Evaluating number of iteration with a certain map with While The 2019 Stack Overflow Developer Survey Results Are InWhy should I avoid the For loop in Mathematica?Out of memory in a Do loopRepeating Calculations/Iterations without a specific functionWhile loop with changing variable , NDSolve and an IntegralUsing Map function with NDSolveHow do I repeat the number of times a nested for loop does an iteration?
Spanish for "widget"
Poison Arrows Piercing damage reduced to 0, do you still get poisoned?
Should I use my personal or workplace e-mail when registering to external websites for work purpose?
How can I create a character who can assume the widest possible range of creature sizes?
Falsification in Math vs Science
Time travel alters history but people keep saying nothing's changed
Which Sci-Fi work first showed weapon of galactic-scale mass destruction?
Can I write a for loop that iterates over both collections and arrays?
Did USCIS resume its biometric service for UK visa?
Feasability of miniature nuclear reactors for humanoid cyborgs
Why is Grand Jury testimony secret?
Are there any other methods to apply to solving simultaneous equations?
Why can Shazam do this?
What is the meaning of Triage in Cybersec world?
Can't find the latex code for the ⍎ (down tack jot) symbol
Fractional alignment
How long do I have to send payment?
Does a dangling wire really electrocute me if I'm standing in water?
Does it makes sense to buy a new cycle to learn riding?
Should I write numbers in words or as symbols in this case?
How to manage monthly salary
How are circuits which use complex ICs normally simulated?
Why could you hear an Amstrad CPC working?
Output the Arecibo Message
Evaluating number of iteration with a certain map with While
The 2019 Stack Overflow Developer Survey Results Are InWhy should I avoid the For loop in Mathematica?Out of memory in a Do loopRepeating Calculations/Iterations without a specific functionWhile loop with changing variable , NDSolve and an IntegralUsing Map function with NDSolveHow do I repeat the number of times a nested for loop does an iteration?
$begingroup$
Beeing used to programming in C-like languages I am struggling with iterations and loops with mathematica. I am trying not to use the For command, as already lots of people recommended.
I am trying to solve the following problem:
Given the map $z_i+1= z_i^2 +c$ with $z_i, c in mathbbC$ and $z_0 = 0$ evaluate the contours that represents given the parameter $c$ the number of iterations $i$ that I have to perform in order to have $|z_i|> 2$. Perform the computation with $-0.6 leq Re(z_i)leq -0.4 $ and $0.6 leq Im(z_i)leq 0.4$ and 100 points per axis.
Given the condition I though I could use a While Loop to perform the task
i=0; (*init counter*)
z[i]=0; (*init z[i]*)
g[c_]:= While[
Abs[z[i]]<= 2, (*condition*)
z[i+1]= z[i]^2 +c; (*process*)
i++; (*increment*)
]
Print[i]
g[0.2 + 0.2 I]
This computation with the input, say, $(-0.2 +0.2 i)$ (and with many others) takes all the memory of the machine I am using (Wolfram online). I don't understand whether I am just missing something or the amount of computation I can perform on the server just isn't enough (which seems really unlikely)
Furthermore I would like the function to return an integer (i - the number of iterations) but I really struggle with how to correctly use the synthax of Mathematica to do that.
Thanks in advance to everyone who is so keen to stop by and help :)
procedural-programming
New contributor
JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Beeing used to programming in C-like languages I am struggling with iterations and loops with mathematica. I am trying not to use the For command, as already lots of people recommended.
I am trying to solve the following problem:
Given the map $z_i+1= z_i^2 +c$ with $z_i, c in mathbbC$ and $z_0 = 0$ evaluate the contours that represents given the parameter $c$ the number of iterations $i$ that I have to perform in order to have $|z_i|> 2$. Perform the computation with $-0.6 leq Re(z_i)leq -0.4 $ and $0.6 leq Im(z_i)leq 0.4$ and 100 points per axis.
Given the condition I though I could use a While Loop to perform the task
i=0; (*init counter*)
z[i]=0; (*init z[i]*)
g[c_]:= While[
Abs[z[i]]<= 2, (*condition*)
z[i+1]= z[i]^2 +c; (*process*)
i++; (*increment*)
]
Print[i]
g[0.2 + 0.2 I]
This computation with the input, say, $(-0.2 +0.2 i)$ (and with many others) takes all the memory of the machine I am using (Wolfram online). I don't understand whether I am just missing something or the amount of computation I can perform on the server just isn't enough (which seems really unlikely)
Furthermore I would like the function to return an integer (i - the number of iterations) but I really struggle with how to correctly use the synthax of Mathematica to do that.
Thanks in advance to everyone who is so keen to stop by and help :)
procedural-programming
New contributor
JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Beeing used to programming in C-like languages I am struggling with iterations and loops with mathematica. I am trying not to use the For command, as already lots of people recommended.
I am trying to solve the following problem:
Given the map $z_i+1= z_i^2 +c$ with $z_i, c in mathbbC$ and $z_0 = 0$ evaluate the contours that represents given the parameter $c$ the number of iterations $i$ that I have to perform in order to have $|z_i|> 2$. Perform the computation with $-0.6 leq Re(z_i)leq -0.4 $ and $0.6 leq Im(z_i)leq 0.4$ and 100 points per axis.
Given the condition I though I could use a While Loop to perform the task
i=0; (*init counter*)
z[i]=0; (*init z[i]*)
g[c_]:= While[
Abs[z[i]]<= 2, (*condition*)
z[i+1]= z[i]^2 +c; (*process*)
i++; (*increment*)
]
Print[i]
g[0.2 + 0.2 I]
This computation with the input, say, $(-0.2 +0.2 i)$ (and with many others) takes all the memory of the machine I am using (Wolfram online). I don't understand whether I am just missing something or the amount of computation I can perform on the server just isn't enough (which seems really unlikely)
Furthermore I would like the function to return an integer (i - the number of iterations) but I really struggle with how to correctly use the synthax of Mathematica to do that.
Thanks in advance to everyone who is so keen to stop by and help :)
procedural-programming
New contributor
JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Beeing used to programming in C-like languages I am struggling with iterations and loops with mathematica. I am trying not to use the For command, as already lots of people recommended.
I am trying to solve the following problem:
Given the map $z_i+1= z_i^2 +c$ with $z_i, c in mathbbC$ and $z_0 = 0$ evaluate the contours that represents given the parameter $c$ the number of iterations $i$ that I have to perform in order to have $|z_i|> 2$. Perform the computation with $-0.6 leq Re(z_i)leq -0.4 $ and $0.6 leq Im(z_i)leq 0.4$ and 100 points per axis.
Given the condition I though I could use a While Loop to perform the task
i=0; (*init counter*)
z[i]=0; (*init z[i]*)
g[c_]:= While[
Abs[z[i]]<= 2, (*condition*)
z[i+1]= z[i]^2 +c; (*process*)
i++; (*increment*)
]
Print[i]
g[0.2 + 0.2 I]
This computation with the input, say, $(-0.2 +0.2 i)$ (and with many others) takes all the memory of the machine I am using (Wolfram online). I don't understand whether I am just missing something or the amount of computation I can perform on the server just isn't enough (which seems really unlikely)
Furthermore I would like the function to return an integer (i - the number of iterations) but I really struggle with how to correctly use the synthax of Mathematica to do that.
Thanks in advance to everyone who is so keen to stop by and help :)
procedural-programming
procedural-programming
New contributor
JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
JacquesLeenJacquesLeen
303
303
New contributor
JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
JacquesLeen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
The problem with your code is that for some values of c, Abs[z] will never become larger than 2. You need to cap the number of iterations.
For this type of iteration, the typical function to use is Nest and related functions.
countIter[c_] :=
Length@NestWhileList[
#^2 + c &,
0.0,
Abs[#] <= 2 &,
1,
100 (* limit number of iterations to 100 *)
]
result =
Table[
countIter[re + im I],
re, -0.6, -0.4, 0.2/100,
im, 0.4, 0.6, 0.2/100
];
ArrayPlot[result, ColorFunction -> "Rainbow"]

However, this type of problem is quite amenable to compilation with Compile. When using Compile, the usual advice does not apply: a procedural style is still the best. (This does not mean that For is good, I'd still argue against that. But there are many other procedural constructs such as Do and While).
countIterCompiled = Compile[c, _Complex,
Block[z = 0.0 + 0.0 I, i = 0,
While[i <= 100 && Abs[z] <= 2,
z = z^2 + c;
i++
];
i
]
]
Using countIterCompiled will be much faster than countIter.
$endgroup$
$begingroup$
thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
$endgroup$
– JacquesLeen
7 hours ago
$begingroup$
@JacquesLeen Maybe that was part of the exercise: will you discover it on your own? InsideCompile,ModuleandBlockare the same, I think. (Not outside of it.)
$endgroup$
– Szabolcs
6 hours ago
add a comment |
$begingroup$
For iterated function systems like this, Nest and relatives are the preferred tools. Just exploring your (rather famous) map:
f[z_, c_] := z^2 + c
Abs[NestList[f[#, 0.2 + 0.2 I] &, 0, 30]]
(* 0, 0.282843, 0.344093, 0.351367, 0.327239, 0.304778, 0.303605,
0.311545, 0.316158, 0.315818, 0.313773, 0.312729, 0.31295, 0.313482,
0.313697, 0.313611, 0.313477, 0.313435, 0.313464, 0.313497, 0.313504,
0.313495, 0.313487, 0.313486, 0.313489, 0.313491, 0.313491, 0.31349,
0.31349, 0.31349, 0.31349 *)
As you can see, it converges to a value inside your radius. That's why your function doesn't terminate.
$endgroup$
add a comment |
$begingroup$
You could also use MandelbrotSetPlot to create Szabolcs' graphic:
MandelbrotSetPlot[-0.6 + 0.4 I, -0.4 + 0.6 I, PlotLegends -> Automatic]

$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "387"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
JacquesLeen is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f194872%2fevaluating-number-of-iteration-with-a-certain-map-with-while%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The problem with your code is that for some values of c, Abs[z] will never become larger than 2. You need to cap the number of iterations.
For this type of iteration, the typical function to use is Nest and related functions.
countIter[c_] :=
Length@NestWhileList[
#^2 + c &,
0.0,
Abs[#] <= 2 &,
1,
100 (* limit number of iterations to 100 *)
]
result =
Table[
countIter[re + im I],
re, -0.6, -0.4, 0.2/100,
im, 0.4, 0.6, 0.2/100
];
ArrayPlot[result, ColorFunction -> "Rainbow"]

However, this type of problem is quite amenable to compilation with Compile. When using Compile, the usual advice does not apply: a procedural style is still the best. (This does not mean that For is good, I'd still argue against that. But there are many other procedural constructs such as Do and While).
countIterCompiled = Compile[c, _Complex,
Block[z = 0.0 + 0.0 I, i = 0,
While[i <= 100 && Abs[z] <= 2,
z = z^2 + c;
i++
];
i
]
]
Using countIterCompiled will be much faster than countIter.
$endgroup$
$begingroup$
thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
$endgroup$
– JacquesLeen
7 hours ago
$begingroup$
@JacquesLeen Maybe that was part of the exercise: will you discover it on your own? InsideCompile,ModuleandBlockare the same, I think. (Not outside of it.)
$endgroup$
– Szabolcs
6 hours ago
add a comment |
$begingroup$
The problem with your code is that for some values of c, Abs[z] will never become larger than 2. You need to cap the number of iterations.
For this type of iteration, the typical function to use is Nest and related functions.
countIter[c_] :=
Length@NestWhileList[
#^2 + c &,
0.0,
Abs[#] <= 2 &,
1,
100 (* limit number of iterations to 100 *)
]
result =
Table[
countIter[re + im I],
re, -0.6, -0.4, 0.2/100,
im, 0.4, 0.6, 0.2/100
];
ArrayPlot[result, ColorFunction -> "Rainbow"]

However, this type of problem is quite amenable to compilation with Compile. When using Compile, the usual advice does not apply: a procedural style is still the best. (This does not mean that For is good, I'd still argue against that. But there are many other procedural constructs such as Do and While).
countIterCompiled = Compile[c, _Complex,
Block[z = 0.0 + 0.0 I, i = 0,
While[i <= 100 && Abs[z] <= 2,
z = z^2 + c;
i++
];
i
]
]
Using countIterCompiled will be much faster than countIter.
$endgroup$
$begingroup$
thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
$endgroup$
– JacquesLeen
7 hours ago
$begingroup$
@JacquesLeen Maybe that was part of the exercise: will you discover it on your own? InsideCompile,ModuleandBlockare the same, I think. (Not outside of it.)
$endgroup$
– Szabolcs
6 hours ago
add a comment |
$begingroup$
The problem with your code is that for some values of c, Abs[z] will never become larger than 2. You need to cap the number of iterations.
For this type of iteration, the typical function to use is Nest and related functions.
countIter[c_] :=
Length@NestWhileList[
#^2 + c &,
0.0,
Abs[#] <= 2 &,
1,
100 (* limit number of iterations to 100 *)
]
result =
Table[
countIter[re + im I],
re, -0.6, -0.4, 0.2/100,
im, 0.4, 0.6, 0.2/100
];
ArrayPlot[result, ColorFunction -> "Rainbow"]

However, this type of problem is quite amenable to compilation with Compile. When using Compile, the usual advice does not apply: a procedural style is still the best. (This does not mean that For is good, I'd still argue against that. But there are many other procedural constructs such as Do and While).
countIterCompiled = Compile[c, _Complex,
Block[z = 0.0 + 0.0 I, i = 0,
While[i <= 100 && Abs[z] <= 2,
z = z^2 + c;
i++
];
i
]
]
Using countIterCompiled will be much faster than countIter.
$endgroup$
The problem with your code is that for some values of c, Abs[z] will never become larger than 2. You need to cap the number of iterations.
For this type of iteration, the typical function to use is Nest and related functions.
countIter[c_] :=
Length@NestWhileList[
#^2 + c &,
0.0,
Abs[#] <= 2 &,
1,
100 (* limit number of iterations to 100 *)
]
result =
Table[
countIter[re + im I],
re, -0.6, -0.4, 0.2/100,
im, 0.4, 0.6, 0.2/100
];
ArrayPlot[result, ColorFunction -> "Rainbow"]

However, this type of problem is quite amenable to compilation with Compile. When using Compile, the usual advice does not apply: a procedural style is still the best. (This does not mean that For is good, I'd still argue against that. But there are many other procedural constructs such as Do and While).
countIterCompiled = Compile[c, _Complex,
Block[z = 0.0 + 0.0 I, i = 0,
While[i <= 100 && Abs[z] <= 2,
z = z^2 + c;
i++
];
i
]
]
Using countIterCompiled will be much faster than countIter.
edited 8 hours ago
answered 8 hours ago
SzabolcsSzabolcs
163k14448945
163k14448945
$begingroup$
thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
$endgroup$
– JacquesLeen
7 hours ago
$begingroup$
@JacquesLeen Maybe that was part of the exercise: will you discover it on your own? InsideCompile,ModuleandBlockare the same, I think. (Not outside of it.)
$endgroup$
– Szabolcs
6 hours ago
add a comment |
$begingroup$
thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
$endgroup$
– JacquesLeen
7 hours ago
$begingroup$
@JacquesLeen Maybe that was part of the exercise: will you discover it on your own? InsideCompile,ModuleandBlockare the same, I think. (Not outside of it.)
$endgroup$
– Szabolcs
6 hours ago
$begingroup$
thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
$endgroup$
– JacquesLeen
7 hours ago
$begingroup$
thank u very much for the suggestion... I previously had a similar idea using Module instead of Block, and the problem was that the exercise did not specify that for many values the map was converging so I had to cap the number of iterations.
$endgroup$
– JacquesLeen
7 hours ago
$begingroup$
@JacquesLeen Maybe that was part of the exercise: will you discover it on your own? Inside
Compile, Module and Block are the same, I think. (Not outside of it.)$endgroup$
– Szabolcs
6 hours ago
$begingroup$
@JacquesLeen Maybe that was part of the exercise: will you discover it on your own? Inside
Compile, Module and Block are the same, I think. (Not outside of it.)$endgroup$
– Szabolcs
6 hours ago
add a comment |
$begingroup$
For iterated function systems like this, Nest and relatives are the preferred tools. Just exploring your (rather famous) map:
f[z_, c_] := z^2 + c
Abs[NestList[f[#, 0.2 + 0.2 I] &, 0, 30]]
(* 0, 0.282843, 0.344093, 0.351367, 0.327239, 0.304778, 0.303605,
0.311545, 0.316158, 0.315818, 0.313773, 0.312729, 0.31295, 0.313482,
0.313697, 0.313611, 0.313477, 0.313435, 0.313464, 0.313497, 0.313504,
0.313495, 0.313487, 0.313486, 0.313489, 0.313491, 0.313491, 0.31349,
0.31349, 0.31349, 0.31349 *)
As you can see, it converges to a value inside your radius. That's why your function doesn't terminate.
$endgroup$
add a comment |
$begingroup$
For iterated function systems like this, Nest and relatives are the preferred tools. Just exploring your (rather famous) map:
f[z_, c_] := z^2 + c
Abs[NestList[f[#, 0.2 + 0.2 I] &, 0, 30]]
(* 0, 0.282843, 0.344093, 0.351367, 0.327239, 0.304778, 0.303605,
0.311545, 0.316158, 0.315818, 0.313773, 0.312729, 0.31295, 0.313482,
0.313697, 0.313611, 0.313477, 0.313435, 0.313464, 0.313497, 0.313504,
0.313495, 0.313487, 0.313486, 0.313489, 0.313491, 0.313491, 0.31349,
0.31349, 0.31349, 0.31349 *)
As you can see, it converges to a value inside your radius. That's why your function doesn't terminate.
$endgroup$
add a comment |
$begingroup$
For iterated function systems like this, Nest and relatives are the preferred tools. Just exploring your (rather famous) map:
f[z_, c_] := z^2 + c
Abs[NestList[f[#, 0.2 + 0.2 I] &, 0, 30]]
(* 0, 0.282843, 0.344093, 0.351367, 0.327239, 0.304778, 0.303605,
0.311545, 0.316158, 0.315818, 0.313773, 0.312729, 0.31295, 0.313482,
0.313697, 0.313611, 0.313477, 0.313435, 0.313464, 0.313497, 0.313504,
0.313495, 0.313487, 0.313486, 0.313489, 0.313491, 0.313491, 0.31349,
0.31349, 0.31349, 0.31349 *)
As you can see, it converges to a value inside your radius. That's why your function doesn't terminate.
$endgroup$
For iterated function systems like this, Nest and relatives are the preferred tools. Just exploring your (rather famous) map:
f[z_, c_] := z^2 + c
Abs[NestList[f[#, 0.2 + 0.2 I] &, 0, 30]]
(* 0, 0.282843, 0.344093, 0.351367, 0.327239, 0.304778, 0.303605,
0.311545, 0.316158, 0.315818, 0.313773, 0.312729, 0.31295, 0.313482,
0.313697, 0.313611, 0.313477, 0.313435, 0.313464, 0.313497, 0.313504,
0.313495, 0.313487, 0.313486, 0.313489, 0.313491, 0.313491, 0.31349,
0.31349, 0.31349, 0.31349 *)
As you can see, it converges to a value inside your radius. That's why your function doesn't terminate.
answered 8 hours ago
John DotyJohn Doty
7,56811124
7,56811124
add a comment |
add a comment |
$begingroup$
You could also use MandelbrotSetPlot to create Szabolcs' graphic:
MandelbrotSetPlot[-0.6 + 0.4 I, -0.4 + 0.6 I, PlotLegends -> Automatic]

$endgroup$
add a comment |
$begingroup$
You could also use MandelbrotSetPlot to create Szabolcs' graphic:
MandelbrotSetPlot[-0.6 + 0.4 I, -0.4 + 0.6 I, PlotLegends -> Automatic]

$endgroup$
add a comment |
$begingroup$
You could also use MandelbrotSetPlot to create Szabolcs' graphic:
MandelbrotSetPlot[-0.6 + 0.4 I, -0.4 + 0.6 I, PlotLegends -> Automatic]

$endgroup$
You could also use MandelbrotSetPlot to create Szabolcs' graphic:
MandelbrotSetPlot[-0.6 + 0.4 I, -0.4 + 0.6 I, PlotLegends -> Automatic]

answered 6 hours ago
Carl WollCarl Woll
73.2k397191
73.2k397191
add a comment |
add a comment |
JacquesLeen is a new contributor. Be nice, and check out our Code of Conduct.
JacquesLeen is a new contributor. Be nice, and check out our Code of Conduct.
JacquesLeen is a new contributor. Be nice, and check out our Code of Conduct.
JacquesLeen is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f194872%2fevaluating-number-of-iteration-with-a-certain-map-with-while%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown