draw a pulley system Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: placing a line (transformed into a sinusoidal shape) parallel to an edge connecting nodesAbsolutely position arrow headHow to define the default vertical distance between nodes?Computing the rectangle encompassing a node and a pointUse of overlay command in a graphTikZ: Drawing an arc from an intersection to an intersectionGetting the proper shading within a circle - a bit of litographyAdjusting edge alignment and positioning of fitted nodeRelative transparency in TikZ?Line up nested tikz enviroments or how to get rid of them

Why are current probes so expensive?

New Order #6: Easter Egg

Fit odd number of triplets in a measure?

Does the universe have a fixed centre of mass?

Can I cut the hair of a conjured korred with a blade made of precious material to harvest that material from the korred?

calculator's angle answer for trig ratios that can work in more than 1 quadrant on the unit circle

Does the main washing effect of soap come from foam?

As a dual citizen, my US passport will expire one day after traveling to the US. Will this work?

How does TikZ render an arc?

Where did Ptolemy compare the Earth to the distance of fixed stars?

One-one communication

Is honorific speech ever used in the first person?

Which types of prepositional phrase is "toward its employees" in Philosophy guiding the organization's policies towards its employees is not bad?

The test team as an enemy of development? And how can this be avoided?

Improvising over quartal voicings

Understanding piped commands in GNU/Linux

Why did Bronn offer to be Tyrion Lannister's champion in trial by combat?

.bashrc alias for a command with fixed second parameter

Does a random sequence of vectors span a Hilbert space?

An isoperimetric-type inequality inside a cube

How do Java 8 default methods hеlp with lambdas?

Flight departed from the gate 5 min before scheduled departure time. Refund options

How to make triangles with rounded sides and corners? (squircle with 3 sides)

3D Masyu - A Die



draw a pulley system



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)TikZ: placing a line (transformed into a sinusoidal shape) parallel to an edge connecting nodesAbsolutely position arrow headHow to define the default vertical distance between nodes?Computing the rectangle encompassing a node and a pointUse of overlay command in a graphTikZ: Drawing an arc from an intersection to an intersectionGetting the proper shading within a circle - a bit of litographyAdjusting edge alignment and positioning of fitted nodeRelative transparency in TikZ?Line up nested tikz enviroments or how to get rid of them










2















enter image description here
I need to draw a pulley system as in the figure. Can you help?



 begintikzpicture
fill[pattern=north east lines] (-3,0) rectangle (3,.3);
draw(-3,0)--(3,0);
draw(-2.5,0)--(-2.5,-2.4);
draw(2.5,0)--(2.5,-1);

draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);
draw[fill=white] (0,-3) circle (.153);

draw
(2.5,-1) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (0,-2.75) coordinate (c) node[above right]
pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
angle=a--b--c;

draw
(0,-2.75) coordinate (a) node[right]
-- (0,-3) coordinate (b) node[left]
-- (-2.5,-2.4) coordinate (c) node[above right]
pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
angle=a--b--c;
draw[dashed] (0,-3)--(0,-1);
draw[fill=white] (-2.5,-2.4) circle (.3);
draw[fill=white] (2.5,-1) circle (.3);

draw[fill=white] (0,-3) circle (.153);


endtikzpicture









share|improve this question




























    2















    enter image description here
    I need to draw a pulley system as in the figure. Can you help?



     begintikzpicture
    fill[pattern=north east lines] (-3,0) rectangle (3,.3);
    draw(-3,0)--(3,0);
    draw(-2.5,0)--(-2.5,-2.4);
    draw(2.5,0)--(2.5,-1);

    draw[fill=white] (-2.5,-2.4) circle (.3);
    draw[fill=white] (2.5,-1) circle (.3);
    draw[fill=white] (0,-3) circle (.153);

    draw
    (2.5,-1) coordinate (a) node[right]
    -- (0,-3) coordinate (b) node[left]
    -- (0,-2.75) coordinate (c) node[above right]
    pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
    angle=a--b--c;

    draw
    (0,-2.75) coordinate (a) node[right]
    -- (0,-3) coordinate (b) node[left]
    -- (-2.5,-2.4) coordinate (c) node[above right]
    pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
    angle=a--b--c;
    draw[dashed] (0,-3)--(0,-1);
    draw[fill=white] (-2.5,-2.4) circle (.3);
    draw[fill=white] (2.5,-1) circle (.3);

    draw[fill=white] (0,-3) circle (.153);


    endtikzpicture









    share|improve this question


























      2












      2








      2


      0






      enter image description here
      I need to draw a pulley system as in the figure. Can you help?



       begintikzpicture
      fill[pattern=north east lines] (-3,0) rectangle (3,.3);
      draw(-3,0)--(3,0);
      draw(-2.5,0)--(-2.5,-2.4);
      draw(2.5,0)--(2.5,-1);

      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);
      draw[fill=white] (0,-3) circle (.153);

      draw
      (2.5,-1) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (0,-2.75) coordinate (c) node[above right]
      pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
      angle=a--b--c;

      draw
      (0,-2.75) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (-2.5,-2.4) coordinate (c) node[above right]
      pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
      angle=a--b--c;
      draw[dashed] (0,-3)--(0,-1);
      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);

      draw[fill=white] (0,-3) circle (.153);


      endtikzpicture









      share|improve this question
















      enter image description here
      I need to draw a pulley system as in the figure. Can you help?



       begintikzpicture
      fill[pattern=north east lines] (-3,0) rectangle (3,.3);
      draw(-3,0)--(3,0);
      draw(-2.5,0)--(-2.5,-2.4);
      draw(2.5,0)--(2.5,-1);

      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);
      draw[fill=white] (0,-3) circle (.153);

      draw
      (2.5,-1) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (0,-2.75) coordinate (c) node[above right]
      pic["$beta$", draw=orange, <->, angle eccentricity=1.2172, angle radius=.51cm]
      angle=a--b--c;

      draw
      (0,-2.75) coordinate (a) node[right]
      -- (0,-3) coordinate (b) node[left]
      -- (-2.5,-2.4) coordinate (c) node[above right]
      pic["$alpha$", draw=orange, <->, angle eccentricity=.72172, angle radius=.751cm]
      angle=a--b--c;
      draw[dashed] (0,-3)--(0,-1);
      draw[fill=white] (-2.5,-2.4) circle (.3);
      draw[fill=white] (2.5,-1) circle (.3);

      draw[fill=white] (0,-3) circle (.153);


      endtikzpicture






      tikz-pgf






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 2 hours ago







      Thumbolt

















      asked 3 hours ago









      ThumboltThumbolt

      1,521822




      1,521822




















          1 Answer
          1






          active

          oldest

          votes


















          4














          In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



          documentclass[tikz,border=3.14mm]standalone
          usetikzlibrarypatterns,calc,angles,quotes
          begindocument
          begintikzpicture
          fill[pattern=north east lines] (-3,0) rectangle (3,.3);
          beginscope[thick]
          draw(-3,0)--(3,0);

          path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
          (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
          (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
          draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
          draw[dashed] (M) -- (0,-1)coordinate (M1);
          draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
          let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
          arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
          draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
          let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
          arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
          endscope
          path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
          pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
          endtikzpicture
          enddocument


          enter image description here






          share|improve this answer

























            Your Answer








            StackExchange.ready(function()
            var channelOptions =
            tags: "".split(" "),
            id: "85"
            ;
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function()
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled)
            StackExchange.using("snippets", function()
            createEditor();
            );

            else
            createEditor();

            );

            function createEditor()
            StackExchange.prepareEditor(
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: false,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: null,
            bindNavPrevention: true,
            postfix: "",
            imageUploader:
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            ,
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            );



            );













            draft saved

            draft discarded


















            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f485982%2fdraw-a-pulley-system%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4














            In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



            documentclass[tikz,border=3.14mm]standalone
            usetikzlibrarypatterns,calc,angles,quotes
            begindocument
            begintikzpicture
            fill[pattern=north east lines] (-3,0) rectangle (3,.3);
            beginscope[thick]
            draw(-3,0)--(3,0);

            path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
            (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
            (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
            draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
            draw[dashed] (M) -- (0,-1)coordinate (M1);
            draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
            let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
            arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
            draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
            let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
            arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
            endscope
            path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
            pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
            endtikzpicture
            enddocument


            enter image description here






            share|improve this answer





























              4














              In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



              documentclass[tikz,border=3.14mm]standalone
              usetikzlibrarypatterns,calc,angles,quotes
              begindocument
              begintikzpicture
              fill[pattern=north east lines] (-3,0) rectangle (3,.3);
              beginscope[thick]
              draw(-3,0)--(3,0);

              path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
              (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
              (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
              draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
              draw[dashed] (M) -- (0,-1)coordinate (M1);
              draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
              let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
              arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
              draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
              let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
              arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
              endscope
              path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
              pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
              endtikzpicture
              enddocument


              enter image description here






              share|improve this answer



























                4












                4








                4







                In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



                documentclass[tikz,border=3.14mm]standalone
                usetikzlibrarypatterns,calc,angles,quotes
                begindocument
                begintikzpicture
                fill[pattern=north east lines] (-3,0) rectangle (3,.3);
                beginscope[thick]
                draw(-3,0)--(3,0);

                path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
                (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
                (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
                draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
                draw[dashed] (M) -- (0,-1)coordinate (M1);
                draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
                let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
                draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
                let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
                endscope
                path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
                pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
                endtikzpicture
                enddocument


                enter image description here






                share|improve this answer















                In order to compute the tangents it is advantageous to make the circles nodes and to use tangent cs:, which comes with calc. And the angles can be conveniently drawn with the angles library, where quotes makes it somewhat simpler to add alpha and beta.



                documentclass[tikz,border=3.14mm]standalone
                usetikzlibrarypatterns,calc,angles,quotes
                begindocument
                begintikzpicture
                fill[pattern=north east lines] (-3,0) rectangle (3,.3);
                beginscope[thick]
                draw(-3,0)--(3,0);

                path (-2.5,-2.4) node[circle,draw,inner sep=.3cm] (L)
                (2.5,-1) node[circle,draw,inner sep=.3cm] (R)
                (0,-3) node[circle,draw,inner sep=.153cm,label=below:$m$] (M);
                draw (L.north) -- (L.north|-0,0) (R.north) -- (R.north|-0,0);
                draw[dashed] (M) -- (0,-1)coordinate (M1);
                draw (M) -- (tangent cs:node=L,point=(M.center),solution=1) coordinate (L1)
                let p1=($(L1)-(L.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:180:n2) -- ++(0,-1.5) node[below,draw]$m_1$;
                draw (M) -- (tangent cs:node=R,point=(M.center),solution=2) coordinate (R1)
                let p1=($(R1)-(R.center)$),n1=atan2(y1,x1),n2=veclen(y1,x1) in
                arc(n1:00:n2) -- ++(0,-1.5) node[below,draw]$m_2$;
                endscope
                path pic [draw,angle radius=0.5cm,"$alpha$",angle eccentricity=1.5] angle = M1--M--L1
                pic [draw,angle radius=0.7cm,"$beta$",angle eccentricity=1.5] angle = R1--M--M1 ;
                endtikzpicture
                enddocument


                enter image description here







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 2 hours ago

























                answered 2 hours ago









                marmotmarmot

                120k6156292




                120k6156292



























                    draft saved

                    draft discarded
















































                    Thanks for contributing an answer to TeX - LaTeX Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid


                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.

                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function ()
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f485982%2fdraw-a-pulley-system%23new-answer', 'question_page');

                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    How to create a command for the “strange m” symbol in latex? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)How do you make your own symbol when Detexify fails?Writing bold small caps with mathpazo packageplus-minus symbol with parenthesis around the minus signGreek character in Beamer document titleHow to create dashed right arrow over symbol?Currency symbol: Turkish LiraDouble prec as a single symbol?Plus Sign Too Big; How to Call adfbullet?Is there a TeX macro for three-legged pi?How do I get my integral-like symbol to align like the integral?How to selectively substitute a letter with another symbol representing the same letterHow do I generate a less than symbol and vertical bar that are the same height?

                    Българска екзархия Съдържание История | Български екзарси | Вижте също | Външни препратки | Литература | Бележки | НавигацияУстав за управлението на българската екзархия. Цариград, 1870Слово на Ловешкия митрополит Иларион при откриването на Българския народен събор в Цариград на 23. II. 1870 г.Българската правда и гръцката кривда. От С. М. (= Софийски Мелетий). Цариград, 1872Предстоятели на Българската екзархияПодмененият ВеликденИнформационна агенция „Фокус“Димитър Ризов. Българите в техните исторически, етнографически и политически граници (Атлас съдържащ 40 карти). Berlin, Königliche Hoflithographie, Hof-Buch- und -Steindruckerei Wilhelm Greve, 1917Report of the International Commission to Inquire into the Causes and Conduct of the Balkan Wars

                    Чепеларе Съдържание География | История | Население | Спортни и природни забележителности | Културни и исторически обекти | Религии | Обществени институции | Известни личности | Редовни събития | Галерия | Източници | Литература | Външни препратки | Навигация41°43′23.99″ с. ш. 24°41′09.99″ и. д. / 41.723333° с. ш. 24.686111° и. д.*ЧепелареЧепеларски Linux fest 2002Начало на Зимен сезон 2005/06Национални хайдушки празници „Капитан Петко Войвода“Град ЧепелареЧепеларе – народният ски курортbgrod.orgwww.terranatura.hit.bgСправка за населението на гр. Исперих, общ. Исперих, обл. РазградМузей на родопския карстМузей на спорта и скитеЧепеларебългарскибългарскианглийскитукИстория на градаСки писти в ЧепелареВремето в ЧепелареРадио и телевизия в ЧепелареЧепеларе мами с родопски чар и добри пистиЕвтин туризъм и снежни атракции в ЧепелареМестоположениеИнформация и снимки от музея на родопския карст3D панорами от ЧепелареЧепелареррр