printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; 




$ sec2min 500
8:20
$ sec2min 1
0:01






share|improve this answer












share|improve this answer



share|improve this answer










answered 6 hours ago









glenn jackmanglenn jackman

53k573114




53k573114












  • Thanks! That's working perfectly :)

    – Joe
    4 hours ago











  • Here's the same operation using a second iteration of awk ... awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'

    – RubberStamp
    2 hours ago

















  • Thanks! That's working perfectly :)

    – Joe
    4 hours ago











  • Here's the same operation using a second iteration of awk ... awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'

    – RubberStamp
    2 hours ago
















Thanks! That's working perfectly :)

– Joe
4 hours ago





Thanks! That's working perfectly :)

– Joe
4 hours ago













Here's the same operation using a second iteration of awk ... awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'

– RubberStamp
2 hours ago





Here's the same operation using a second iteration of awk ... awk ' min = ($1 / 60)-(($1 % 60)*1/60) ; sec = $1 % 60 ; print min,":",sec'

– RubberStamp
2 hours ago

















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