Can anything be seen from the center of the Boötes void? How dark would it be? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) 2019 Moderator Election Q&A - Question CollectionDo all the individual stars that we can see in the night sky belong to Milky Way?What does the sky look like to human eyes from orbit?Names, maps for Milky Way dust clouds? (Dark Cloud Constellations)How much of sky can be seen on a typical night from a mid-latitude location?View of the Sun from Voyager 1How deep is the Great Red Spot?How to track the visual path of a LEO satellite as seen from the groundCan the Earth be seen to transit the sun from the outer planets?Establishing true (ie present) positions of cosmic bodiesIf someone from another part of the observable universe had their own Hubble Telescope, would they see different things than we did?How is it possible to see stars-light, from stars millions of light years apart with the naked eye?

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Can anything be seen from the center of the Boötes void? How dark would it be?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
2019 Moderator Election Q&A - Question CollectionDo all the individual stars that we can see in the night sky belong to Milky Way?What does the sky look like to human eyes from orbit?Names, maps for Milky Way dust clouds? (Dark Cloud Constellations)How much of sky can be seen on a typical night from a mid-latitude location?View of the Sun from Voyager 1How deep is the Great Red Spot?How to track the visual path of a LEO satellite as seen from the groundCan the Earth be seen to transit the sun from the outer planets?Establishing true (ie present) positions of cosmic bodiesIf someone from another part of the observable universe had their own Hubble Telescope, would they see different things than we did?How is it possible to see stars-light, from stars millions of light years apart with the naked eye?










18












$begingroup$


Let's say I was at the very center of the enormous Boötes void, way out in deep, deep space. What could I see with the naked eye? I assume I could see no individual stars, but could I resolve any galaxies? If I gazed in the direction of a super-cluster of galaxies would it seem brighter than other directions? How dark would it be compared to, say, the far side of the moon when it is a full moon on earth?



I am told there are, in fact, a few galaxies in the void. So let's say I pick a spot in the void that is as far from any of those galaxies as possible.










share|cite|improve this question











$endgroup$











  • $begingroup$
    The Bootes void has some galaxies in it, and I don't know if it has much of a centre. IMO this needs to be more specific about the conditions.
    $endgroup$
    – JMac
    8 hours ago






  • 3




    $begingroup$
    Let's pick the spot that is furthest from any galaxy.
    $endgroup$
    – Paul Young
    8 hours ago










  • $begingroup$
    @PaulYoung so you're saying "if there's a bright center to the Universe, you're at the [point] it's farthest from"?
    $endgroup$
    – MikeTheLiar
    1 hour ago















18












$begingroup$


Let's say I was at the very center of the enormous Boötes void, way out in deep, deep space. What could I see with the naked eye? I assume I could see no individual stars, but could I resolve any galaxies? If I gazed in the direction of a super-cluster of galaxies would it seem brighter than other directions? How dark would it be compared to, say, the far side of the moon when it is a full moon on earth?



I am told there are, in fact, a few galaxies in the void. So let's say I pick a spot in the void that is as far from any of those galaxies as possible.










share|cite|improve this question











$endgroup$











  • $begingroup$
    The Bootes void has some galaxies in it, and I don't know if it has much of a centre. IMO this needs to be more specific about the conditions.
    $endgroup$
    – JMac
    8 hours ago






  • 3




    $begingroup$
    Let's pick the spot that is furthest from any galaxy.
    $endgroup$
    – Paul Young
    8 hours ago










  • $begingroup$
    @PaulYoung so you're saying "if there's a bright center to the Universe, you're at the [point] it's farthest from"?
    $endgroup$
    – MikeTheLiar
    1 hour ago













18












18








18





$begingroup$


Let's say I was at the very center of the enormous Boötes void, way out in deep, deep space. What could I see with the naked eye? I assume I could see no individual stars, but could I resolve any galaxies? If I gazed in the direction of a super-cluster of galaxies would it seem brighter than other directions? How dark would it be compared to, say, the far side of the moon when it is a full moon on earth?



I am told there are, in fact, a few galaxies in the void. So let's say I pick a spot in the void that is as far from any of those galaxies as possible.










share|cite|improve this question











$endgroup$




Let's say I was at the very center of the enormous Boötes void, way out in deep, deep space. What could I see with the naked eye? I assume I could see no individual stars, but could I resolve any galaxies? If I gazed in the direction of a super-cluster of galaxies would it seem brighter than other directions? How dark would it be compared to, say, the far side of the moon when it is a full moon on earth?



I am told there are, in fact, a few galaxies in the void. So let's say I pick a spot in the void that is as far from any of those galaxies as possible.







astronomy






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 2 hours ago









costrom

314128




314128










asked 8 hours ago









Paul YoungPaul Young

1,314116




1,314116











  • $begingroup$
    The Bootes void has some galaxies in it, and I don't know if it has much of a centre. IMO this needs to be more specific about the conditions.
    $endgroup$
    – JMac
    8 hours ago






  • 3




    $begingroup$
    Let's pick the spot that is furthest from any galaxy.
    $endgroup$
    – Paul Young
    8 hours ago










  • $begingroup$
    @PaulYoung so you're saying "if there's a bright center to the Universe, you're at the [point] it's farthest from"?
    $endgroup$
    – MikeTheLiar
    1 hour ago
















  • $begingroup$
    The Bootes void has some galaxies in it, and I don't know if it has much of a centre. IMO this needs to be more specific about the conditions.
    $endgroup$
    – JMac
    8 hours ago






  • 3




    $begingroup$
    Let's pick the spot that is furthest from any galaxy.
    $endgroup$
    – Paul Young
    8 hours ago










  • $begingroup$
    @PaulYoung so you're saying "if there's a bright center to the Universe, you're at the [point] it's farthest from"?
    $endgroup$
    – MikeTheLiar
    1 hour ago















$begingroup$
The Bootes void has some galaxies in it, and I don't know if it has much of a centre. IMO this needs to be more specific about the conditions.
$endgroup$
– JMac
8 hours ago




$begingroup$
The Bootes void has some galaxies in it, and I don't know if it has much of a centre. IMO this needs to be more specific about the conditions.
$endgroup$
– JMac
8 hours ago




3




3




$begingroup$
Let's pick the spot that is furthest from any galaxy.
$endgroup$
– Paul Young
8 hours ago




$begingroup$
Let's pick the spot that is furthest from any galaxy.
$endgroup$
– Paul Young
8 hours ago












$begingroup$
@PaulYoung so you're saying "if there's a bright center to the Universe, you're at the [point] it's farthest from"?
$endgroup$
– MikeTheLiar
1 hour ago




$begingroup$
@PaulYoung so you're saying "if there's a bright center to the Universe, you're at the [point] it's farthest from"?
$endgroup$
– MikeTheLiar
1 hour ago










2 Answers
2






active

oldest

votes


















18












$begingroup$

The number density of galaxies in a void is typically 1/10 the average in the Universe. In this astronomy.SE post, I estimate the number density of galaxies of magnitude $M=-17$ or brighter in the Boötes Void to be $n sim 0.004,mathrmMpc^-3$, or $10^-4,mathrmMlyr^-3$ (i.e. "per cubic mega-light-year"). Hence, the typical distance to a galaxy from a random point in the Boötes Void is
$$
d = left( frac34pi n right)^1/3 simeq 13,mathrmMlyr.
$$



That distance corresponds to a distance modulus of $mu simeq 28$, so the apparent magnitude of the galaxy would be
$$
m = M + mu simeq 11.
$$

Typically, humans cannot see objects darker than $m simeq 6.5$ (the magnitude scale is backwards, so darker means "larger values than 6.5"), although some have claimed to be able to see $msimeq8$ — still an order of magnitude brighter than the $m=11$ estimated above. Moreover, this threshold assumes point sources, whereas a galaxy has its brightness smeared out over a quite large area, lowering its surface brightness significantly!$^dagger$



Hence, you would be floating in complete darkness.$^ddagger$




$^dagger$For instance, the Andromeda galaxy has an apparent magnitude of $m=3.44$ which, if its light were concentrated in a point, would make it easily visibly even under light-polluted conditions.



$^ddagger$Your eye might be able to detect individual photons, at stated in Árpád Szendrei's answer, but that hardly counts as "seeing anything".






share|cite|improve this answer











$endgroup$








  • 4




    $begingroup$
    Well, that's an utterly terrifying concept to imagine. Thanks to everyone for making me aware of it, I am going to go lie down now
    $endgroup$
    – llama
    4 hours ago






  • 5




    $begingroup$
    @llama Luckily, the terrifying scenario would be over in a minute, after which you'd die from asphyxia.
    $endgroup$
    – pela
    4 hours ago


















3












$begingroup$

In fact you would see only individual stars. Like on Earth, you can only see individual stars, and no galaxies with the naked eye. Why? Because galaxies are too dim as a whole.



Now, if you would just float in empty space in the void you would be better off then on Earth. It is because here on Earth there is some light pollution.



But in the void, there is basically no light pollution, so you could see even single photons arriving from far away giant stars.



And yes, the human eye is able to detect even single photons.



By the way, all the stars that you can see with the naked eye from Earth are from the Milky Way. But again, that is too because of the light pollution and because our night sky even if there would be no light pollution here on Earth would be filled with brighter start from the Milky way. Our eyes would get used to that, and the start from other galaxies would just appear too dim to see.



Now on the dark side of the moon it would be a little different, but only that there is no light pollution like on Earth. Still, from the dark side of the Moon you could still only see stars from the Milky way.



Now in the void in your case, I think it is different. It is so dark and void, that even a single photon coming from a far away large star would be visible to our eyes that get used to the darkness.



Please see here:



Do all the individual stars that we can see in the night sky belong to Milky Way?






share|cite|improve this answer









$endgroup$








  • 1




    $begingroup$
    You can see Andromeda with the naked eye, under optimal conditions. It's mag +3.44. Sagittarius Dwarf Spheroidal Galaxy and M33 should also be visible
    $endgroup$
    – CSM
    3 hours ago











Your Answer








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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









18












$begingroup$

The number density of galaxies in a void is typically 1/10 the average in the Universe. In this astronomy.SE post, I estimate the number density of galaxies of magnitude $M=-17$ or brighter in the Boötes Void to be $n sim 0.004,mathrmMpc^-3$, or $10^-4,mathrmMlyr^-3$ (i.e. "per cubic mega-light-year"). Hence, the typical distance to a galaxy from a random point in the Boötes Void is
$$
d = left( frac34pi n right)^1/3 simeq 13,mathrmMlyr.
$$



That distance corresponds to a distance modulus of $mu simeq 28$, so the apparent magnitude of the galaxy would be
$$
m = M + mu simeq 11.
$$

Typically, humans cannot see objects darker than $m simeq 6.5$ (the magnitude scale is backwards, so darker means "larger values than 6.5"), although some have claimed to be able to see $msimeq8$ — still an order of magnitude brighter than the $m=11$ estimated above. Moreover, this threshold assumes point sources, whereas a galaxy has its brightness smeared out over a quite large area, lowering its surface brightness significantly!$^dagger$



Hence, you would be floating in complete darkness.$^ddagger$




$^dagger$For instance, the Andromeda galaxy has an apparent magnitude of $m=3.44$ which, if its light were concentrated in a point, would make it easily visibly even under light-polluted conditions.



$^ddagger$Your eye might be able to detect individual photons, at stated in Árpád Szendrei's answer, but that hardly counts as "seeing anything".






share|cite|improve this answer











$endgroup$








  • 4




    $begingroup$
    Well, that's an utterly terrifying concept to imagine. Thanks to everyone for making me aware of it, I am going to go lie down now
    $endgroup$
    – llama
    4 hours ago






  • 5




    $begingroup$
    @llama Luckily, the terrifying scenario would be over in a minute, after which you'd die from asphyxia.
    $endgroup$
    – pela
    4 hours ago















18












$begingroup$

The number density of galaxies in a void is typically 1/10 the average in the Universe. In this astronomy.SE post, I estimate the number density of galaxies of magnitude $M=-17$ or brighter in the Boötes Void to be $n sim 0.004,mathrmMpc^-3$, or $10^-4,mathrmMlyr^-3$ (i.e. "per cubic mega-light-year"). Hence, the typical distance to a galaxy from a random point in the Boötes Void is
$$
d = left( frac34pi n right)^1/3 simeq 13,mathrmMlyr.
$$



That distance corresponds to a distance modulus of $mu simeq 28$, so the apparent magnitude of the galaxy would be
$$
m = M + mu simeq 11.
$$

Typically, humans cannot see objects darker than $m simeq 6.5$ (the magnitude scale is backwards, so darker means "larger values than 6.5"), although some have claimed to be able to see $msimeq8$ — still an order of magnitude brighter than the $m=11$ estimated above. Moreover, this threshold assumes point sources, whereas a galaxy has its brightness smeared out over a quite large area, lowering its surface brightness significantly!$^dagger$



Hence, you would be floating in complete darkness.$^ddagger$




$^dagger$For instance, the Andromeda galaxy has an apparent magnitude of $m=3.44$ which, if its light were concentrated in a point, would make it easily visibly even under light-polluted conditions.



$^ddagger$Your eye might be able to detect individual photons, at stated in Árpád Szendrei's answer, but that hardly counts as "seeing anything".






share|cite|improve this answer











$endgroup$








  • 4




    $begingroup$
    Well, that's an utterly terrifying concept to imagine. Thanks to everyone for making me aware of it, I am going to go lie down now
    $endgroup$
    – llama
    4 hours ago






  • 5




    $begingroup$
    @llama Luckily, the terrifying scenario would be over in a minute, after which you'd die from asphyxia.
    $endgroup$
    – pela
    4 hours ago













18












18








18





$begingroup$

The number density of galaxies in a void is typically 1/10 the average in the Universe. In this astronomy.SE post, I estimate the number density of galaxies of magnitude $M=-17$ or brighter in the Boötes Void to be $n sim 0.004,mathrmMpc^-3$, or $10^-4,mathrmMlyr^-3$ (i.e. "per cubic mega-light-year"). Hence, the typical distance to a galaxy from a random point in the Boötes Void is
$$
d = left( frac34pi n right)^1/3 simeq 13,mathrmMlyr.
$$



That distance corresponds to a distance modulus of $mu simeq 28$, so the apparent magnitude of the galaxy would be
$$
m = M + mu simeq 11.
$$

Typically, humans cannot see objects darker than $m simeq 6.5$ (the magnitude scale is backwards, so darker means "larger values than 6.5"), although some have claimed to be able to see $msimeq8$ — still an order of magnitude brighter than the $m=11$ estimated above. Moreover, this threshold assumes point sources, whereas a galaxy has its brightness smeared out over a quite large area, lowering its surface brightness significantly!$^dagger$



Hence, you would be floating in complete darkness.$^ddagger$




$^dagger$For instance, the Andromeda galaxy has an apparent magnitude of $m=3.44$ which, if its light were concentrated in a point, would make it easily visibly even under light-polluted conditions.



$^ddagger$Your eye might be able to detect individual photons, at stated in Árpád Szendrei's answer, but that hardly counts as "seeing anything".






share|cite|improve this answer











$endgroup$



The number density of galaxies in a void is typically 1/10 the average in the Universe. In this astronomy.SE post, I estimate the number density of galaxies of magnitude $M=-17$ or brighter in the Boötes Void to be $n sim 0.004,mathrmMpc^-3$, or $10^-4,mathrmMlyr^-3$ (i.e. "per cubic mega-light-year"). Hence, the typical distance to a galaxy from a random point in the Boötes Void is
$$
d = left( frac34pi n right)^1/3 simeq 13,mathrmMlyr.
$$



That distance corresponds to a distance modulus of $mu simeq 28$, so the apparent magnitude of the galaxy would be
$$
m = M + mu simeq 11.
$$

Typically, humans cannot see objects darker than $m simeq 6.5$ (the magnitude scale is backwards, so darker means "larger values than 6.5"), although some have claimed to be able to see $msimeq8$ — still an order of magnitude brighter than the $m=11$ estimated above. Moreover, this threshold assumes point sources, whereas a galaxy has its brightness smeared out over a quite large area, lowering its surface brightness significantly!$^dagger$



Hence, you would be floating in complete darkness.$^ddagger$




$^dagger$For instance, the Andromeda galaxy has an apparent magnitude of $m=3.44$ which, if its light were concentrated in a point, would make it easily visibly even under light-polluted conditions.



$^ddagger$Your eye might be able to detect individual photons, at stated in Árpád Szendrei's answer, but that hardly counts as "seeing anything".







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited 6 hours ago

























answered 6 hours ago









pelapela

8,2272030




8,2272030







  • 4




    $begingroup$
    Well, that's an utterly terrifying concept to imagine. Thanks to everyone for making me aware of it, I am going to go lie down now
    $endgroup$
    – llama
    4 hours ago






  • 5




    $begingroup$
    @llama Luckily, the terrifying scenario would be over in a minute, after which you'd die from asphyxia.
    $endgroup$
    – pela
    4 hours ago












  • 4




    $begingroup$
    Well, that's an utterly terrifying concept to imagine. Thanks to everyone for making me aware of it, I am going to go lie down now
    $endgroup$
    – llama
    4 hours ago






  • 5




    $begingroup$
    @llama Luckily, the terrifying scenario would be over in a minute, after which you'd die from asphyxia.
    $endgroup$
    – pela
    4 hours ago







4




4




$begingroup$
Well, that's an utterly terrifying concept to imagine. Thanks to everyone for making me aware of it, I am going to go lie down now
$endgroup$
– llama
4 hours ago




$begingroup$
Well, that's an utterly terrifying concept to imagine. Thanks to everyone for making me aware of it, I am going to go lie down now
$endgroup$
– llama
4 hours ago




5




5




$begingroup$
@llama Luckily, the terrifying scenario would be over in a minute, after which you'd die from asphyxia.
$endgroup$
– pela
4 hours ago




$begingroup$
@llama Luckily, the terrifying scenario would be over in a minute, after which you'd die from asphyxia.
$endgroup$
– pela
4 hours ago











3












$begingroup$

In fact you would see only individual stars. Like on Earth, you can only see individual stars, and no galaxies with the naked eye. Why? Because galaxies are too dim as a whole.



Now, if you would just float in empty space in the void you would be better off then on Earth. It is because here on Earth there is some light pollution.



But in the void, there is basically no light pollution, so you could see even single photons arriving from far away giant stars.



And yes, the human eye is able to detect even single photons.



By the way, all the stars that you can see with the naked eye from Earth are from the Milky Way. But again, that is too because of the light pollution and because our night sky even if there would be no light pollution here on Earth would be filled with brighter start from the Milky way. Our eyes would get used to that, and the start from other galaxies would just appear too dim to see.



Now on the dark side of the moon it would be a little different, but only that there is no light pollution like on Earth. Still, from the dark side of the Moon you could still only see stars from the Milky way.



Now in the void in your case, I think it is different. It is so dark and void, that even a single photon coming from a far away large star would be visible to our eyes that get used to the darkness.



Please see here:



Do all the individual stars that we can see in the night sky belong to Milky Way?






share|cite|improve this answer









$endgroup$








  • 1




    $begingroup$
    You can see Andromeda with the naked eye, under optimal conditions. It's mag +3.44. Sagittarius Dwarf Spheroidal Galaxy and M33 should also be visible
    $endgroup$
    – CSM
    3 hours ago















3












$begingroup$

In fact you would see only individual stars. Like on Earth, you can only see individual stars, and no galaxies with the naked eye. Why? Because galaxies are too dim as a whole.



Now, if you would just float in empty space in the void you would be better off then on Earth. It is because here on Earth there is some light pollution.



But in the void, there is basically no light pollution, so you could see even single photons arriving from far away giant stars.



And yes, the human eye is able to detect even single photons.



By the way, all the stars that you can see with the naked eye from Earth are from the Milky Way. But again, that is too because of the light pollution and because our night sky even if there would be no light pollution here on Earth would be filled with brighter start from the Milky way. Our eyes would get used to that, and the start from other galaxies would just appear too dim to see.



Now on the dark side of the moon it would be a little different, but only that there is no light pollution like on Earth. Still, from the dark side of the Moon you could still only see stars from the Milky way.



Now in the void in your case, I think it is different. It is so dark and void, that even a single photon coming from a far away large star would be visible to our eyes that get used to the darkness.



Please see here:



Do all the individual stars that we can see in the night sky belong to Milky Way?






share|cite|improve this answer









$endgroup$








  • 1




    $begingroup$
    You can see Andromeda with the naked eye, under optimal conditions. It's mag +3.44. Sagittarius Dwarf Spheroidal Galaxy and M33 should also be visible
    $endgroup$
    – CSM
    3 hours ago













3












3








3





$begingroup$

In fact you would see only individual stars. Like on Earth, you can only see individual stars, and no galaxies with the naked eye. Why? Because galaxies are too dim as a whole.



Now, if you would just float in empty space in the void you would be better off then on Earth. It is because here on Earth there is some light pollution.



But in the void, there is basically no light pollution, so you could see even single photons arriving from far away giant stars.



And yes, the human eye is able to detect even single photons.



By the way, all the stars that you can see with the naked eye from Earth are from the Milky Way. But again, that is too because of the light pollution and because our night sky even if there would be no light pollution here on Earth would be filled with brighter start from the Milky way. Our eyes would get used to that, and the start from other galaxies would just appear too dim to see.



Now on the dark side of the moon it would be a little different, but only that there is no light pollution like on Earth. Still, from the dark side of the Moon you could still only see stars from the Milky way.



Now in the void in your case, I think it is different. It is so dark and void, that even a single photon coming from a far away large star would be visible to our eyes that get used to the darkness.



Please see here:



Do all the individual stars that we can see in the night sky belong to Milky Way?






share|cite|improve this answer









$endgroup$



In fact you would see only individual stars. Like on Earth, you can only see individual stars, and no galaxies with the naked eye. Why? Because galaxies are too dim as a whole.



Now, if you would just float in empty space in the void you would be better off then on Earth. It is because here on Earth there is some light pollution.



But in the void, there is basically no light pollution, so you could see even single photons arriving from far away giant stars.



And yes, the human eye is able to detect even single photons.



By the way, all the stars that you can see with the naked eye from Earth are from the Milky Way. But again, that is too because of the light pollution and because our night sky even if there would be no light pollution here on Earth would be filled with brighter start from the Milky way. Our eyes would get used to that, and the start from other galaxies would just appear too dim to see.



Now on the dark side of the moon it would be a little different, but only that there is no light pollution like on Earth. Still, from the dark side of the Moon you could still only see stars from the Milky way.



Now in the void in your case, I think it is different. It is so dark and void, that even a single photon coming from a far away large star would be visible to our eyes that get used to the darkness.



Please see here:



Do all the individual stars that we can see in the night sky belong to Milky Way?







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answered 7 hours ago









Árpád SzendreiÁrpád Szendrei

4,3611624




4,3611624







  • 1




    $begingroup$
    You can see Andromeda with the naked eye, under optimal conditions. It's mag +3.44. Sagittarius Dwarf Spheroidal Galaxy and M33 should also be visible
    $endgroup$
    – CSM
    3 hours ago












  • 1




    $begingroup$
    You can see Andromeda with the naked eye, under optimal conditions. It's mag +3.44. Sagittarius Dwarf Spheroidal Galaxy and M33 should also be visible
    $endgroup$
    – CSM
    3 hours ago







1




1




$begingroup$
You can see Andromeda with the naked eye, under optimal conditions. It's mag +3.44. Sagittarius Dwarf Spheroidal Galaxy and M33 should also be visible
$endgroup$
– CSM
3 hours ago




$begingroup$
You can see Andromeda with the naked eye, under optimal conditions. It's mag +3.44. Sagittarius Dwarf Spheroidal Galaxy and M33 should also be visible
$endgroup$
– CSM
3 hours ago

















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