3 doors, three guards, one stone Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Two doors with two guards - one lies, one tells the truthLying, truthful and merciless guards (variation)Two doors with three guards - one lies, one tells the truth, and one is unreliableWhich is the door to heavenWhy does this answer to “two doors with two guards” work?The last question to the guardsClassic 2 Guards But With 3 Doors InsteadClassic two guards and two doorsMonty's LabyrinthPossible answer to the Heaven Hell Door riddle
Limit for e and 1/e
What did Darwin mean by 'squib' here?
Geometric mean and geometric standard deviation
Classification of bundles, Postnikov towers, obstruction theory, local coefficients
Need a suitable toxic chemical for a murder plot in my novel
When communicating altitude with a '9' in it, should it be pronounced "nine hundred" or "niner hundred"?
If I can make up priors, why can't I make up posteriors?
Interesting examples of non-locally compact topological groups
Windows 10: How to Lock (not sleep) laptop on lid close?
Am I ethically obligated to go into work on an off day if the reason is sudden?
What is the electric potential inside a point charge?
The following signatures were invalid: EXPKEYSIG 1397BC53640DB551
Writing Thesis: Copying from published papers
Cold is to Refrigerator as warm is to?
Statistical model of ligand substitution
Array/tabular for long multiplication
What items from the Roman-age tech-level could be used to deter all creatures from entering a small area?
Passing functions in C++
Is above average number of years spent on PhD considered a red flag in future academia or industry positions?
Unable to start mainnet node docker container
Autumning in love
Is there folklore associating late breastfeeding with low intelligence and/or gullibility?
Why is there no army of Iron-Mans in the MCU?
How did the aliens keep their waters separated?
3 doors, three guards, one stone
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Two doors with two guards - one lies, one tells the truthLying, truthful and merciless guards (variation)Two doors with three guards - one lies, one tells the truth, and one is unreliableWhich is the door to heavenWhy does this answer to “two doors with two guards” work?The last question to the guardsClassic 2 Guards But With 3 Doors InsteadClassic two guards and two doorsMonty's LabyrinthPossible answer to the Heaven Hell Door riddle
$begingroup$
You are in a room with three doors. You find out, that behind two of these doors, the darkest pit of hell is waiting for you to make a mistake. The other door, leads to heaven, where you, obviously, want to get.
Each door is guarded by a guard:
- Michael, who tells truth with 75% chance;
- Vlad, who lies with 90% chance;
- John, who lies with 70% chance.
You do not know who is who, or which door he guards. You may ask each guard 2 questions max, but no more than 4 questions in total, because those guys do not like long conversations.
The other thing you have is a magic stone, that can be used only once. This stone makes the event with the lowest chance to occur.
What is the easiest way, which gives you the most chances to go to heaven?
Hint: the solution lies on the surface.
logical-deduction probability liars
New contributor
$endgroup$
add a comment |
$begingroup$
You are in a room with three doors. You find out, that behind two of these doors, the darkest pit of hell is waiting for you to make a mistake. The other door, leads to heaven, where you, obviously, want to get.
Each door is guarded by a guard:
- Michael, who tells truth with 75% chance;
- Vlad, who lies with 90% chance;
- John, who lies with 70% chance.
You do not know who is who, or which door he guards. You may ask each guard 2 questions max, but no more than 4 questions in total, because those guys do not like long conversations.
The other thing you have is a magic stone, that can be used only once. This stone makes the event with the lowest chance to occur.
What is the easiest way, which gives you the most chances to go to heaven?
Hint: the solution lies on the surface.
logical-deduction probability liars
New contributor
$endgroup$
$begingroup$
Are only yes/no questions allowed?
$endgroup$
– EKons
6 hours ago
$begingroup$
@EKons, you may ask them whatever question you want, but there is no guard, who always tells the truth, which makes it difficult to find the correct door using qs like "What's 1 + 1"
$endgroup$
– Andrii Chumakov
6 hours ago
$begingroup$
So, if you ask Michael "Who are you?" without using the stone and he decides to lie (or you use the stone, so he'll lie) could he say either "Vlad" or "John"?
$endgroup$
– EKons
6 hours ago
$begingroup$
@EKons, yes, that's what would happen in this case
$endgroup$
– Andrii Chumakov
6 hours ago
add a comment |
$begingroup$
You are in a room with three doors. You find out, that behind two of these doors, the darkest pit of hell is waiting for you to make a mistake. The other door, leads to heaven, where you, obviously, want to get.
Each door is guarded by a guard:
- Michael, who tells truth with 75% chance;
- Vlad, who lies with 90% chance;
- John, who lies with 70% chance.
You do not know who is who, or which door he guards. You may ask each guard 2 questions max, but no more than 4 questions in total, because those guys do not like long conversations.
The other thing you have is a magic stone, that can be used only once. This stone makes the event with the lowest chance to occur.
What is the easiest way, which gives you the most chances to go to heaven?
Hint: the solution lies on the surface.
logical-deduction probability liars
New contributor
$endgroup$
You are in a room with three doors. You find out, that behind two of these doors, the darkest pit of hell is waiting for you to make a mistake. The other door, leads to heaven, where you, obviously, want to get.
Each door is guarded by a guard:
- Michael, who tells truth with 75% chance;
- Vlad, who lies with 90% chance;
- John, who lies with 70% chance.
You do not know who is who, or which door he guards. You may ask each guard 2 questions max, but no more than 4 questions in total, because those guys do not like long conversations.
The other thing you have is a magic stone, that can be used only once. This stone makes the event with the lowest chance to occur.
What is the easiest way, which gives you the most chances to go to heaven?
Hint: the solution lies on the surface.
logical-deduction probability liars
logical-deduction probability liars
New contributor
New contributor
edited 5 hours ago
Andrii Chumakov
New contributor
asked 8 hours ago
Andrii ChumakovAndrii Chumakov
415
415
New contributor
New contributor
$begingroup$
Are only yes/no questions allowed?
$endgroup$
– EKons
6 hours ago
$begingroup$
@EKons, you may ask them whatever question you want, but there is no guard, who always tells the truth, which makes it difficult to find the correct door using qs like "What's 1 + 1"
$endgroup$
– Andrii Chumakov
6 hours ago
$begingroup$
So, if you ask Michael "Who are you?" without using the stone and he decides to lie (or you use the stone, so he'll lie) could he say either "Vlad" or "John"?
$endgroup$
– EKons
6 hours ago
$begingroup$
@EKons, yes, that's what would happen in this case
$endgroup$
– Andrii Chumakov
6 hours ago
add a comment |
$begingroup$
Are only yes/no questions allowed?
$endgroup$
– EKons
6 hours ago
$begingroup$
@EKons, you may ask them whatever question you want, but there is no guard, who always tells the truth, which makes it difficult to find the correct door using qs like "What's 1 + 1"
$endgroup$
– Andrii Chumakov
6 hours ago
$begingroup$
So, if you ask Michael "Who are you?" without using the stone and he decides to lie (or you use the stone, so he'll lie) could he say either "Vlad" or "John"?
$endgroup$
– EKons
6 hours ago
$begingroup$
@EKons, yes, that's what would happen in this case
$endgroup$
– Andrii Chumakov
6 hours ago
$begingroup$
Are only yes/no questions allowed?
$endgroup$
– EKons
6 hours ago
$begingroup$
Are only yes/no questions allowed?
$endgroup$
– EKons
6 hours ago
$begingroup$
@EKons, you may ask them whatever question you want, but there is no guard, who always tells the truth, which makes it difficult to find the correct door using qs like "What's 1 + 1"
$endgroup$
– Andrii Chumakov
6 hours ago
$begingroup$
@EKons, you may ask them whatever question you want, but there is no guard, who always tells the truth, which makes it difficult to find the correct door using qs like "What's 1 + 1"
$endgroup$
– Andrii Chumakov
6 hours ago
$begingroup$
So, if you ask Michael "Who are you?" without using the stone and he decides to lie (or you use the stone, so he'll lie) could he say either "Vlad" or "John"?
$endgroup$
– EKons
6 hours ago
$begingroup$
So, if you ask Michael "Who are you?" without using the stone and he decides to lie (or you use the stone, so he'll lie) could he say either "Vlad" or "John"?
$endgroup$
– EKons
6 hours ago
$begingroup$
@EKons, yes, that's what would happen in this case
$endgroup$
– Andrii Chumakov
6 hours ago
$begingroup$
@EKons, yes, that's what would happen in this case
$endgroup$
– Andrii Chumakov
6 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
No questions are required!
Use the magic stone, then try one of the doors. It's less likely to get the right door (1/3) than one of the wrong ones (2/3), so you'll end up in the right place
$endgroup$
add a comment |
$begingroup$
I'd go with this:
Go to any guard, use the magic stone, and ask the question:
Which of the remaining two guards will lie?
If it is Michel
Since he will lie, so he'll say
"None"
If it is Vlad
He will point to one guard, who will be John, so the other would be Michel
If it is John
He will point to one guard, who will be Vlad, so the other would be Michel
So
I'll identify Michel who will say the truth 75% of times, and ask him the second question
"Which door leads to heaven"
It is a 75% chance that he'll tell the truth
This isn't an optimal solution, so work is still in progress
$endgroup$
1
$begingroup$
Not quite. Without the magic stone all the guards a basically random. If you ask one of them “which guard will lie”, they will not have an answer for you. It’s impossible to tell when someone will lie or tell the truth. That’s like asking “when will the next die roll land on a 3”. Whether the guard is lying or telling the truth, he will not know the answer to that.
$endgroup$
– Amorydai
2 hours ago
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "559"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Andrii Chumakov is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f81764%2f3-doors-three-guards-one-stone%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
No questions are required!
Use the magic stone, then try one of the doors. It's less likely to get the right door (1/3) than one of the wrong ones (2/3), so you'll end up in the right place
$endgroup$
add a comment |
$begingroup$
No questions are required!
Use the magic stone, then try one of the doors. It's less likely to get the right door (1/3) than one of the wrong ones (2/3), so you'll end up in the right place
$endgroup$
add a comment |
$begingroup$
No questions are required!
Use the magic stone, then try one of the doors. It's less likely to get the right door (1/3) than one of the wrong ones (2/3), so you'll end up in the right place
$endgroup$
No questions are required!
Use the magic stone, then try one of the doors. It's less likely to get the right door (1/3) than one of the wrong ones (2/3), so you'll end up in the right place
answered 4 hours ago
StephenTGStephenTG
1,5121921
1,5121921
add a comment |
add a comment |
$begingroup$
I'd go with this:
Go to any guard, use the magic stone, and ask the question:
Which of the remaining two guards will lie?
If it is Michel
Since he will lie, so he'll say
"None"
If it is Vlad
He will point to one guard, who will be John, so the other would be Michel
If it is John
He will point to one guard, who will be Vlad, so the other would be Michel
So
I'll identify Michel who will say the truth 75% of times, and ask him the second question
"Which door leads to heaven"
It is a 75% chance that he'll tell the truth
This isn't an optimal solution, so work is still in progress
$endgroup$
1
$begingroup$
Not quite. Without the magic stone all the guards a basically random. If you ask one of them “which guard will lie”, they will not have an answer for you. It’s impossible to tell when someone will lie or tell the truth. That’s like asking “when will the next die roll land on a 3”. Whether the guard is lying or telling the truth, he will not know the answer to that.
$endgroup$
– Amorydai
2 hours ago
add a comment |
$begingroup$
I'd go with this:
Go to any guard, use the magic stone, and ask the question:
Which of the remaining two guards will lie?
If it is Michel
Since he will lie, so he'll say
"None"
If it is Vlad
He will point to one guard, who will be John, so the other would be Michel
If it is John
He will point to one guard, who will be Vlad, so the other would be Michel
So
I'll identify Michel who will say the truth 75% of times, and ask him the second question
"Which door leads to heaven"
It is a 75% chance that he'll tell the truth
This isn't an optimal solution, so work is still in progress
$endgroup$
1
$begingroup$
Not quite. Without the magic stone all the guards a basically random. If you ask one of them “which guard will lie”, they will not have an answer for you. It’s impossible to tell when someone will lie or tell the truth. That’s like asking “when will the next die roll land on a 3”. Whether the guard is lying or telling the truth, he will not know the answer to that.
$endgroup$
– Amorydai
2 hours ago
add a comment |
$begingroup$
I'd go with this:
Go to any guard, use the magic stone, and ask the question:
Which of the remaining two guards will lie?
If it is Michel
Since he will lie, so he'll say
"None"
If it is Vlad
He will point to one guard, who will be John, so the other would be Michel
If it is John
He will point to one guard, who will be Vlad, so the other would be Michel
So
I'll identify Michel who will say the truth 75% of times, and ask him the second question
"Which door leads to heaven"
It is a 75% chance that he'll tell the truth
This isn't an optimal solution, so work is still in progress
$endgroup$
I'd go with this:
Go to any guard, use the magic stone, and ask the question:
Which of the remaining two guards will lie?
If it is Michel
Since he will lie, so he'll say
"None"
If it is Vlad
He will point to one guard, who will be John, so the other would be Michel
If it is John
He will point to one guard, who will be Vlad, so the other would be Michel
So
I'll identify Michel who will say the truth 75% of times, and ask him the second question
"Which door leads to heaven"
It is a 75% chance that he'll tell the truth
This isn't an optimal solution, so work is still in progress
answered 4 hours ago
AkariAkari
647223
647223
1
$begingroup$
Not quite. Without the magic stone all the guards a basically random. If you ask one of them “which guard will lie”, they will not have an answer for you. It’s impossible to tell when someone will lie or tell the truth. That’s like asking “when will the next die roll land on a 3”. Whether the guard is lying or telling the truth, he will not know the answer to that.
$endgroup$
– Amorydai
2 hours ago
add a comment |
1
$begingroup$
Not quite. Without the magic stone all the guards a basically random. If you ask one of them “which guard will lie”, they will not have an answer for you. It’s impossible to tell when someone will lie or tell the truth. That’s like asking “when will the next die roll land on a 3”. Whether the guard is lying or telling the truth, he will not know the answer to that.
$endgroup$
– Amorydai
2 hours ago
1
1
$begingroup$
Not quite. Without the magic stone all the guards a basically random. If you ask one of them “which guard will lie”, they will not have an answer for you. It’s impossible to tell when someone will lie or tell the truth. That’s like asking “when will the next die roll land on a 3”. Whether the guard is lying or telling the truth, he will not know the answer to that.
$endgroup$
– Amorydai
2 hours ago
$begingroup$
Not quite. Without the magic stone all the guards a basically random. If you ask one of them “which guard will lie”, they will not have an answer for you. It’s impossible to tell when someone will lie or tell the truth. That’s like asking “when will the next die roll land on a 3”. Whether the guard is lying or telling the truth, he will not know the answer to that.
$endgroup$
– Amorydai
2 hours ago
add a comment |
Andrii Chumakov is a new contributor. Be nice, and check out our Code of Conduct.
Andrii Chumakov is a new contributor. Be nice, and check out our Code of Conduct.
Andrii Chumakov is a new contributor. Be nice, and check out our Code of Conduct.
Andrii Chumakov is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f81764%2f3-doors-three-guards-one-stone%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Are only yes/no questions allowed?
$endgroup$
– EKons
6 hours ago
$begingroup$
@EKons, you may ask them whatever question you want, but there is no guard, who always tells the truth, which makes it difficult to find the correct door using qs like "What's 1 + 1"
$endgroup$
– Andrii Chumakov
6 hours ago
$begingroup$
So, if you ask Michael "Who are you?" without using the stone and he decides to lie (or you use the stone, so he'll lie) could he say either "Vlad" or "John"?
$endgroup$
– EKons
6 hours ago
$begingroup$
@EKons, yes, that's what would happen in this case
$endgroup$
– Andrii Chumakov
6 hours ago