Relationship between Gromov-Witten and Taubes' Gromov invariant The 2019 Stack Overflow Developer Survey Results Are InNegative Gromov-Witten invariantsGromov-Witten invariants counting curves passing through two pointsQuestion on Ionel and Parker's paper: Relative Gromov Witten InvariantsAre genus zero Gromov Witten Invariants on Del-Pezzo surfaces enumerative?How does one define Moduli spaces in Symplectic Geometry and naively interpret higher genus GW Invariants?Is the complex structure on a del-Pezzo surface a regular complex structure?How to understand Taubes' moduli space of holomorphic curves?What is the mirror of symplectic field theory?Is there any known relationship between sutured contact homology and Legendrian contact homology?Gromov-Witten invariants and the mod 2 spectral flow

Relationship between Gromov-Witten and Taubes' Gromov invariant



The 2019 Stack Overflow Developer Survey Results Are InNegative Gromov-Witten invariantsGromov-Witten invariants counting curves passing through two pointsQuestion on Ionel and Parker's paper: Relative Gromov Witten InvariantsAre genus zero Gromov Witten Invariants on Del-Pezzo surfaces enumerative?How does one define Moduli spaces in Symplectic Geometry and naively interpret higher genus GW Invariants?Is the complex structure on a del-Pezzo surface a regular complex structure?How to understand Taubes' moduli space of holomorphic curves?What is the mirror of symplectic field theory?Is there any known relationship between sutured contact homology and Legendrian contact homology?Gromov-Witten invariants and the mod 2 spectral flow










5












$begingroup$


Fix a compact, symplectic four-manifold ($X$, $omega$).



Recall Taubes' Gromov invariant is a certain integer-valued function on $H^2(X; mathbbZ)$ defined by weighted counts of pseudoholomorphic curves in $X$. In particular, this count combines curves of any genus.



On the other hand, the Gromov-Witten invariants for a fixed genus $g$ and homology class $A in H_2(X; mathbbZ)$ are (very roughly) integers derived from the "fundamental class" of the moduli space $mathcalM_g^A(X)$ of pseudoholomorphic maps from a surface of genus $g$ into $X$ representing the class $A$.



Is there any sort of relationship, conjectural or otherwise, between these two invariants that is stronger than "they both count holomorphic curves"? Of course, this would require looking at Gromov-Witten invariants for any genus $g$. I personally don't understand the best way to define these for genus $g > 0$. I do understand that Zinger has a construction for $g = 1$ that is a bit more refined than looking at the entire moduli space.










share|cite|improve this question











$endgroup$











  • $begingroup$
    With respect to Ionel-Parker's paper (which is the answer), note that GT allows a single curve to be disconnected with "whatever" genus whereas GW considers a connected curve of fixed genus, so you should expect that their generating series are the same (roughly speaking).
    $endgroup$
    – Chris Gerig
    23 mins ago
















5












$begingroup$


Fix a compact, symplectic four-manifold ($X$, $omega$).



Recall Taubes' Gromov invariant is a certain integer-valued function on $H^2(X; mathbbZ)$ defined by weighted counts of pseudoholomorphic curves in $X$. In particular, this count combines curves of any genus.



On the other hand, the Gromov-Witten invariants for a fixed genus $g$ and homology class $A in H_2(X; mathbbZ)$ are (very roughly) integers derived from the "fundamental class" of the moduli space $mathcalM_g^A(X)$ of pseudoholomorphic maps from a surface of genus $g$ into $X$ representing the class $A$.



Is there any sort of relationship, conjectural or otherwise, between these two invariants that is stronger than "they both count holomorphic curves"? Of course, this would require looking at Gromov-Witten invariants for any genus $g$. I personally don't understand the best way to define these for genus $g > 0$. I do understand that Zinger has a construction for $g = 1$ that is a bit more refined than looking at the entire moduli space.










share|cite|improve this question











$endgroup$











  • $begingroup$
    With respect to Ionel-Parker's paper (which is the answer), note that GT allows a single curve to be disconnected with "whatever" genus whereas GW considers a connected curve of fixed genus, so you should expect that their generating series are the same (roughly speaking).
    $endgroup$
    – Chris Gerig
    23 mins ago














5












5








5


1



$begingroup$


Fix a compact, symplectic four-manifold ($X$, $omega$).



Recall Taubes' Gromov invariant is a certain integer-valued function on $H^2(X; mathbbZ)$ defined by weighted counts of pseudoholomorphic curves in $X$. In particular, this count combines curves of any genus.



On the other hand, the Gromov-Witten invariants for a fixed genus $g$ and homology class $A in H_2(X; mathbbZ)$ are (very roughly) integers derived from the "fundamental class" of the moduli space $mathcalM_g^A(X)$ of pseudoholomorphic maps from a surface of genus $g$ into $X$ representing the class $A$.



Is there any sort of relationship, conjectural or otherwise, between these two invariants that is stronger than "they both count holomorphic curves"? Of course, this would require looking at Gromov-Witten invariants for any genus $g$. I personally don't understand the best way to define these for genus $g > 0$. I do understand that Zinger has a construction for $g = 1$ that is a bit more refined than looking at the entire moduli space.










share|cite|improve this question











$endgroup$




Fix a compact, symplectic four-manifold ($X$, $omega$).



Recall Taubes' Gromov invariant is a certain integer-valued function on $H^2(X; mathbbZ)$ defined by weighted counts of pseudoholomorphic curves in $X$. In particular, this count combines curves of any genus.



On the other hand, the Gromov-Witten invariants for a fixed genus $g$ and homology class $A in H_2(X; mathbbZ)$ are (very roughly) integers derived from the "fundamental class" of the moduli space $mathcalM_g^A(X)$ of pseudoholomorphic maps from a surface of genus $g$ into $X$ representing the class $A$.



Is there any sort of relationship, conjectural or otherwise, between these two invariants that is stronger than "they both count holomorphic curves"? Of course, this would require looking at Gromov-Witten invariants for any genus $g$. I personally don't understand the best way to define these for genus $g > 0$. I do understand that Zinger has a construction for $g = 1$ that is a bit more refined than looking at the entire moduli space.







sg.symplectic-geometry symplectic-topology






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edited 5 hours ago









Ali Taghavi

23852085




23852085










asked 6 hours ago









Rohil PrasadRohil Prasad

445411




445411











  • $begingroup$
    With respect to Ionel-Parker's paper (which is the answer), note that GT allows a single curve to be disconnected with "whatever" genus whereas GW considers a connected curve of fixed genus, so you should expect that their generating series are the same (roughly speaking).
    $endgroup$
    – Chris Gerig
    23 mins ago

















  • $begingroup$
    With respect to Ionel-Parker's paper (which is the answer), note that GT allows a single curve to be disconnected with "whatever" genus whereas GW considers a connected curve of fixed genus, so you should expect that their generating series are the same (roughly speaking).
    $endgroup$
    – Chris Gerig
    23 mins ago
















$begingroup$
With respect to Ionel-Parker's paper (which is the answer), note that GT allows a single curve to be disconnected with "whatever" genus whereas GW considers a connected curve of fixed genus, so you should expect that their generating series are the same (roughly speaking).
$endgroup$
– Chris Gerig
23 mins ago





$begingroup$
With respect to Ionel-Parker's paper (which is the answer), note that GT allows a single curve to be disconnected with "whatever" genus whereas GW considers a connected curve of fixed genus, so you should expect that their generating series are the same (roughly speaking).
$endgroup$
– Chris Gerig
23 mins ago











1 Answer
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$begingroup$

Ionel and Parker worked out the relationship between Taubes' Gromov invariant and the usual Gromov--Witten invariants (which they refer to as "Ruan--Tian invariants") in this paper:
https://arxiv.org/abs/alg-geom/9702008






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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    5












    $begingroup$

    Ionel and Parker worked out the relationship between Taubes' Gromov invariant and the usual Gromov--Witten invariants (which they refer to as "Ruan--Tian invariants") in this paper:
    https://arxiv.org/abs/alg-geom/9702008






    share|cite|improve this answer









    $endgroup$

















      5












      $begingroup$

      Ionel and Parker worked out the relationship between Taubes' Gromov invariant and the usual Gromov--Witten invariants (which they refer to as "Ruan--Tian invariants") in this paper:
      https://arxiv.org/abs/alg-geom/9702008






      share|cite|improve this answer









      $endgroup$















        5












        5








        5





        $begingroup$

        Ionel and Parker worked out the relationship between Taubes' Gromov invariant and the usual Gromov--Witten invariants (which they refer to as "Ruan--Tian invariants") in this paper:
        https://arxiv.org/abs/alg-geom/9702008






        share|cite|improve this answer









        $endgroup$



        Ionel and Parker worked out the relationship between Taubes' Gromov invariant and the usual Gromov--Witten invariants (which they refer to as "Ruan--Tian invariants") in this paper:
        https://arxiv.org/abs/alg-geom/9702008







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 5 hours ago









        John PardonJohn Pardon

        9,361331106




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