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How to color a curve


Changing the background color of the framed region of a plotHow to do the log scale plot for ListContourPlotContourPlot color problemsListPlot will not color markers in accordance with my color functionHow to color the exterior of a region in a `RegionPlot`?How to color a particular contour line in a ContourPlot and obtain the area surrounded?Color consistency in Plot3D with 2D projectionPlotting the outer region contourPlotting displacement values over defined regionWhat is the logarithmic color scales?(not logarithmic axes)













2












$begingroup$


How does one color the interior of the elongated circular region in the following figure:



ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]









share|improve this question











$endgroup$
















    2












    $begingroup$


    How does one color the interior of the elongated circular region in the following figure:



    ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]









    share|improve this question











    $endgroup$














      2












      2








      2


      0



      $begingroup$


      How does one color the interior of the elongated circular region in the following figure:



      ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]









      share|improve this question











      $endgroup$




      How does one color the interior of the elongated circular region in the following figure:



      ContourPlot[y^2 - x (x - 1)(x - 3) == 0, x, -2, 7, y, -4, 3]






      plotting






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 57 mins ago









      J. M. is slightly pensive

      98.4k10307466




      98.4k10307466










      asked 4 hours ago









      Sara yaqobSara yaqob

      134




      134




















          2 Answers
          2






          active

          oldest

          votes


















          1












          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]


          enter image description here






          share|improve this answer









          $endgroup$












          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            4 hours ago


















          2












          $begingroup$

          I am assuming you mean that you would like to color the round object in the plot (not really a circle):



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$








          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            4 hours ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            4 hours ago










          • $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            3 hours ago










          Your Answer





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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1












          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]


          enter image description here






          share|improve this answer









          $endgroup$












          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            4 hours ago















          1












          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]


          enter image description here






          share|improve this answer









          $endgroup$












          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            4 hours ago













          1












          1








          1





          $begingroup$

          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]


          enter image description here






          share|improve this answer









          $endgroup$



          Try without "==0"



          ContourPlot[y^2 - x (x - 1) (x - 3), x, -2, 7, y, -4, 3]


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 4 hours ago









          XminerXminer

          30918




          30918











          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            4 hours ago
















          • $begingroup$
            But I need only the curve not the surface
            $endgroup$
            – Sara yaqob
            4 hours ago















          $begingroup$
          But I need only the curve not the surface
          $endgroup$
          – Sara yaqob
          4 hours ago




          $begingroup$
          But I need only the curve not the surface
          $endgroup$
          – Sara yaqob
          4 hours ago











          2












          $begingroup$

          I am assuming you mean that you would like to color the round object in the plot (not really a circle):



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$








          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            4 hours ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            4 hours ago










          • $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            3 hours ago















          2












          $begingroup$

          I am assuming you mean that you would like to color the round object in the plot (not really a circle):



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$








          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            4 hours ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            4 hours ago










          • $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            3 hours ago













          2












          2








          2





          $begingroup$

          I am assuming you mean that you would like to color the round object in the plot (not really a circle):



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here






          share|improve this answer











          $endgroup$



          I am assuming you mean that you would like to color the round object in the plot (not really a circle):



          Your plot



          c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, x, -2, 7, y, -4, 3]


          enter image description here
          The region you would like colored



          R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, x, -2, 7, y, -4, 3]


          enter image description here



          Both plotted together



          Show[c, R]


          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 4 hours ago

























          answered 4 hours ago









          mjwmjw

          9779




          9779







          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            4 hours ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            4 hours ago










          • $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            3 hours ago












          • 1




            $begingroup$
            Thank you so so much sir. That's what I need.
            $endgroup$
            – Sara yaqob
            4 hours ago










          • $begingroup$
            @Sara, You are welcome!
            $endgroup$
            – mjw
            4 hours ago










          • $begingroup$
            @Sarayaqob you mistakenly accepted my answer
            $endgroup$
            – Xminer
            3 hours ago







          1




          1




          $begingroup$
          Thank you so so much sir. That's what I need.
          $endgroup$
          – Sara yaqob
          4 hours ago




          $begingroup$
          Thank you so so much sir. That's what I need.
          $endgroup$
          – Sara yaqob
          4 hours ago












          $begingroup$
          @Sara, You are welcome!
          $endgroup$
          – mjw
          4 hours ago




          $begingroup$
          @Sara, You are welcome!
          $endgroup$
          – mjw
          4 hours ago












          $begingroup$
          @Sarayaqob you mistakenly accepted my answer
          $endgroup$
          – Xminer
          3 hours ago




          $begingroup$
          @Sarayaqob you mistakenly accepted my answer
          $endgroup$
          – Xminer
          3 hours ago

















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