Mdtryhht

let arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];

console.log(Array.from(new Set(arr)));

let arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];

let res = arr
 .join(',')
 .replace(/(b,w+b)(?=.*1)/ig, '')
 .split(',')
 .map(Number);

console.log(res);

let arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];

let obj = arr.reduce((acc, val) => Object.assign(acc, 
 [val]: val
), );

console.log(Object.values(obj));

let arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];
let finalResult = arr.filter((e, i, a) => a.indexOf(e) == i).sort(function(a, b)return a - b);
console.log(finalResult);

let arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];
let finalResult = arr.filter((e, i, a) => a.filter(f => f == e).length == 1).sort(function(a, b)return a - b);
console.log(finalResult);

let arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];
let res = [...new Set(arr)]
console.log(res)

let arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];
//to get the object with count of each number in array.
let obj = arr.reduce((ac,a) => 
 //check if number doesnot occur before then set its count to 1
 if(!ac[a]) ac[a] = 1;
 //if number is already in object increase its count
 else ac[a]++;
 return ac;
,)
//Using reduce on all the keys of object means all numbers.
let res = Object.keys(obj).reduce((ac,a) => 
 //check if count of current number 'a' is `1` in the above object then add it into array
 if(obj[a] === 1) ac.push(+a)
 return ac;
,[])
console.log(res)

var array = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10],
 result1,
 result2;

array.sort((a, b) => a - b);

result1 = array.filter((v, i, a) => a[i - 1] !== v);
result2 = array.filter((v, i, a) => a[i - 1] !== v && a[i + 1] !== v);

console.log(...result1);
console.log(...result2)

let arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];
let unique = new Set();
let repeated = Array.from(arr.reduce((acc, curr) => 
	acc.has(curr) ? unique.delete(curr) : acc.add(curr) && unique.add(curr);
	return acc;
, new Set()));

console.log(Array.from(unique))
console.log(repeated)

const arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];
const hash = arr.reduce((a, c) => (a[c] = (a[c] || 0) + 1, a), );

// [1, 2, 3, 4, 5, 8, 9, 10];
const finalResultOne = Object.keys(hash);

// [1, 9, 10];
const finalResultTwo = Object.keys(hash).filter(k => hash[k] === 1);

console.log('finalResultOne:', ...finalResultOne);
console.log('finalResultTwo:', ...finalResultTwo);

let arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];

const build = ar => 
 const mapObj = ar.reduce((acc, e) => 
 acc.has(e) ? acc.set(e, true) : acc.set(e, false)
 return acc
 , new Map())
 
 return function(hasDup = true) 
 if(hasDup) return [...mapObj.keys()]
 else return [...mapObj].filter(([key, val]) => !val).map(([k, v])=> k)
 


const getArr = build(arr)

console.log(getArr())
console.log(getArr(false))

const arr = [1, 2, 4, 2, 3, 3, 4, 5, 5, 5, 8, 8, 9, 10];

const count = (arr, e) => arr.filter(n => n == e).length

const unique = arr => arr.filter(e => count(arr, e) < 2)

console.log(unique(arr));